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Regex to match only letters between two words
I guess you're looking for something like this: import re def equal_letters(x, y): return re.sub(r'W+', '', x) == re.sub(r'W+', '', y) >>> equal_letters("Ultramagnetic MC's", "Ultramagnetic MC’s") True >>> equal_letters("Ultramagnetic MC's", "Ultramagnetic Foo") False

Categories : Python

Regex to match words in any order
You should be able to do this without the need for look ahead. Try a pattern like ^(one|two|three|s)+?$ the above will match one, two, three, or a s white space character.

Categories : PHP

regex pattern to match words of a string
You can use array_filter in combination with a regular expression to achieve this: $array = array("hello word", "lovely child", "i am lost in paradise" ); $term = "lo"; // necessary in case $term contains characters with special meaning in a regex $term = preg_quote($term, '/'); $results = array_filter( $array, function($el) use($term) {return preg_match('/'.$term.'/', $el);} ); The regular expression uses the word boundary anchor to ensure that the search term appears at the beginning of a word.

Categories : PHP

clojure regex to match words and everything inbetween
Try using the following regex: w+|W+ > (re-seq #"w+|W+" "This is a test. Only a test!") ("This" " " "is" " " "a" " " "test" ". " "Only" " " "a" " " "test" "!")

Categories : Regex

Regex to match words in sentence after a pattern
Maybe the regex should be: How much is (.*)? Or if you want to match all the words but one word in each capture: How much is (?:(w+)s*)+? Regex regexWords = new Regex(@"How much is (?:(w+)s*)+?"); foreach(Capture word in regexWords.Match(input).Groups[1].Captures) { // word.Value contains one word. } Good luck with your quest.

Categories : C#

Regex to match space separated words like CSS classes
You are probably looking for something like: (^|s)name(s|$) starting at the beginning of the string (^) or after whitespace ending at the end of the string ($) or before whitespace See e.g. http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html

Categories : Regex

Regex to match any words with the following condition: after the character %, it's allowed only to have %s or %.[0-9]f
Use a double negative! (?!.*%(?!s|.[0-9]+f)).* So the nested negative lookahead will cause the outer negative lookahead to fail if the % is followed by s or a valid float expression (like %.3f). You may want to add a beginning of string anchor here to make sure you don't get partial matches. Example: http://rubular.com/r/VTzJEUAlpb

Categories : Java

regex match all words in a python list not preeced by @
You could simply use a negative look-behind. A pattern like this should work: (?<!@)w+ Note the  (word boundaries) are there to ensure that it matches the whole word—without them it would match pples and uava.

Categories : Python

Java Regex: find a match only at the beginnings of words
You have to use a Pattern: final Pattern p = Pattern.compile("\bAbc"); // ... if (p.matcher(input).find()) // match FYI,  is the word anchor. Java's definition for a word character is the underscore, a digit or a letter.

Categories : Java

I need a regex to select words from given list of words.
Finally I found something ^((man1|man2|man3|man4)(,(man1|man2|man3|man4)){0,3})?$ only problem is I cant restrict duplicating. Any suggestion to restrict duplicating?????

Categories : Misc

regex to match entire words containing mandatory and allowed characters
you can do that with this kind of pattern, if your regex flavor have the lookahead feature: (?=[a-z]*?c)(?=[a-z]*?a)(?=[a-z]*?t)[actys]+ Note that lookarounds can be expensive due to the backtracks. You can limit it using two tricks: 1) using more constraints for character classes: (?=[a-bd-z]*c)(?=[b-z]*a)(?=[a-su-z]*t)[actys]+ 2) using possessive quantifiers (if supported) (?=[a-bd-z]*+c)(?=[b-z]*+a)(?=[a-su-z]*+t)[actys]++ or atomic groups in place of: (?=(?>[a-bd-z]*)c)(?=(?>[b-z]*)a)(?=(?>[a-su-z]*)t)(?>[actys]+)

Categories : Regex

regex to match entire words containing (one or more) mandatory and allowed characters
Rather than giving a straight answer, let me help you help yourself. A word that passes consists of a sequence of: zero or more allowed or mandatory characters a mandatory character zero or more allowed or mandatory characters Write regexes for each of these, then just concatenate them to get a regex for the entire thing.

