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While Sending Html Mails from my web application Recieved Mails contains Symbols like &ldquo,&rdquo, ‘
Check with another constructor for htmlView: ContentType mimeType = new System.Net.Mime.ContentType("text/html"); var htmlView = AlternateView.CreateAlternateViewFromString(bodyMessage, mimeType);

Categories : Asp Net Mvc

Regex to stop at a specific character
this grep line would do the job: grep -oP 'ds+K[^[]*' with your example: kent$ echo " 16 1VirtualMachine1 [aljkas] some_data.blah 17 Virtual Machine 1 [jklaj] some_more_data.blah 23 Virtu al Machin e 1 [adwv] some_more_data.blah 12 Virtual_Machine one [awa] some_more_data.blah 11 VirtualMa chineone [kladfsa] some_more_data.blah"|grep -oP 'ds+K[^[]*' 1VirtualMachine1 Virtual Machine 1 Virtu al Machin e 1 Virtual_Machine one VirtualMa chineone

Categories : Regex

Trouble rejecting a specific character in my RegEx
This should work for you: [a-zA-Z][a-zA-Z0-9.-]{2,25}s*$ What this regex will validate: The first character is a letter The input contains only alphanumeric characters (i added - also) if dont want - just remove - The input is 2-25 characters long

Categories : Regex

Regex to replace all occurrences of single character within specific tokens
A way to do this: $pattern = '~(?:TOKEN1:|G(?<!^))(?:[^:.]+|:(?!TOKEN2))*K.~'; $replacement = ' '; $subject = 'TOKEN1:Run.Spot.run:TOKEN2'; $result = preg_replace($pattern, $replacement, $subject); pattern details: ~ # pattern delimiter (?: # open a non capturing group TOKEN1: # TOKEN1: | # OR G(?<!^) # a contiguous match but not at the start of the string ) # close the non capturing group (?: # open a non capturing group [^:.]+ # all that is not the first character of :TOKEN2 or the searched character | # OR :(?!TOKEN2) # The first character of :TOKEN2 not followed by the other characters )* # repeat the non capturing group zer

Categories : PHP

How to remove words of a line upto specific character pattern...Regex
A pure bash one-liner: while read x; do [[ $x =~ test.* ]] && echo ${BASH_REMATCH[0]}; done <infile Input: infile This is a test page. My test work of test is complete. Output: test page. test work of test is complete. It reads all lines from file infile, checks if the line contains the string test and then prints the rest of the line (including test). The same in sed: sed 's/.(test.)/1/' infile (Oops! This is wrong! .* is greedy, so it cuts too much from the 2nd example line). This works well: sed -e 's/(test.*)/x03&/' -e 's/.*x03//' infile I did some speed testing (for the original (wrong) sed version). The result is that for small files the bash solution performs better. For larger files sed is better. I also tried this awk version, which is even better for

Categories : Regex

regex reject if found
Test for a string not existing to the end: (?:.(?!xyz))*$ It basically means, "Every single character from this point forth, must not be followed by xyz." Since . doesn't match newlines though, you might want to generalize it to: (?:[sS](?!xyz))*$ ^^^^^^ (It's union of complementary sets, therefore truly all characters.) To apply this to your case, just replace xyz with the thing you don't want appearing anywhere: # checks that the var name is NOT (using ?!) using one of the acceptable rejection methods (?:[sS](?! 1[.s]+ (?:setFeatures*(s*"http://xml.org/sax/features/external-general-entities"s*,s*falses*) |setFeatures*(s*"http://apache.org/xml/features/disallow-doctype-decl"s*,s*falses*) |setExpandEntityReferencess*(s*falses*)) ))*$ Us

Categories : Java

How to reject/close specific incoming number
Finally, solve the issue, Create IDL interface for getting core Telephony service package name must be com.android.internal.telephony FileName : ITelephony.aidl // First Here I am createing ITelephony.java For the create .aidl file New > File and write ITelephony.aidl And follow the steps Blocking a call without user intervention in android with an example.

