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Creating json object from POJO object in restful web service
You can use GSon to convert json object to java object Link to refer example. Gson gson = new Gson(); //to get json object use toJson String json = gson.toJson(obj); //to get java object use fromJson MyClass obj = gson.fromJson(jsonObj, MyClass.class); or jackson is also pretty fast and easy to use

Categories : Java

While Sending Html Mails from my web application Recieved Mails contains Symbols like &ldquo,&rdquo, ‘
Check with another constructor for htmlView: ContentType mimeType = new System.Net.Mime.ContentType("text/html"); var htmlView = AlternateView.CreateAlternateViewFromString(bodyMessage, mimeType);

Categories : Asp Net Mvc

how to make json object from an element in json object with unique values in underscore js
var col = [ { "MerchantName": "Fashion and You", "BrandList": " Nike, Fila", "MerchantImage": "Fashion-You-medium.jpeg" }, { "MerchantName": "Fashion and You", "BrandList": " Levis, Fasttrack, Fila", "MerchantImage": "Fashion-You-medium.jpeg" }, { "MerchantName": "ebay", "BrandList": "Nokia,HTC,Samsung", "MerchantImage": "ebay.jpeg" }, { "MerchantName": "amazon", "BrandList": "Apple,Dell,Samsung", "MerchantImage": "amazon.jpeg" }, { "MerchantName": "amazon", "BrandList": " pepe jeans, peter england, red tape", "MerchantImage, Fila": "amazon.jpeg" } ]; var brands = []; //get unique brands _.each(col, function(i){ brands = _.union

Categories : Javascript

Create a empty JSON object from an existing JSON object array
You can use an object literal to store whatever you want. It is just a bag of properties (i.e. name) and values. e.g. var order = {}; Then an array literal could be used to hold the orders. e.g var orders = []; orders.push(order); But it would be just as easy to use another object literal with the id as a property. But it seems like you want some sort of validation. Perhaps something to manage the order data and handle the validation, etc. Like so: orderManager.dataStore = { _data: {}, //_redundantData = []; //could easily store in an array if id isn't unique get: function (id) { return this._data[id]; }, getAll: function () { return this._data; }, set: function (id, order) { validateOrder(order); this._data[id] = order; }, clear: function (id)

Categories : Javascript

Order JSON object alphabetical and return to JSON object
write a compare function function compare(a,b) { if (a.name < b.name) return -1; if (a.name > b.name) return 1; return 0; } then sort your data var cities = {}; $.getJSON('http://mypage.com/json/cities.php', function(data){ data.sort(compare); $.each(data, function (k, vali) { cities[vali.cid] = vali.name; }); });

Categories : Jquery

JSON.NET: Serialize json string property into json object
You need a converter to do that, here is an example: public class RawJsonConverter : JsonConverter { public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer) { writer.WriteRawValue(value.ToString()); } public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer) { throw new NotImplementedException(); } public override bool CanConvert(Type objectType) { return typeof(string).IsAssignableFrom(objectType); } public override bool CanRead { get { return false; } } } Then decorate your class with it: public class Foo { public int Id; [JsonConverter(typeof(RawJsonConverter))] public string RawData; } Then, when you use:

Categories : C#

@JsonProperty Json object inside Json object
A helpful reference for using @JsonProperty annotations in a constructor is provided by StaxMan. A simple example shown below: public class Address { private String address; private String city; private String state; private String zip; // Constructors, getters/setters } public class Location { private boolean needsRecoding; private Double longitude; private Double latitude; private Address humanAddress; public Location() { super(); } @JsonCreator public Location( @JsonProperty("needs_recoding") boolean needsRecoding, @JsonProperty("longitude") Double longitude, @JsonProperty("latitude") Double latitude, @JsonProperty("human_address") Address humanAddress) { super(); this.needs