Categories : PHP

Tagging words/phrases in a sentence based on Regex match in Perl
Using your own dump with a simple for to iterate with the 2 arrays: #!/usr/bin/perl use strict; use warnings; use Data::Dumper; my $text = 'zzzzzzz microRNA146a xxx (miR-146a, mir-33c) xxxx microRNA146a wwwwww Breast Cancer aaaa Breast Cancer zzzz mir-33c kkk'; # Rule 1 for miRNA definition my $i = 0; $text =~ s/(mir-dw+|micrornad+w?)/"[$1]<MIR-" . $i++ . ">"/gie; # Rule 2 for special words/phrases my $j = 0; $text =~ s/(breast cancer)/"[$1]<CANCER-" . $j++ . ">"/gie; print $text; Live DEMO.

Categories : Regex

A regex to highlight words in text
I dont remember the exact syntax of how it would look in javascript, but it would be something like for(var input : inputs){ string.regexReplace("("+input+")","<b>1<>") }

Categories : Javascript

Modify regex in a script that highlights certain words in a text by adding span classes to them
Did you consider processing the text highlighting on client-side using Javascript? jQuery or similar could allow you to iterate over nodes to find where to highlight instead of working with the raw HTML. I can't help you much with the regular expression though.

Categories : PHP

A program that opens a text file, counts the number of words and reports the top N words ordered by the number of times they appear in the file?
Use collections.Counter for counting words and open() for opening the file: from collections import Counter def main(): #use open() for opening file. #Always use `with` statement as it'll automatically close the file for you. with open(r'C:Data est.txt') as f: #create a list of all words fetched from the file using a list comprehension words = [word for line in f for word in line.split()] print "The total word count is:", len(words) #now use collections.Counter c = Counter(words) for word, count in c.most_common(): print word, count main() collections.Counter example: >>> from collections import Counter >>> c = Counter('aaaaabbbdddeeegggg') Counter.most_common returns words in sorted order based

Categories : Python

Replacing words in a list occuring in a text with words in another list
I don't really get where you're heading with those two lists structure. It's unclear, and I don't think you can get a proper algorithm out of that. You say: "For a given text if any of the words in position_list occurs, it must be replaced with specific words in position", that means that 'front' has to be replaced by 'down', 'frnt' by 'right' and 'rhs' has no replacement. That makes no sense! So I'm guessing, from the rest of your question, that you want the words that follows 'front' to be replaced by 'front', and the words that follows 'back' to be replaced by 'back'. But then, there's no information to help an algorithm know what words are the replacements, and what words are to be replaced. So the only solution would be to change your structures in a more pythonic way to make an e

Categories : Python

Perl regex to capture text between two anchor words but ignore anchor word in comments
This one is a bit tricky. The idea is usually to distinguish all the possible things that you do want to match, put them in an alternation and repeat. So what do we want to match? a single-line comment: // to the end of the string, no matter what. a block-comment: /* until the next */, no matter what. anything else, as long as it doesn't start endmodule The last part can be accomplished by using a negative lookahead at every position in the repetition. So let's put that together: $content =~ m~ modules+whatever # marks the start of the module (?: # each instance of this alternation matches one kind of # module "token" //.*+ # match a single-line comment | # or /[*] # op

Categories : Regex

Availability of a list with English words (including frequencies)?
As you mention, "corpus" is the keyword to search for. E. g. here is a nice list of resources: http://www-nlp.stanford.edu/links/statnlp.html (scroll down)

Categories : Python

Column of words to a list of words in quotation marks with commas separating them
You're looking for the string.join function For your specific example the code would look like: ', '.join(map(lambda x: '"' + x + '"',stuff)) Using the map function along with the lambda function effectively puts quotes around every element in your stuff collection.

