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How to display single record in the database if duplicate records are available using hibernate
If the PK is [sid, subject], then the ID of the Student entity should be a class containing these two fields, and you would use it the same way as you would do with a non-composite primary key: StudentKey key = new StudentKey(someSid, someSubject); Student student = (Student) session.get(Student.class, key); If this is not clear enough, then edit your question and show how you defined the entity mapped to this table.

Categories : Hibernate

How to display a list of database records (retrieved via Hibernate) to a JSP page in Struts 2?
May be you understand, but don't know why you didn't any attempt to resolve it. If you want to display data, first you should put it in the database. Check the data is available, connecting to it via the client application. There's many ways to connect to the database, including a JDBC client application supplied with the IDE. It also takes a connection properties right from your hibernate.cfg.xml and has capability to test the connection. Also, make sure the credential used to connect to the database has DML/DDL access privileges to the schema which should be probably created manually. This file is for hibernate configuration, that you should take attention on it, to be valid due to a correct DTD corresponding to the version of hibernate. Then, you are using annotation based mapping, a

Categories : Java

Two Spring MVC projects on one database (hibernate)
Yes you can, but not a reference to the hibernate project itself, You could easily build some Jar file inside your Hibernate project using Ant Script, this Jar file would encapsulate all your common classes an resources Then you could add this Jar to Internal and Admin Project Build paths The problem of this solution is that you will need remember to build the common Jar file on every change on your common classes Check this tutorial to know how building a Jar using Ant, you could use Maven too There is another approach using SVN externals or any mapped feature on your Version control system, by making the common project as an external repository and check it out in both projects (internal and admin). However using this approach will have the following problems: The configuration of

Categories : Hibernate

how to retrieve the record from database by using spring 2.0 with hibernate springMVC
It would depend on what property is giving you the NullPointerException (NPE). If you're using Spring MVC then it's likely that your DAO or Manager is giving you the NPE because it hasn't been initialized before you attempt to use it. Could you share your the code in your Controller where you declare either your DAO or Manager? Okay, looking at your code I would imagine you're receiving your NPE at this line: ArrayList list = (ArrayList)edao.findAll(); I would begin looking at the EmpJB class and ensure you have all of the dependent properties initialized.

Categories : Java

Need some kind of enum which is extensible by database (using Spring 3.2, Hibernate 4.2)
The first idea was to put those extra groups in the database when it's created and simply rely on the fact that they are in there, but I think that's bad practice. (because the system will crash if they get deleted or renamed) Your application will also crash if the database is not there at all, or if tables and columns used by your application are renamed for example. To me, the presence of these rows, with the correct IDs or names, is simply a prerequisite, just like the presence of tables and columns of the right type. Just make sure to document the fact that these rows must be present. Make sure that the application doesn't allow renaming or deleting them and, if you're really concerned about someone deleting these rows, check that all the hard-coded IDs/names you're using in th

Categories : Database

Expecting database exceptions with JUnit, Spring and HIbernate
Use @Test(expected=DataIntegrityViolationException.class) You must use the top-most exception. In your expected you listed the cause not the top-most exception. OK, Wait a second. If you put the expected on the test, you should not have a try/catch in the test. Or if you do, you should re-throw the exception.

Categories : Java

Hibernate spring unit testing with mySQL in memory database
Spring supports only H2, HSQL and Derby as in-memory database implementations. If you are really interested in testing with MySql itself, you should be able to run your unit tests against an external MySql database server, running either locally or on a different machine.

Categories : Mysql

Insert one line in database for multiple records formats using Spring Batch
You can look at this official forum thread or spring-batch example called Multiline Order. The point is have a custom ItemReader<YouBeanClass> delegate to ItemReader<FieldSet> who is responsible to create the right FieldSet based upon record header (H,D,T) have a PatternMatchingCompositeLineTokenizer to create the right FieldSet (attached to ItemReader<FieldSet> at point 1) In ItemReader<YouBeanClass> rewrite ItemReader.read() and build up a YourBeanClass from every H(D+)T records range After that you have a fully constructed YourBeanClass object.

Categories : Java

spring integration: Custom header enricher that records header values to database
This is fairly advanced. You will need a schema, a namespace handler that associates the parser with the namespace element and the parser itself. It might be simpler to use a <transformer/> and simply reference your bean that adds the headers (and stores them). If you want to learn how to write your own namespace; a good place to get started is the STS project templates which will create all of the boiler plate for you. EDIT: In response to your updates... Since it's still a bean definition, and not yet a bean, you can simply change the beanClassName property... BeanDefinition beanDefinition = new StandardHeaderEnricherParser().parse(element, parserContext); beanDefinition.setBeanClassName(Foo.class.getName());

