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Error instantiating servlet class in Eclipse Europa?
Shouldn't it be public class First extends HttpServlet ? We should declare servlet class as public so that server can instantiate it. At least the Container complains so : SEVERE: Allocate exception for servlet A java.lang.IllegalAccessException: Class org.apache.catalina.core.StandardWrapper can not access a member of class com.First with modifiers "" at sun.reflect.Reflection.ensureMemberAccess(Unknown Source) at java.lang.Class.newInstance0(Unknown Source) at java.lang.Class.newInstance(Unknown Source)

Categories : Java

Tomcat Class Not Found - Servlet
This is how your webapp should look like : > DeCommGlobal > |-->src > |-->com > |-->authentication > |-->DeCommServlet.java > |-->META-INF > |-->WEB-INF > |-->classes > |-->lib

Categories : Eclipse

Error in instantiating canjs controller using requirejs
This is not a CanJS problem but more how AMD (and RequireJS works). If you define your models and controls like this: // models/home_m.js define(['can/model'], function(Model) { return Model.extend({ findAll: 'GET ../webService/ajax/ajax_router.php?q=desc', create: 'POST ../webService/ajax/ajax_router.php', update: 'PUT ../webService/ajax/ajax_router.php/{id}', destroy: 'DELETE ../webService/ajax/ajax_router.php/{id}' }, {}); }); // controller/home_c.js define(['can/control', '../model/home_m'], function(Control, homeModel){ return Control.extend({ 'init': function(element, options){ var self = this; console.log(self); Description.findAll({}, function(des){ console.log(des); }); } }); })

Categories : Javascript

Tomcat servlet not running - error 404
in the web.xml you have /PlayerController and /AdminController in the serlet mapping. So you should call localhost:8080/beergame/PlayerController or localhost:8080/beergame/AdminController Where beergame is the name of the folder which you have copied you

Categories : Tomcat

404 error tomcat when running a servlet
Try to change in web.xml By adding attributes to "web-app" tag like: <web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd" version="3.1" metadata-complete="false"> if you have already not done it. Check for enviornment variable Variable Name: CLASSPATH Variable Value: /lib/servlet-api.jar I think your class path is not set. Or Dump all the source files in /webapps/ROOT/WEB-INF/classes and add the lines in web.xml already present in /webapps/ROOT/WEB-INF. Hope this helps!!

Categories : Tomcat

Cannot be resolved to a type - Error while compiling servlet (tomcat) on RHEL 5
Looking at javac fbLoginServlet.java -classpath /root/apache-tomcat-6.0.37/lib/servlet-api.jar you are compiling the fbLoginServlet class without the UserDAO and UserVO classes. Change your classpath to javac fbLoginServlet.java -classpath /folder/containing/those/classes:/root/apache-tomcat-6.0.37/lib/servlet-api.jar Where /folder/containing/those/classes is the folder that contains the packages containing the missing classes.

Categories : Java

HTTP 404 Error when running a Hello World servlet with Tomcat 7 in Eclipse 3.7
If the server says ClassNotFoundException, it means the Class is Not Found Exception :-) Did you check your deploy and work directories inside tomcat? verify you really have the class inside your war (or uncompressed in the work dir) If not: put them manually to check your code works; then check why your eclipse or netb doesn't copy them to the server deployement dir

Categories : Java

how to access tomcat servlet in maven project structure with embeddable tomcat
Your application context path is /Archery (defined in context.xml) Your servlet path is also /Archery (urlPatterns property of @WebServlet) It's also duplicated by your web.xml So, your URL should be localhost:8080/Archery/Archery First server[:port], followed by context path, followed by servlet path Anyway, you will have to fix project structure in order for this to work. If you are following Maven conventions web resources directory should be src/main/webapp The web.xml (and context.xml) should be put under WEB-INF directory under this directory. After you have packaged the war, just make sure these files are there (under WEB-INF)

Categories : Maven

uninitialized constant error when instantiating class
Try adding "SharingHelper::" to your provider string before you :constantize it. It looks like you're trying to find a top-level Twitter rather than SharingHelper::Twitter.