Categories : Python

How do I capitalize all words in a string apart from small words in the middle and in the beginning?
It’s easiest to just forget about the special case of the first letter initially and then handle it after doing everything else: def title(sentence) small_words = %w[on the and] capitalized_words = sentence.split(' ').map do |word| small_words.include?(word) ? word : word.capitalize end capitalized_words.first.capitalize! capitalized_words.join(' ') end This also capitalizes any “small word” at the beginning, not just “the”—but I think that’s probably what you want anyway.

Categories : Ruby

In PHP, how to save words separated by space and lines and put words in array
use simple explode() function $str="new sample string"; $str=preg_replace("/s+/", " ", $str); $arr=explode(" ",$str); print_r($arr); output : Array ( [0] => new [1] => sample [2] => string )

Categories : PHP

Javascript / REGEX: Delete a specific Text (word) starting with a specific letter inside a String with words separated by spaces
How about: str.replace(/sS+/ig,"") Explanation: NODE EXPLANATION ----------------------------------------------------------------------  the boundary between a word char (w) and something that is not a word char ---------------------------------------------------------------------- s 's' ---------------------------------------------------------------------- S+ non-whitespace (all but , , , f, and " ") (1 or more times (matching the most amount possible)) ---------------------------------------------------------------------- i is for case-insensitive g is for global

Categories : Javascript

highlight words in php and return part that contains highlighted words
What about this solution? It uses preg_match_all() to get all occurrences of the word and displays max 10 characters left or right of it but highlights only the matched word $text = <<<EOF hello_world sdfsdf sd fsdfdsf hello_world hello_world safdsa EOF; $word = preg_quote('hello_world'); $text = preg_match_all("~(.{0,10})($word)(.{0,10})~is", $text, $matches); for($i = 0; $i < count($matches[0]); $i++) { echo '<p>' . $matches[1][$i] . '<span class="hl">' . $matches[2][$i] . '</span>' . $matches[3][$i] . '</p>'; }

Categories : PHP

How to change the color the words between two specific words in a sentence
I am not going to bother iterating and parsing your string thats trivial. SpannableString span1 = new SpannableString("pravind "); SpannableString span2 = new SpannableString("kumar"); span1 .setSpan(new ForegroundColorSpan(Color.BLUE), 5, 13, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE); span2.setSpan(new ForegroundColorSpan(Color.RED), 5, 13, Spannable.SPAN_EXCLUSIVE_EXCLUSIVE); mTextView.setText(TextUtils.concat(span1," " ,span2));

Categories : Java

Removing duplicate words in url and filtering out words not in a list
How about this one, using LINQ string str = "www.example.com/About/About/Videos/Videos/Videos/Featured/5-great-videos"; var result = str.Split('/').GroupBy(x=>x).Select(x=>x.Key).Aggregate((a,b)=>a+"/"+b);

Categories : C#

How could I match the three words
You can add more characters to the set of allowed characters by using a character class: /[w.]+/ The _ is already matched by w.

Categories : Regex

multiline regex pattern that match 3 digits
So the entire file must look like this? Then try new Regex(@"A(?:d{3} ? )*z") Explanation: A # Start of string (?: # Match the following (non-capturing) group: d{3} # - three digits ? # - one CRLF or LF (linebreak) )* # any number of times (0 or more) z # until the very end of the string If the file might not end with a newline (not sure from your description), you can use new Regex(@"A(?:d{3} ?$ ?)*z", RegexOptions.Multiline) This initially makes newlines optional ( ? ?) but ensures that there is a line ending after every three-character bit by placing the end-of-line anchor $ between CR and LF, which is where (strangely) .NET thinks it should match.

Categories : Dotnet

Multiline Regex matches first occurance but can't match second
Regex is not really the right solution for this, but if you must... Your problem is a combination of regex greediness and starting the match with ^. If it starts with ^ it needs it to start the string and it won't match anywhere else. The greediness of .* can be fixed by making it .*? instead. Try this: (d{4}-d{2}-d{2} d{2}:d{2}:d{2}) - (.*?) (Work notes) ([wW]*?)((?= d{4}-d{2}-d{2} d{2}:d{2}:d{2} - .*? (Work notes) )|((s{0,})$))

Categories : C#

git match tag with multiple words
If I understand you correctly, you could probably do something along the lines of: /^git describe --tag --dirty --match '(?:TEST|RUN)*'$/ Live demo and explanation: http://regex101.com/r/qC3gW5