Categories : Spring

Spring + Hibernate: No Hibernate Session bound to thread
If you have defined a TransactionManager in your spring context you have to specify @Transactional somewhere in the stack. Otherwise you will get the exception you encountered because you are trying to run a query outside of a transaction. There are workarounds to this such specifying current_session_context_class in your hibernate configuration to thread or <property name="current_session_context_class">org.hibernate.context.ThreadLocalSessionContext</property> but it's not production safe.. The possible values for current_session_context_class are jta, thread and managed. Further to that, jta and thread are supported by hibernate out of box. thread context is used in most stand alone hibernate apps or those based on light weight frameworks like Spring and jta is used in

Categories : Java

spring mvc 3 with hibernate (and hibernate.hbm2ddl.auto)
You seem to be missing the spring-tx jar from your classpath given this line 15:49:04,031 ERROR [org.springframework.beans.factory.support.DefaultListableBeanFactory] (MSC service thread 1-3) Destroy method on bean with name '(inner bean)' threw an exception: java.lang.NoClassDefFoundError: org/springframework/transaction/support/TransactionSynchronization You can get it here. You actually seem to be missing much more than that. java.lang.ClassNotFoundException: org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean Get all the spring jars from the here.

Categories : Java

Spring, JPA, Hibernate, Tomcat: Unable to find persistence unit when loading Spring application context
As far I understood from my recent expirience of setting up 2 EntityManagerFactory in the same application - @PersistenceUnit(unitName="myPU") just doesn't work at all. I would suggest to inject EntityManager, not EntityManagerFactory. This is clear since you always know which EMF is used. Same for specifying right TransactionManager. Updated code of the service class: @Service public class CompetenceAreaManager { @PersistenceContext(unitName = "emf1") private EntityManager em; @SuppressWarnings("unchecked") @Transactional(transactionManager="transactionManager1", readOnly=true) public List<CompetenceArea> getCompetenceAreas() { List<CompetenceArea> competenceAreaList = null; Query q = em.createNamedQuery(CompetenceArea.FIND_ALL);

Categories : Java

Spring MVC bind hibernate session factory other thread in spring web mvc
You need to either go through AOP decorated transactional bean (e.g. your service layer annotated with @Transactional), or you need to use TransactionTemplate: new TransactionTemplate(txManager).execute(new TransactionCallback<Void>() { @Override public Void doInTransaction(TransactionStatus status) { // Your Hibenrate stuff return null; } });

Categories : Spring

How can I search for two terms in Hibernate Search and get them both in result?
Maybe this is what you want,Assuming you have an String array of terms to be searched. BooleanQuery finalLuceneQuery=new BooleanQuery(); for(String term:terms) { TermQuery query = new TermQuery(new Term("your search field", term)); finalLuceneQuery.add(query,BooleanClause.Occur.MUST); } FullTextQuery fullTextQuery = fullTextSession.createFullTextQuery(finalLuceneQuery, <your class>.class); Cheers.

Categories : Hibernate

Cannot update records using Hibernate
You should: Start a session and a transaction Load your two records Update the values of these records Commit the transaction saveOrUpdate doesn't have to be used in that scenario because you're only updating existing records.

Categories : Java

Transferring records in hibernate
I know of no built-in Hibernate command for cut-n-paste. Hibernate just gives HQL for that matter. You should: Retrieve the entities using Hibernate; Transform them to the desired other entity type. Manually, yes. Save the new entities via session.save. Delete the old entities via session.delete. Notes If you're doing this for lots of records, this naive algorithm isn't performant. For performant bulk save / delete operations your choice would be StatelessSession First save and only afterwards delete, so that if your application crashes in between no data is lost. Don't forget to make it transactional if it is forbidden that these entities will show up in both tables.

Categories : Hibernate

Searching for a variable number of terms in a MySQL database using Laravel Fluent
Something like this might work: $matches = LibraryCase::where('id','>',0); $user_query = "sonic hedgehog"; foreach(explode(' ', $user_query) as $word) { $matches = $matches->or_where('diagnosis', 'LIKE', $word); $matches = $matches->or_where('description', 'LIKE', $word); } return $matches->paginate(10);

Categories : Mysql

What is the correct procedure for including a Maven-Spring-Roo-Hibernate jar in a Non-Maven-Non-Spring project?
Because the application context don't aware about the model. You are creating the model out of the appcontext. if you get the Model using getBean("MyUser"); some thing like that will work. else auto-wire the model and use that model for your crud operations. You can see the following code in MyUser - @PersistenceContext rotected transient EntityManager entityManager; Then only the entityManager object will initialized inside the the Myuser. @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = { "classpath*:/META-INF/spring/applicationContext.xml"}) public class SomeTest extends AbstractJUnit4SpringContextTests { @Autowired MyUser myUser; // use this object for ur crud operations @Test public void someTest() throws Exce