Categories : Java

AngularJS: textarea bind to JSON object shows "object-object"
You can do that in two steps : Create a filter that'll stringify JSON (http://docs.angularjs.org/guide/dev_guide.templates.filters.creating_filters) $scope.watch the field to save it when it changes (example http://jsfiddle.net/ceJ4w/)

Categories : Angularjs

Why is no constructor needed of the object, deserialized from a json string, using ServiceStack Json Serializer
Default (no parameters) constructor is created by the compiler if no constructors are specified. The compiler does that when and only when NO constructors exist. If you create ANY constructor in your class this compiler behaviour will no longer apply. (Try creating a constructor with at least one parameter to see what will happen) Deserialization will involve two steps - create empty object using default (no parameters) constructor and than set all values. If you class does NOT have default (no parameters) constructor - either created by yourself explicitly or by the compiler - deserialization will fail. Deserialization never uses parametrised constructors as it is impossible for it to guess the correct constructor to use. Example: deserialization can not distinguish between Constructor

Categories : C#

Rendering json Object with express and jade - Can't access json fields
The output of your DB query returns the result as an array, so you need to send as data[0] to the product template, so that you can access directly the values else you need to access as result[0].name etc. /*Route to Product Views*/ app.get('/product/:id', function(req, res){ Product.find({_id: req.params.id}, function (error, data) { if(error){ console.log(error); } else { console.log("DATA :" + data[0]); //correct json object res.render('product',{ title: 'Product Template', result: data[0] } ); } }); }) Jade Template: !!! 5 html

Categories : Json

json request failed to pass json object to php var_dump is empty
Replace ; with , from this line, type: {type: tipo, subtype: sottotipo}; Should be, type: {type: tipo, subtype: sottotipo}, There is an error SyntaxError: missing } after property list in your script, and always use tools like mozilla's firebug addon, when you are processing with ajax requests. You can see the above error in firebug's console panel.

Categories : PHP

when we serialize serializable object using JSON.Net, JSON string is different from DatacontractJSON serializer
Unless you are always communicating from WCF to WCF, your best bet is probably going to be to use the Newtonsoft serializer. Unfortunately, the MS serializer seems to follow some Microsoft-specific standards that do not match the standards that many web apps expect. Newtonsoft's serializer seems to be more standard, and even MS uses it for WebAPI, and in the Web API http client (nuget will pull it down for you). Here's another difference that you will find -- try serializing a DateTime type. You will find that the DataContract serialzer serializes the value in a different format that is not compatible with other JSON (you will notice some slashes in it). My understanding is that that alternate format was used by some of the AJAX WebForm controls, but it's specific to Microsoft Webforms

Categories : C#

How to directly write to a JSON object (ObjectNode) from ObjectMapper in Jackson JSON?
You need to make use of ObjectMapper#valueToTree() instead. This will construct equivalent JSON Tree representation. Functionally same as if serializing value into JSON and parsing JSON as tree, but more efficient. You don't need to write the User object out to a JSON file, if that's not required. public class MyClass { private ObjectNode jsonObj; public ObjectNode getJson() { ObjectMapper mapper = new ObjectMapper(); // some code to generate the Object user... JsonNode jsonNode = mapper.valueToTree(user); if (jsonNode.isObject()) { jsonObj = (ObjectNode) jsonNode; return jsonObj; } return null; } }

Categories : Java

In jquery each Loop from json object How (make loop find a value from object and compare to another object value to not repeat a print)?
Try var songs = {}; $.each(data, function(key,val) { if(val.Artist != ""){ var key = val.Artist + '@' + val.Album; if(!songs[key]){ output += '<li><a class="songname" href="#" data-src="'+ val.Location +'">' + val.Artist + '</a></li>'; songs[key] = true ; }//End of PreSong != Song }//End of val.Artist });//End of Each output += '</ol>'; $("#wrapper").append(output); Demo: Fiddle You can change the key to find the unique combination. Ex: if you want a unique combination of Artist, Album and Song then use var key = val.Artist + '@' + val.Album + val.Song;