Categories : Regex

Remove some words replace some other words from a txt file
This should do the trick. You use a list to store the objects you want to delete, and then loop through the list and remove every element in the list from the contents string. Then, you use a dictionary to store the words you have now and the words you want to replace them with. You also loop over those and replace the current words with the replace ones. def replace(): contents = "" deleteWords = ["the ", "and ", "in "] replaceWords = {"ancient": "old", "month":"years", "centuries":"years"} with open("meText.txt") as f: contents = f.read() for word in deleteWords: contents = contents.replace(word,"") for key, value in replaceWords.iteritems(): contents = contents.replace(key, value) return contents

Categories : Python

Remove words in string from words in array with c#
I just changed this line pattern = @"" + word + ""; to this pattern = @"" + word + @""; //added '@' and I got the result THIS IS AMAZING WEBSITE LAYOUT and it would be better if you use String.Empty instead of "" like: stringToClean = Regex.Replace(stringToClean, pattern, String.Empty);

Categories : C#

get each words from a string array + color words
Correct the usage of String array String [] words = mystring.split(" "); Then use the index to get each string. Eg: words[i] where i is the index. So instead of declaring a separate String for each, you may just use words[0], words[1] and so on without declaring addition variables. Its same as doing the following: String s1 = words[0]; String s2 = words[1]; ... Regarding showing in a TextView, its not clear what you want to show in the TextView. TextView text = (TextView) findViewById(Your_Textviw_ID); // you might have declared it in an XML somewhere. text.setText(the_sring_you_want_to_set_it_to);

Categories : Java

PHP: using levenshtein distance to match words
First of all it doesn't matter what outputs similar_text(), because it uses another algorithm to calculate similarity between strings. Lets try to understand why levenstein() thinks, that hw r u my dear ange is closer to orange than to 'how are you. Wikipedia has a good definition of what Levenstein distance is. Informally, the Levenshtein distance between two words is the minimum number of single-character edits (insertion, deletion, substitution) required to change one word into the other. Now lets count how many edits we have to do to change hw r u my dear angel into orange. hw r u my dear angel → hw r u my dear ange (deletion of last character) hw r u my dear ange → hw r u my dearange (deletion of last space) hw r u my dearange → arange (deletion of first 12 character

Categories : PHP

how should I do to match uppercase words also containing colon
You must add the colon in your character class. or just before the closing parenthesis of you capturing group (with a question mark if you want it optional). $str = preg_replace('~[A-Z]{2,}(?:s[A-Z]{2,})?:?~', '<b>$0</b>', $str); Notice: word boundaries are not needed here, since the regex engine begin from the left and your quantifier {2,} is greedy)

Categories : PHP

preg_match to match a list of words but not some
In order to exclude a certain list of words, you can combine two lookaheads: (?!webkit|robot)(?=bot|search|web|slurp|crawl) Apparently the first part would be your exclusion list. This would match "web" but not "webkit" A small note on the syntax. (?!regex) is negative lookahead and (?=regex) is a positive lookahead (non-consuming regular expression). You can read more upon it here. In short, a lookahead means "match regex expr but after that continue matching at the original match-point."

Categories : PHP

jquery autocomplete (NOT UI) , match beginning of the words
Have you looked at Typeahead? It has several options for matching and can potentially solve your problem. http://twitter.github.io/typeahead.js/examples/

Categories : Jquery

preg_replace doesn't match with two spaces between words
Unless you have some good reason to use that regexp, try something simpler, like: /([A-Zs]+):/ Also, just so you know, you can use asterisk to specify none or more space characters: s*

Categories : PHP

jQuery Datatables - match filtering words
One solution will be to have a hidden column (see bVisible) and add the alternate description in that column. (In your case, where the result is 4x4 then in the hidden column it would be 4wd and the other way around). So when you search you will get both results

Categories : Jquery

Words with single quote and `MATCH AGAINST` accuracy
I think this is in relation to your issue Full text query with a single quote I am almost certain dont or don't is a stopword.

Categories : Mysql



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