Categories : Android

how to exclude a character in a regex pattern character class if last character?
I don't think it's possible in a single regex check... someone might be able to correct me on that, but I don't think so at the moment (Or I can't think to optimise things at the moment). What you can do, on the other hand, is run a check. Run the input through an initial replace function first to see whether there is a dot at the end or not and replace it if there is one. From there you can just feed it through the previous regex. So this is how it could go... function dotCheck( $url ) { $noDotURL = preg_replace( '/.+$/', '', $url ); return $noDotURL; } urlCheck( dotCheck( $_POST['form'] ) ); Where urlCheck is the main check to see whether it is a valid link structure or not. The regex - in verbose form - checks for any dots as the last characters in the link and deletes them.

Categories : PHP

Intellij IDEA regex character class may not be used inside character range
You are creating a range by using the hyphen(-) in mid of your character class. You should move it to either end. Also, note that you don't need to escape the regex meta-characters inside the character class. They loose their meanings in there. So, just use: [-w._+%]

Categories : Javascript

Regex to match text after a given character excluding the character itself
Look-around could be an option: (?<=")[^"]*(?=") (?<=") checks that the previous character is a ". (?=") checks that the next character is a ". Test. An alternative is just to use grouping: "([^"]*)" How to extract the group is dependent on the language used. Test. (note the "Matching groups" area) I didn't simply use "(.*)" because the string abc "def" "ghi" will match "def" "ghi", though you may have wanted to match "def" and "ghi" separately. An alternative to [^"] is non-greedy matching - "(.*?)", which will match as little of the string as possible.

Categories : Regex

How do you reject a string if preceded by another string using standard POSIX regex?
You want to use "Negative Lookbehind" (if it's supported by your regex engine.) effectively you say "I want to match X patern, as long as this other pattern does NOT preceed it." In your example, it looks like this: /(?<!read )(exception|error)/i see more about "lookaround" features here.

Categories : Regex

How to put a character at a specific point in a character array?
You have the problem in your output code: your printfs use userBoard.user[location] for all 16 cells (i.e. you are printing the same characters 16 times). This kind of error is what one usually gets for 'copy&paste programming'. Use loops. And I suppose you should print 12 cells, not 16.

Categories : C

Regex match up to character unless character in between
How about this: (.*?)([^s(]*(?=s|$))? It matches something in brackets, then optionally matches any number of non-space non-) characters followed by look-ahead to match a space (or end-of-string, in case it may appear at the end of the string). Note that there shouldn't be a | in [] (unless you want to match the | character). Live demo (surrounded by brackets and added non-capturing group (?:)).

Categories : Regex

matching un-closed font tags in the same line using regex
You are right that regex isn't very good for parsing HTML. Python as an HTML parser http://docs.python.org/2/library/htmlparser.html that should help with this task.

Categories : Javascript

Extracting contents from specific meta tags that are not closed using BeautifulSoup
Although I'm not sure it will work for every page: from bs4 import BeautifulSoup import urllib page3 = urllib.urlopen("https://angel.co/uber").read() soup3 = BeautifulSoup(page3) desc = soup3.findAll(attrs={"name":"description"}) print desc[0]['content'].encode('utf-8') Yields: Learn about Uber's product, founders, investors and team. Everyone's Private Dri ver - Request a car from any mobile phoneΓÇötext message, iPhone and Android app s. Within minutes, a professional driver in a sleek black car will arrive curbsi de. Automatically charged to your credit card on file, tip included.