Categories : Javascript

How to parse json array without json object title in android?
This is a JSONArray and not a JSONObject - to make a JSONObject from it, use JSONObject jsonObject = jsonArray.getJSONObject(0); this gets the first JSONObject from this JSONArray. If you have multiple JSONObjects, use this: JSONObject jsonObject; for(int n = 0; n < jsonArray.length(); n++) { jsonObject = jsonArray.getJSONObject(n); } To get the values: jsonObject.getString("name");

Categories : Android

stringified json vs json object memory usage in mongodb
You can check the size of document with Object.bsonsize() in the mongoshell For example: > Object.bsonsize({}) 5 > Object.bsonsize({a:''}) 13 > Object.bsonsize({a:'',b:''}) 21 > Object.bsonsize({a:'',b:'',c:''}) 29 > Object.bsonsize({a:{a:'',b:'',c:''}}) 37 > Object.bsonsize({a:{a:'',b:''}}) 29 > Object.bsonsize({a:{a:''}}) 21 > Object.bsonsize({a:"{a:'',b:'',c:''}"}) 29 > Object.bsonsize({a:"{a:'',b:''}"}) 24 > Object.bsonsize({a:"{a:''}"}) 19 > Object.bsonsize({a:""}) 13 > Object.bsonsize({ab:""}) 14 > Object.bsonsize({abc:""}) 15 It looks like for me that empty doc is 5 byte one empty string is 7 byte plus each character in the name is 1 byte and each in the content is 1 byte.

Categories : Json

Why does this simple JSON object throw an error with JSON.parse?
JSON.parse expects a string. The value of t is a javascript object, so it doesn't need to be parsed. If you had: var t = "{"message":"ok, Heru we go!"}"; then JSON.parse would be what you were after.

Categories : Javascript

how to load datagrid of easyui with json data on click of a button 'search' and how to pass parameter as json object>?
try like this, function searchUserResult(){ $.ajax({ type: "POST", url: 'somurl', dataType: 'json', data:$('#searchUser').serialize(), }).done(function( responseJson ) { $('#search_gridresult').datagrid('loadData', responseJson ); }); }

Categories : Spring

Android Iterating JSON Array containing JSON Object
You are using the same Cast object for every entry. On each iteration you just changed the same object instead creating a new one. This code should fix it: JSONArray jCastArr = jObj.getJSONArray("abridged_cast"); ArrayList<Cast> castList= new ArrayList<Cast>(); for (int i=0; i < jCastArr.length(); i++) { Cast person = new Cast(); // create a new object here JSONObject jpersonObj = jCastArr.getJSONObject(i); person.castId = (String) jpersonObj.getString("id"); person.castFullName = (String) jpersonObj.getString("name"); castList.add(person); } details.castList = castList;

Categories : Java

Why Won't Any C# JSON Class Generators Process this JSON Object?
things inside of arrays dont themselves have names so just change "entities": [ "entity": { "type": "DETECTED_TYPE", to "entities": [ { "type": "DETECTED_TYPE",

Categories : C#

Android- create JSON Array and JSON Object
JSONObject obj = new JSONObject(); try { obj.put("id", "3"); obj.put("name", "NAME OF STUDENT"); obj.put("year", "3rd"); obj.put("curriculum", "Arts"); obj.put("birthday", "5/5/1993"); } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } JSONArray js=new JSONArray(obj.toString()); JSONObject obj2 = new JSONObject(); obj2.put("student", js.toString());

Categories : Android

c# parsing json: error reading json object
That JSON is a list not a dictionary. So what you need to do is this: string he_ident = (string)(((ArrayList)o2)[0])["he_ident"]; (Or simply loop through the list) The JSON data: {"le_ident":"06L"} Should work with the code you have there.

Categories : C#

Can use this as a json object? Custom string to json parser
No, that's not valid JSON. [...] encloses an array, which must be a comma-separated list of elements. You have key:value pairs in your brackets, and they're separated by semicolons. Is there a reason you're not using JSON.stringify()?