Categories : Ruby On Rails

Error LNK2028: Thrown when instantiating an native C++ class within C++/CLI
What causes this linker error? Reason could be pBiosUpdate interface is not exported from the DLL to be visible to the DLL'S clients, in your case the C# code. How can I resolve the linker error so that the program runs as intended? use dllexport as mentioned here (or) Use a module definition file (.def file) to export the DLL's function as mentioned here

Categories : C#

Error when instantiating a generic class with a generic parameter
You can strip the type parameter on the constructor and surpress the warning public JAXBSerializing(Class<?> oType) { mType = oType; } Then this should not yield compiler error IXMLSerializing<MapEntry<String, String>> serializer = new JAXBSerializing<MapEntry<String, String>>(MapEntry.class);

Categories : Java

Tomcat 7 - use in in web.xml
This works fine for me in same environment (eclipse + Tomcat 7). Maybe you should check the web.xml schema version? I'm using this : <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0"> ... </web-app>

Categories : Jsp

App crashes when instantiating view controller from storyboard
Regarding your exception - your storyboard is probably not copied to the main bundle. See this. Also, the method instantiateViewControllerWithIdentifier uses the Storyboard ID defined in the Storyboard itself and not the name of the view controller. See this for more information on how to instantiate a specific view controller from a storyboard, or use the instantiateInitialViewController if you want to initialize the initial view controller (the one that is pointed by an arrow in your storyboard). Edit: the exception is raised because of a bug in iOS where storyboards with name modifier, such as Storyboard_ipad and Storyboard_iphone cause a confusion in an internal iOS mechanism inside [UIStoryboard storyboardWithName:bundle:]. The solution is to avoid using this naming convention and p

Categories : IOS

Java Servlet not working on Tomcat
First of all, according to your web.xml, the imageServlet is mapped to : /segnalazioni_degrado/imageUpload Secondly, you should remove the question mark from the url try changing it to: localhost:8080/Segnalazioni_Degrado/imageUpload and see what happens.

Categories : Java

servlet context to tomcat 7 root
check the context documentation. You're looking for the docBase attribute for your webapp's path and the path attribute for the root context, e.g. leave it empty as described in the attribute's documentation.

Categories : Java

Tomcat 6: How does Http11NioProtocol work without servlet 3.0?
With Tomcat you can create an ExecutorService to do your background processing. Or you could even spawn your own threads - or go for a more comprehensive solution of using JMS, using e.g. ActiveMQ to do async processing - either in the same JVM or on a different JVM. Some care must be taken, as if you reload your webapp, all threads you explicitly create, or implicitly by using an ExecutorService must be stopped - so you need to establish a ServletContextListener that shuts down these when the context is destroyed.

Categories : Tomcat

Tomcat Servlet Cookies Example Not Working
Cookie[] cookies = request.getCookies() is returning null which is the servlet engine's way of saying zero cookies have been submitted. You need to guard your for loop with a check against that. It was likely working 'sometimes' before because at the time there happened to be cookies in your IE session but not chrome that were being sent thereby allowing the loop to execute.

Categories : Java

Is this code instantiating or extending an abstract class without creating a new class?
It almost looks like the code extends WindowAdapter or overrides the windowClosing method This is exactly what's happening. but how is that possible without writing a new class? In fact, the code is creating a new (anonymous) class. It's just that the syntax is different to what you've come across so far. Take a look at the tutorial. For a discussion of how anonymous classes are used, see How are Anonymous (inner) classes used in Java?

Categories : Java

Trying to deploy GWT project in Tomcat ends with offending class error
Thou shall never deploy gwt-user.jar and/or gwt-dev.jar! Deploy gwt-servlet.jar if you use GWT-RPC or RequestFactory. If you're not using managed dependencies (Maven, etc.) you might have to deploy gwt-servlet-deps.jar too, which you'll find in the GWT SDK zip bundle. Otherwise, your dependency manager (Maven, etc.) should take care of transitive dependencies fro you. If you use managed dependencies, put gwt-user and gwt-dev in the provided scope (or whatever is equivalent for your build tool / dependency manager if you're not using Maven). See http://www.gwtproject.org/doc/latest/DevGuideDeploying.html#DevGuideDeployingServletContainerUsingRPC

Categories : Java

Error configuring application listener of class com.sun.xml.ws.transport.http.servlet.WSServletContextListener
It seems you didn't add dependency for com.sun.xml.ws.transport.http.servlet.WSServletContextListener in your pom.xml. Add the below repository(If already added, please ignore) and dependency in the pom.xml <repository> <id>deprecated</id> <name>JBoss Deprecated</name> <url>https://repository.jboss.org/nexus/content/repositories/‌​deprecated</url> </repository> and <dependency> <groupId>com.sun.xml</groupId> <artifactId>jaxws-rt</artifactId> <version>2.0EA3</version> </dependency> Now, package your application and deploy it. Note: The root cause of the problem is jar files needed for running your application is available in your netbeans classpath(hence, i