Categories : Python

Javascript / REGEX: Delete a specific Text (word) starting with a specific letter inside a String with words separated by spaces
How about: str.replace(/sS+/ig,"") Explanation: NODE EXPLANATION ----------------------------------------------------------------------  the boundary between a word char (w) and something that is not a word char ---------------------------------------------------------------------- s 's' ---------------------------------------------------------------------- S+ non-whitespace (all but , , , f, and " ") (1 or more times (matching the most amount possible)) ---------------------------------------------------------------------- i is for case-insensitive g is for global

Categories : Javascript

regex allows one character (it should not) why?
Firstly, you can replace '[0-9]' with 'd'. So we can rewrite your first regex a little more cleanly as $?[d,]*.dd Breaking this down: $? - A literal dollar sign, zero or one [d,]* - Either a digit or a comma, zero or more . - A literal dot, required d - A digit, required d - A digit, required From this, we can see that the minimum legal string is .dd, three characters long. The regex you gave will never validate against any one character string. Looking at your second regex, [$]? - A literal dollar sign, zero or one ([0-9,])* - Either a digit or a comma, subexpression for later use, zero or more [.] - A literal dot, required [0-9]{2} - A digit, twice required This has the exact same minimum matchable string as above - .dd. edit: As mention

Categories : Javascript

Regex allow only 0-9 and the - character, and dot (.)
Your regex is weird... Regex invalidCharsRegex = new Regex(@"^*[0-9.]+$"); Remove the first asterisk, it's not doing anything good. And to allow - characters, you simply add it to the character class. Also, you don't need to escape the dot in a character class: Regex invalidCharsRegex = new Regex(@"^[0-9.-]+$"); If you're trying to validate a number, this regex will have to be revised, because the regex will accept ---- or ...... Something a bit like this for integer/floating numbers: Regex invalidCharsRegex = new Regex(@"^-?[0-9]+(?:.[0-9]+)?$");

Categories : C#

RegEX in trimming first two character
You can use String.indexOf to find the location of the = and then String.substring to get your two values: String currentLine = "BROWSER=Firefox"; int indexOfEq = currentLine.indexOf('='); String myKey = currentLine.substring(0, indexOfEq); String myVal = currentLine.substring(indexOfEq + 1); System.out.println(myKey + ":" + myVal);

Categories : Java

match first character in a regex?
http://([^/:]*):?([0-9]*)(/.*) The first group is matching everything but : and now I added /, that's because the [^] operator means match everything but what's inside the group, everything else is just the same. Hope it helped!

Categories : Regex

Regex character sets - and what they contain
Question 1: Find out. :) var accepted = []; for(var i = 0; i < 65535 /* the unicode BMP */; i++) { var s = String.fromCharCode(i); if(/[a-ö]+/g.test(s)) accepted.push(s); } console.log(s.join("")); outputs abcdefghijklmnopqrstuvwxyz{|}~ ¡¢£¤¥¦§¨©ª«¬­®¯°±²³ ´µ¶·¸¹º»¼½¾¿ÀÁÂÃÄÅÆÇÈÉÊËÌÍÎÏÐÑÒÓÔÕÖ×ØÙÚÛÜÝÞßàáâãäåæçèéêëìíîïðñòóôõö on my system. Question 2: What attacks are you looking to stop? Either way, the answer is "No, probably not". Instead of mangling user data (I'm sure your, say, French or Japanese customers will have some beef with your validation), make sure to sanitize your data whenever it's going into customer view or out thereof (HTML escaping, SQL parameter escaping, etc.).

Categories : Javascript

Regex match any character NOT followed by "? something"
Use parse_url: print_r(parse_url('/something/contentimg/coast03.jpg?itok=ABC')) ( [path] => /something/contentimg/coast03.jpg [query] => itok=ABC )

Categories : Regex

Regex C Help on escape character
FWIW, there's nothing wrong with your C++ code, and it works perfectly using Clang and libc++ on my MacBook. As indicated by the comments above, <regex> is one of the features that works in the LLVM project's libc++ but has never worked properly in the GNU project's libstdc++. You might try switching to libc++ if it's available for your platform.