Categories : Javascript

json inside a json object not handling properly
Your third line currently has a syntax error because a : is expected where the = is, and also JavaScript is case sensitive so you need a capital J in Json1 to match the variable on the first line (or change that variable to a lowercase j): var json2 = {"ID":12345, data : Json1 }; If you did that you'd find that json2.data.name returned "OMAR". Also, the data variable and data as a property of the second object are not the same thing. Also, terminology nitpick: there's no such thing as a JSON object. For more details about working with JavaScript objects, MDN has an article titled, conveniently, "Working with objects".

Categories : Javascript

Error adding a json object in a json localstorage
You are trying to call push on the shops object not on the c array, you could do: var oldCli = JSON.parse(localStorage.getItem('shops')).c || [];

Categories : Javascript

ClientRequest, how to serialize POJO's to json data correctly? could not find writer for content-type application/json type:
Problem solved, unfortunately I haven't included all necessary 3rd party libraries to the projects build path. Finally I added the following jars: jackson-core-asl-1.6.3.jar jackson-jaxrs-1.6.3.jar jackson-mapper-asl-1.6.3.jar jackson-xc-1.6.3.jar resteasy-jackson-provider-2.2.1.GA.jar This example brings the strength of Maven to the front. With Maven there is only one entry necessary to fulfill these dependencies. <dependency> <groupId>org.jboss.resteasy</groupId> <artifactId>resteasy-jackson-provider</artifactId> <version>2.2.1.GA</version> </dependency>

Categories : Java

Getting [object Object] error when call JQuery Ajax function for Json data
The reason you are seeing that is that data.d is an object representing the returned JSON text response. When you pass in an object into alert, it displays [object Object]. Whatever you are looking for will be a property of data.d. I would put a breakpoint on that line and see what properties are available. It'll be something like data.d.myProperty which will contain the actual string / HTML you are trying to work with.

Categories : Asp Net

How to iterate a multidimensional json_decoded object in Perl to create a new json object?
Well, you aren't really going wrong; it is just the JSON format that is being as stupid as possible. The JSON is a hash of keys (which are sorted, numeric strings) which map to another level of hashes, which have the keys name and value: { "0": {"name": "someKey", "value": "someValue"}, "1": {"name": "anotherKey", "value": "anotherValue"} } (This data should probably be encoded as [{"someKey": "someValue"}, {"anotherKey": "anotherValue"}].) So what we'll do is to loop through the numerically sorted keys for the outer hash: for my $index (sort { $a <=> $b } keys %records) { ... } Inside that loop, we do not loop through the keys/values of the hash values. Instead, we just pick the values of the keys name and value: my $record_value = $records{$index}; my ($key, $value)

Categories : PHP

Ajax/jQuery/Json pass variable but I get [object Object] error
[object Object] means that $a, $b and $c are objects. To print out an object in javascript you should use data[index].variable where variable is the property of the object. Try to console.log(data) to see what you get: you should see 3 objects. Expand them, and read the variables inside of them. Also, since you're array is made of 3 elements, data[3] should not exists. You should post more PHP code.

Categories : PHP

asp.net web api - action filter - cannot access posted json object from request object
As far as I understand your problem, you want to log requests in case there is a binding error. A binding error is somewhat exception so that you may handle exceptions of your controller or actions. To do this, you need to useExceptionFilterAttribute . The example below : public class ExceptionHandlingAttribute : ExceptionFilterAttribute { public override void OnException(HttpActionExecutedContext actionExecutedContext) { string content = actionExecutedContext.Request.Content.ReadAsStringAsync().Result; ///LOGGING ACTIONS base.OnException(actionExecutedContext); } }

Categories : Asp Net Web Api

Android:Fetch json object set in User Agent object
I am not sure but it may be help to you. Try this one: JSONObject jObject; public JSONObject getJSONFromUrl(String url) { try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); is = httpEntity.getContent(); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } try { BufferedReader reader = new BufferedReader(new InputS

Categories : Android

Nested Object Deserialization of JSON results in an empty object
SubObjA in your example is a single object but in your class it is a collection, so JSON should look like [{"ObjA":"FOO", "SubObjA":[{ "A":0, "B":true, "C":2, "D":0.2 }], "ObjB":false, "ObjC":295, }] Note brackets around SubObjA.