Categories : Java

package javax.servlet does not exist on Tomcat
Add servlet jar to the classpath in your IDE. Your webcontainer will provide it at runtime. You don't have to bundle it in your WAR

Categories : Java

More than one Singleton in a single servlet container (Tomcat)
No. The webapps should be isolated by ClassLoader within Tomcat, so each should have their own instance of the singleton. So long as the answer to #1 is in fact no, then the answer to this is also no. Probably not. As an aside, my understanding is that, as a general rule Java EE web apps are not supposed to spin up new threads.

Categories : Java

tomcat websocket servlet listening port
WebSocket is designed to work over HTTP protocol and so it won't have different listening port like normal TCP Socket but it use the same server port that it deployed on. so here in your case, if you are using tomcat server than websocket may use port 8080 (if you haven't modified explicitly) for communication. You may need to override onOpen and onClose methods of MessageInbound class to get notified on Connection established and connection close. Refer below sample code for more details. public class IncomingMessageHandler extends MessageInbound { private WsOutbound myoutbound; public IncomingMessageHandler() { } @Override public void onOpen(WsOutbound outbound) { logger.info("Open Client."); this.myoutbound = outbound; } @Override pu

Categories : Java

Python analogue to Tomcat and another Servlet-containers
You could use Jython (a Java-based Python interpreter) and actually deploy a Django app as a war file with Tomcat! It's quite outdated though, and gunicorn makes it trivial enough to deploy an app that it's not much different.

Categories : Python

Tomcat not loading Dispatcher Servlet (ClassNotFoundException)
Based on the stack trace you are missing spring-webmvc.jar which contains DispatcherServlet class. Try check your classpath again (WEB-INF/lib) to make sure that jar is there. Typically on a Spring MVC application you'll need these jars: I also recommend you use dependency management tool (eg: Maven / ivy) otherwise it's too hard to manage the jars yourselves

Categories : Spring

AS 5.1.0 tomcat web.xml servlet load-on-startup not work
You can develop your own web application instead of modifying the mentioned web.xml. It is not recommended to modify that file. WSO2 Application Server 5.1.0 comes with new class loading environments. Please refer http://docs.wso2.org/wiki/display/AS510/Webapp+ClassLoading So, the recommended way to load your own Servlet is to develop your own web application. You can choose appropriate environment for your use. Thanks!

Categories : Wso2

Start tomcat from servlet in jetty server
Try to run Tomcat so - ... String envCatalina = System.getenv("CATALINA_HOME") + "\bin\"; File dir = new File(envCatalina); Runtime runtime = Runtime.getRuntime(); Process process = runtime.exec(new String[] { "cmd.exe", "/C", "start", envCatalina + "catalina.bat", "start" }, null, dir); process.waitFor(); process.destroy(); ...

Categories : Java

Where place code in Servlet on start up using Tomcat?
Fortunately for you, there is a class for just such an initialization. In your web application, add a class which implements javax.servlet.ServletContextListener. In your web.xml, you must add that listener class so that the web container can know to run it. At that point, you have two methods you must implement: contextInitialized and contextDestroyed. You're guaranteed that it is launched exactly once at the start of your web application prior to accepting requests and exactly once at the end (assuming there are no serious errors). If you want to wait for these threads to finish, then start them and use Thread.join to wait until their completion so that you don't start accepting requests until they finish. For more information on how to implement a ServletContextListener, see

Categories : Java

HTML5 Server Sent Events using Java Servlet 3 and tomcat
I don't know about EventResource, but I understand that, if you are able to open resource in browser, it should take you one step ahead. Make changes as under in web.xml :- <servlet-class> Give full path to your servlet with package name like - com.test.sse <url-pattern> You can make /* here so it will work for every URL. After making this changes, try to open resource in browser and see if this helps.