Categories : C++

Regex deleted special character
Instead of this regex: Pattern.compile("[\w']+") Use Unicode based: Pattern.compile("[\p{L}']+") It is because by default \w in Java matches only ASCII characters, digits 0-9 and underscore. Another option is to use the modifier Pattern.UNICODE_CHARACTER_CLASS Like this: Pattern.compile("[\w']+", Pattern.UNICODE_CHARACTER_CLASS)

Categories : Java

exclude a certain double character in a regex
You can have something like the following: ^([a-zA-Z0-9]+[ -]?)*[a-zA-Z0-9]+$ http://rubular.com/r/VGfGTrqayR If you ALWAYS want to have 2 or more words, than you'd use the following instead ^([a-zA-Z0-9]+[ -])+[a-zA-Z0-9]+$ http://rubular.com/r/EdV3iBQbsw

Categories : Regex

Illegal character range in regex
You need to escape the double quote inside the string private static final String PASSWORD_PATTERN_SPECIAL_10 = ".*[~?!@#$%^&*()_-+=[]|\;:‘“<>,.?/]{10,20}.*";

Categories : Regex

apply regex only when a character is not at start and end
Use this regex that has lookaround: (?<!{)B$foo(?!}) Lookaround tutorial: http://www.regular-expressions.info/lookaround.html EDIT: I'm tempted to use balancing groups, but I won't for simplicity, so here is my solution as per your comment: (?<=(?:^|})[^{]*)B$foo(?=[^}]*(?:$|{))

Categories : Regex

Regex for 12th character must be Alphabetic or nil
How about this? I suppose nil means end of string... ^d{11}[a-zA-Z]?$ http://rubular.com/r/AhUsJHljD0

Categories : Asp Net

Regex matching a string followed by anything but a certain character
simply try $zgrep "momentaneousVehicleSpeedKmph=[^9]" file.gz if you don't want to match the single 9. /edit If you also need speeds with 2 digits and more, try: momentaneousVehicleSpeedKmph=([0-8]|[0-9]{2,})

Categories : Regex

Lookbehind with the ^ character in a Ruby regex
Look-ahead and look-behind are non-capturing/zero-length, so the first two expressions don't match. The first expression, for instance, amounts to another way of writing: /^d+/ (it's conditioned on d+ not being preceded by a space, but that's not possible since there cannot be anything before ^ anyway).

Categories : Ruby

Regex character case compatibility
It does indeed exclude characters from the outer character class. You can read about it here. To achieve the same thing in PCRE, you can use something along the lines of /[abdeg-wyz]/.

Categories : PHP

Regex required to update a character
Looks like you want a negative lookahead: s(?!<) String str = "testing<b>s<b>tringwit<b>h</b>nomean<b>s</b>ing;"; System.out.println(str.replaceAll("s(?!<)", "<b>X</b>")); output: te<b>X</b>ting<b>s<b>tringwit<b>h</b>nomean<b>s</b>ing;

Categories : Java

Regex to detect urls with '?' character at the end
Try this in your fiddle: var r = /(^|??)(www.[^?]+)/g; I updated your fiddle here: http://jsfiddle.net/DKNat/3/ Update: I see what you are trying to do now. Unfortunately, both your strings are essentially the same, apart from the /, so unless you want your regex to make the assumption that a ? anywhere after a slash denotes a CGI call, then there isn't much you can do. But you could try this: var r = /(^|??)(www.[^?]+/[^/]+?[^?]+|www.[^?]+)/g; Updated fiddle: http://jsfiddle.net/DKNat/5/ Update 2: After determining the requirements, this is the final RegExp I added to fiddle 10: var r = /(^|[?s])(www.[^? ]+/[^/ ]*?[^? ]+|www.[^? ]+)/g;

Categories : Javascript

Valid single character with dot at regex end
Note: based on the title of the question, I'm assuming that the expression you are using is [a-zA-Z0-9_]+. (at the time of writing, the question has been edited by someone other than the OP to remove that dot). Your regex currently requires "at least one of a-z, A-Z, 0-9 or _", followed by "exactly one of any character". Therefore, it requires at least two characters to match. The string "1" and "a" have only one character, and therefore do not match. Given your valid examples, are you sure you need that dot at the end? The expression [a-zA-Z0-9_]+ (without the dot) would match all your examples, including single character ones.