Categories : Java

Hibernate : how to get records from composite key using Criteria Query
Issue solved. I tried below which worked Criteria empAttendanceCr=session2.createCriteria(EmployeeSignin.class); //EmployeeSigninId empId=new EmployeeSigninId(user.getEmpId().toString()); Criterion attdDateCondition = Restrictions.conjunction() .add(Restrictions.eq("id.empId",user.getEmpId().toString())) .add(Restrictions.le("id.signinDate", lastDate)) .add(Restrictions.ge("id.signinDate", startDate));

Categories : Java

My hibernate code to retrieve records does not work
Try this if you need to set list NULL for empty result. List<Timing> timing = cre.list(); if (timing!=null && timing.isEmpty()) timing = null; And I believe it should be 0 instead of 1 in the line ...size() > 1 for your current code and checking for null.

Categories : Java

Saving multiple records on the same instance in Hibernate
What's happening is after you call session.save(anObj), the entity object became pesistent -- meaning any subsequent modification to its state will be detected by Hibernate and synchronized to database (sometime down the track). You can probably save multiple row without re-creating new object by detaching, updating and merging for every new database row, but I'd say this defeats the purpose of using ORM (Object Relational Mapping) in the first place. I believe hibernate was designed so Java programmer can map a domain object stored in database row as one java object (and vice versa)

Categories : Hibernate

How to avoid duplicate records when update in DB using hibernate
Defining a primary key, or at least a unique constraint, on the table, is the surest way to avoid duplicates. Then your code will throw some useful errors for you to handle transactions properly.

Categories : Java

Load a few records from database given an array of integers and keep the order as the array without loading all records to memory
You could turn it around. Make the selection of ids from your array Fetch only the records that you actually need Project the fetched records back on your id selection/order. Like this: Given I have a list of 100 album id's. Take 15 of those id's, let's say, descending order. var ids = Enumerable.Range(1, 100); var subsetOfIds = ids.OrderByDescending(i => i).Take(15); var dbresults = Albums.Where(a => subsetOfIds.Contains(a.AlbumId)).ToArray(); var results = subsetOfIds.Select(id => new { IdFromArray = id, record = dbresults.First(album => album.AlbumId == id) }).ToArray(); Now I only fetched those 15 records from the database and still have them back in the order that I want them to be.

Categories : C#

database space quotas with hibernate and postgresql, limit database megabytes used per user
There's no way this can be answered by looking at the file system, SQL queries must be written. The size in bytes of a bytea field can be obtained with the octet_length function. If hibernate uses large objects (references through the oid type) for the binary contents, you need to use a self-defined lo_size(oid) function as suggested in Obtaining the size of lobject in PostgreSQL. Having the right functions, you can then aggregate the sizes to compute the per-student usage for the various content types. If in addition you need to enforce the quotas on insertion, they should be computed in functions that are TRIGGERed BEFORE the event to be able to cancel the operation when an over-quota limit would be reached.

Categories : Hibernate

I want to get updated records from web sql server database into local database table through Store Procedure
Check linked server. http://www.jensbits.com/2010/11/10/create-linked-server-sql-server-2008/ after link the web server in to your local server, can access data easily.

Categories : Sql Server

Grails/Hibernate - Criteria to fetch a master by two child records
I'm afraid (not 100% sure) Criteria syntax can only query a single child record, so you'll have to use HQL like: from Author as a where exists ( from Book as b1 where b1.author = a and b1.serialNumber = 1 and b1.name = 'ABC' ) and exists ( from Book as b2 where b2.author = a and b2.serialNumber = 2 and b1.name = 'XYZ' ) Maybe you can replace from Book as b2 where b2.author = a with from a.books as b2 - I cannot test it now.

Categories : Hibernate

Hibernate OneToMany mappedby inserts duplicate records when saved
Try replacing the cascade clause for this @Cascade (value={CascadeType.SAVE_UPDATE,CascadeType.DELETE_ORPHAN}) Take a look at my blog post on mapping one-to-many http://arecordon.blogspot.com.ar/2013/05/hibernate-mapping-associations-one-to_20.html

Categories : Java

ASP Retrieving database records, and then retrieving more records from another table using the first records
I am not sure I am understanding but you might try something like this select id,* from mytable where id in (select id from mytable2 where salesdate = date and printed= 0) update mytable2 printed = 1 where id = " & myid

Categories : SQL

Multiple database records in a table vs database queries? What is the best for performance?
Before analyzing scenarios given in your question I would like to request you to clear one point which is a bit confusing in your question. The statements given below are confusing. 1) Also project has many posts, when a post is created a notification is created for each project user. 2) Let's say if Project A has 100 users, we'll have 100 notifications in database, this will load the database with a lot of duplicates. Statement no. 1 describes that when a post is created; a notification is sent for each user. So suppose there are 100 users and 100 posts then the table which has notifications data will have 10000 rows (100*100). Statement no. 2 describes that if there are 100 users then there would be 100 notifications in the database that means the notification table will have 100 row

Categories : Ruby On Rails

Why should we use spring's hibernate?
Thanks to @Wand Maker. I have found the answer I need in the link provided: static.springsource.org/spring/docs/3.0.x/reference/orm.html at the 13.3 Hibernate portion which explains the different ways to implement DAO using spring hibernate.