Categories : HTML

How to upload file from micro control to a tomcat servlet
Your boundary has to be in the content type header. Also there should be an empty line between the http headers and the request body. Your headers end at Content-Length: 441 but the first new line is after Content-Type: text/plain and the parser expects the boundary at the beginning of the body but findsData from sample file. POST /Download/upload HTTP/1.1 Host: localhost:8080 Content-Type: multipart/form-data; boundary=---------------------------263081694432439 Content-Length: 422 -----------------------------263081694432439 Content-Disposition: form-data; name="file"; filename="sample.txt" Content-Type: text/plain Data from sample file -----------------------------263081694432439 Content-Disposition: form-data; name="destination" /tmp -----------------------------263081694432439 Cont

Categories : Tomcat

Unable to deploy my servlet from a Maven Project on Tomcat
Change <servlet-class>ConfigFileInput</servlet-class> to: <servlet-class>edu.apollogrp.dfe.configuration.masterconfig.ConfigFileInput</servlet-class> This should fix your error. And you should know some words about servlet life-cycle. There is no reqires of any main method in servlets.

Categories : Java

Tomcat servlet acting strange with json object
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("application/json"); PrintWriter out = response.getWriter(); Gson gson = new Gson(); LocationTypes locTypes = new LocationTypes(); String json = gson.toJson(locTypes); response.setContentType("application/json"); out.print(json); out.flush(); } try setting content-type as above

Categories : Json

android tomcat read servlet string text
Steps would be : Load the appropriate driver (Keep the driver class under WEB-INF/lib folder) Create a Connection object. Execute the Statement. Iterate through the ResultSet. Get the value of a particular row in a column. Now , look at your code : while(rs.next()){ name=rs.getString(""); // you didn't provide the column name here } Ideally , if the name of the column is name , then your code should have been: while(rs.next()){ name=rs.getString("name"); // here the name of the column is name } You can use either one of the following methods : getString(columnIndex): Retrieves the value of the designated column in the current row of this ResultSet object as a String in the Java programming language. Parameters: columnIndex - the first column is 1, the second

Categories : Java

java.lang.ClassNotFoundException for servlet in tomcat with eclipse
If there's no class test.ImageServlet in your WEB-INF/classes deployment, then Tomcat won't be able to find it. My guess is the you didn't compile, package, and deploy the WAR file properly to Tomcat.

Categories : Java

Sharing session attributes of a web service and a servlet within same Tomcat container
The fact that your class test.main.StoreCreds implements an interface com.data.credentials.manager.IFStoreCredentials doesn't change the fact that your object is still an instance of the concrete test.main.StoreCreds. And if the wabapp doesn't know about this concrete class, it can't use an object of this type, because it can't find the byte-code of the class of the object, which is obviously needed to use it. The concrete class must be shared by both applications. That said, shared sessions is not standard, and should be avoided. Consider making it a single application, or storing the data you want to share between apps in a shared database.

Categories : Java

Eclipse: Thrift inside Tomcat Servlet, ClassNotFoundException TException
While you included the thrift jars into your project, you also have to add them to the Tomcat library as well First make sure your external jars are in your project Java Build Path... right click your project, click Properties Under Deployment Assembly, click Add... Double click Java Build Path Entries... and select the jars/libraries you want to include

Categories : Java

Stream flushing in servlet - does it improve tomcat server side performance?
except for having the data sent faster to the client, what effect is there on the actual server and tomcat? It makes them do more work. Would the CPU usage/load be less when not using flush? Slightly, yes. The flush() itself costs CPU cycles, and also possible network delays. There really isn't much point, as the client can't do much until it has the complete response anyway. If the response isn't chunked or fixed-length, Tomcat has to buffer it all anyway to get the Content-length: anyway before sending it, in which case there is no advantage whatsoever.

Categories : Java

Instantiating a type in its own class
obj1 and obj2 are invisible inside the test() method. void new() is illegal method declaration as new is a keyword. You need to declare obj1 and obj2 as instance method or need to pass it somehow to the test() method as parameter. Rename the method void new() to something else. My suggestions are only to resolve the compilation error . It doesn't account for the logical errors , if any , in the code.

Categories : Java

Instantiating class by string
I haven't tested it, but I'm pretty sure it should be done like this (as per the doc): $obj = new $contrl;

Categories : PHP

Trouble instantiating inner class
Since getInnerX() method is defined in MyInner class. You can't access it directly without the object of MyInner class .So change the line System.out.println("inner.x = " + inner.getInnerX()); to System.out.println("inner.x = " + outer.inner.getInnerX());

Categories : Java



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