Categories : C#

Using Regex in Notepad++ to Replace a Character
There are two options. You could use capturing and write back what you matched (in addition to the quotes): ([a-zA-Z0-9]{16},)([a-zA-Z]+) Each set of parentheses generates a captured group. You can reference what they matched with $n in the replacement string: $1"$2. Note that there is no need to escape the comma. The alternative is lookarounds. What you match inside a lookaround is not part of the match, so it doesn't get removed. If you put everything around the desired position in lookarounds, you'll match a position instead of a string, and the replacement string will simply be inserted in that position: (?<=[a-zA-Z0-9]{16},)(?=[a-zA-Z]+) And replace that with ". In any case, make sure to upgrade to Notepad++ 6. Finally note that in both cases the + at the end is irreleva

Categories : Regex

JavaScript Regex - Replace all word characters except word characters between character X and character Y
'&nbsp;John &amp; Sandy are awesome & rock; They are also weird.'.replace( /(&[^s;]*;)|w/g, function(a, b) { return b || '*'; }); The result: &nbsp;**** &amp; ***** *** ******* & ****; **** *** **** *****. Tried and works for me in Firefox and Chrome.

Categories : Javascript

Regex - replace character with alternating characters
If you are only replacing underscores, you can probably do this without regex. By using the replaceFirst() method in whichever language your using. With regex you would only be detecting underscores and replacing them, same as this. Something like; myURL = myURL.replaceFirst("_",".cfm?"); while(myURL.contains("_")) { myURL = myURL.replaceFirst("_","="); myURL = myURL.replaceFirst("_","&"); } If you need a more complicated one to prevent detection of underscores in other parts of the URL if you outline what the possible combinations for that are I can probably help you find a suitable pattern to separate the domain from the parameters prior to replacement. According to the download page, you are doing this in .net? http://www.iis.net/downloads/microsoft/url-rewrite Ok I'v

Categories : Regex

Javascript regex - replace single character
Since Javascript doesn't support lookbehind assertions you can't check if the char before is an equal char or not. But you could match it an insert it again. return mystr.replace(/([^=:])=(?!=)/g, '$1=='); See it here on Regexr. ([^=:]) is a negated character class, that matches any char, but = and : . This char is reinserted in the replacement string by the $1. This would not work, when the first char in the string is a single "=", since the start of the string would not be matched by [^=:].

Categories : Javascript

CDbCriteria parameters with regex character classes
PHP will not replace placeholders inside strings, i.e within quotes. As in: $criteria->addCondition('col = :app'); // param can be replaced $criteria->addCondition('col = ":app"'); // param can't be replaced Therefore we need to use mysql's CONCAT() function to actually generate the string for regexp, instead of providing the string ourselves, like so: $criteria->addCondition('col regexp CONCAT("[[:<:]]", :app, "[[:>:]]")'); OR, bind the entire regex itself: $criteria->addCondition('col regexp :regexp'); $criteria->params = array(':regexp'=>'[[:<:]]'.$app.'[[:>:]]');

Categories : PHP

How to just more a string of more than 1 character in a regex replace expression vb.net
This is not how negated character classes work. The class disallows any single of the characters /, r, e, f, >. Also, you don't even want to rule out /ref> at all, because you want to remove all the intermediate refs as well. You can simply use .*. Also, you don't want lookarounds, because these exclude the things matched inside them from the match. But you do want to remove those tags as well. Hence, in your case, it should be as simple as: "<ref.*/ref>" Since * is greedy, this match will simply go from the first <ref to the last /ref> - usually a big problem of greediness, but in your particular case exactly what's desired. You might want to use RegexOptions.Singleline so that . matches line breaks, if there are any.

Categories : Xml



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