Categories : Spring

in memory db hibernate spring
Following this answer, and knowing your XML mapping, I'd suggest the following annotation changes to orderId: @Id @GeneratedValue @Column(name="orderId", columnDefintion="BIGINT") String orderId; That's assuming that @GeneratedValue equates to a "native" generator as in your XML. You might need to use an @GenericGenerator instead with a strategy=native instead more like this: @Id @GeneratedValue(generator="my-native-generator") @GenericGenerator(name="my-native-generator", strategy = "native") @Column(name="orderId", columnDefintion="BIGINT") String orderId;

Categories : Spring

Hibernate @Valid and Spring MVC
The path to your messages file is wrong, the content of the resources directory is directly added to the classpath (just like the java directory). More information can be found on the maven website So instead of classpath:/resources/i18n/messages use classpath:/i18n/messages and the same goed for the errors file ofcourse.

Categories : Java

Ajax with spring mvc + hibernate
Thats too broad question to answer in depth. Seems you miss some knowledge how spring mvc works itself. You need to fetch List of rows using hibernate, then add it to mvc model in your controller then you will be able to list them using jsp. If you have it, then start reading about contollers which read/write JSON ( @RequestBody/@ResponseBody ).

Categories : Ajax

hibernate+spring get max id in range
What about something like this? List<Student> results = sessionFactory.getCurrentSession() .createCriteria(Student.class) .setProjection(Projections.max("id")) .add(Restrictions.between("id", 30000, 40000)).list(); if (results != null && results.size() > 0) { s = results.get(0); } else { // not found }

Categories : SQL

Hibernate Spring Joins
The tables will be joined if their relationship is one-to-many. In your domain files, the relationship between Employee_Domain and Employee is one-to-one. Try to change it to: @OneToMany(mappedBy="Employee_Domain") private List<Employee> employees= new ArrayList<Employee>(); And the join will happen.

Categories : Hibernate

Spring Framework - Hibernate
I'm not expertise in spring but I assume that you have a problem with your service, if you use an interface you should inject ut and not your class... see this track... Spring expected at least 1 bean which qualifies as autowire candidate for this dependency

Categories : Java

Hibernate Envers vs Spring AOP
I have just started using Hibernate Envers for auditing and so far I am very much satisfied with it. Pros: 1. We literally don't have to write a single line of code. 2.It also captures the userName and timestamp automatically through RevisionEvent, a very simple thing to configure. 3.the code follows JPA annotations, not hibernate. 4.Well if someone is using hibernate then why not use its entire feature. 5.This feature(Envers) is developed specifically to capture auditing. People are continuously working on upgrade and making it more user friendly. 6.One can write his own event listeners like for update,delete,insert etc: Cons: 1.Creates lots of AUD_ tables. However we can configure the table which we want to AUDIT. 2.It will never capture HQL queries automatically.

Categories : Misc

Spring Autowired DAO with hibernate.cfg.xml
You just define your bean twice! One with XML configuration: <bean id="accountingAccountDAO" class="com.tom.project.dao.accounting.HibernateAccountingAccountDAO"> <property name="sessionFactory" ref="sessionFactory" /> </bean> and one with @Repository annotation @Repository("accountingAccountDAO") public class HibernateAccountingAccountDAO implements AccountingAccountDAO Remove XML definition to get it worked!

Categories : Spring

Struts spring Hibernate
It is missing a jar file. ServletContextListener is in servlet-api.jar include that jar file in your project. (ServletRequestListener is in the same jar file)

Categories : Hibernate

implementing i18n spring mvc with hibernate
i18n and data persistence (ie hibernate ORM) is a different concept. Since you mentioned Spring, I would suggest start with Spring's i18n support. A good way to start is to create a Spring Roo project on STS. File -> New -> Spring Roo Project -> (enter project name, top level pkg) -> select packaging WAR On the Roo Shell, setup mvc by using web mvc setup Run the resulting project using maven embedded tomcat container mvn clean tomcat:run You will get a Spring MVC project complete with i18n and language switcher. Just a little taste on how you can localize your app: # File: messages.properties ----------- ... hello_prefix=Hello {0} ... # File: messages_zh_CN.properties ----- ... hello_prefix=你好 {0} ... Switch locale to Chinese simplified using `http://mycoolwebsite.com?lang=zh

Categories : Spring



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