Categories : C#

how to loop through Json result object inside object array
I'd suggest that if your data is consistent, then you're better off working directly with the format and not looping through everything to find keys and values. I created a Fiddle using your code (skipping the AJAX part.) and for contrast another Fiddle with the following code: var success = function (data) { var product, i, len, $output = $('.resultJson'); for (i = 0, len = data.length; i < len; i++) { product = data[i]; console.log('Object: ' + i); var details = product.ProductDetails; var MSRP = product.ProductDetails.MSRP; var price = product.ProductDetails.Price; console.log(details); console.log(MSRP); console.log(price); $output.append("<br />"); $output.append("ProductId: " + product

Categories : Javascript

Sending many json objects with one object json
On the Django REST page, it says: Note that nested relationships are currently read-only. "Read Only" would make posting a little difficult ;)

Categories : Django

Decoding JSON-like object using the json module
Simple fix would be to use ast.literal_eval, >>> data = ''' ... { ... "nine": 9, ... "ten": 0xA, ... "eleven": 11 ... } ... ''' >>> import ast >>> ast.literal_eval(data) {'eleven': 11, 'nine': 9, 'ten': 10}

Categories : Python

Modifying a JSON object with lift-json
This is ugly as it uses a mutable variable and it also uses json4s (which uses lift-json under the hood), but it works: import org.json4s.JsonAST._ import org.json4s.native.JsonMethods._ import org.json4s.JsonDSL._ object JsonTesting { def main(args: Array[String]) { val john = ("id" -> 1) ~ ("name" -> "Foo") ~ ("nested" -> ("id" -> 2) ~ ("name" -> "Bar")) var changed = false val john2 = john transformField { case JField("name", _) if !changed => changed = true JField("name", "foo") } } } I could not find a more clean way to tell it to either only traverse one level of depth or to be aware of depth for each node checked so I would only make the switch on the first level of de

Categories : Scala

Json object contain json array parsing
What exactly do you want to parse? If what you want is to get access to the data inside test1, for example, you need to retrieve test[1] then get the data out of there. If you are wondering why are you seeing the name of the object in the list, my guess is that you have a toString where you are only displaying the name of the object, in the class that you are adding to that list. Another thing to note, that json that you showed to us in the output, is not valid json. Or rather, it has got 2 fields with the same name, which is not recommended as an object can only have 1 field with the same name. Can you post all the code that you are using for creating and parsing the json? Also, have you considered using GSON? A very simple and powerful JSON library from Google.

Categories : Java

Deserializing JSON Object Array with Json.net
You can create a new model to Deserialize your Json CustomerJson: public class CustomerJson { [JsonProperty("customer")] public Customer Customer { get; set; } } public class Customer { [JsonProperty("first_name")] public string Firstname { get; set; } [JsonProperty("last_name")] public string Lastname { get; set; } ... } And you can deserialize your json easily : JsonConvert.DeserializeObject<List<CustomerJson>>(json); Hope it helps ! Documentation: Serializing and Deserializing JSON

Categories : C#

json returns [object Object] instead of actual data
An object can contain actual data, what is the problem? I suggest you take a look at the network calls from your browser using the developer console or Firebug to see what object is received. Then jQuery parses the string into an object so you can use the data.

Categories : Json

Turning my php array into [object Object] json/JavaScript
You're alerting a string, so it seems that jQuery is not recognizing your response as JSON, and it is not being parsed. Try this: $.ajax({ url : "php/resource.php", data : { node_id: node_id }, dataType : "json" }).done(function(data) { alert(data); return callback(null, data); }).fail(function() { return callback("AJAX error"); });

Categories : PHP



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