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Check the end of a string for valid regex and return the string trimmed of the regex-
You should simply replace: str = 'testfoostringfoo'; var regex = /foo$/; str = str.replace(regex, ''); return str; I removed the if, replace does not affect the string when regex is not found. Keep in mind that match returns an array of matches (['foo']), so the comparison to true fails either way: the condition in if(str.match(regex) == true) is always false. You're looking for if(str.match(regex)) or if(regex.test(str)). Note that trim is somewhat new in JavaScript, and it doesn't take parameters, it just removes whitespaces.

Categories : Javascript

Meta Regex: test if regex is only a string (no regex "wildcards")
Well, there's a quick two-step way to test for this. Instead of testing for escaped characters and wildcards in one regex, the first line of your function could remove escaped characters, then the second line would test the remaining string for wildcard-type expressions. .*(([.+?])|({[0-9]*,[0-9]*})|(*)|(+)).* will match a string that contains any *, +, {#,#}, or [] expression. In your function, return whether or not the passed string matches this expression.

Categories : C++

Convert JavaScript Regex String to PHP Regex String
Regular expressions are not language specific. They are applicable in most coding languages and used the same way -- the only difference is how they are applied. For PHP, use methods such as preg_match or preg_replace. For more information on Regular Expressions, go here. If you go to Languages and Libraries, you can see all the coding languages that support Regular Expressions. Some may require libraries or packages, but in general the way you write regular expressions is fairly universal. EDIT: I stand corrected as there are some very slight variations between different coding languages for how they handle Regex. You can find out how to make Regular Expressions for PHP here: http://www.php.net/manual/en/regexp.introduction.php You can also get more information on some of the subtle d

Categories : PHP

Performing a Regex Expression on a String of which may contain Regex Metacharacters?
.NET provides the Regex.Escape method for exactly this purpose: Dim regDirs = New Func(Of String, Boolean)(Function(i) Regex.IsMatch(i, "[d]+[s]" & Regex.Escape(strName), RegexOptions.Compiled Or RegexOptions.IgnoreCase))

Categories : Regex

regex - notepad++ - search for a string containing a string and not containing another string
Try using negative look ahead: user = (?![aA][bB]).* You are misunderstand how a character class works. The character class - [ab] matches only one character, out of all present inside [ and ]. So, it will match either a or b. I won't match ab in sequence. Basically [ab] is same as a|b.

Categories : Regex

Check a string for all or 3 consecutive characters of another string? Regex python NOT case-sensitive
You can create all triplets from string1 and then check if any of these triplets occur in string2: string1 = "Helloworld33" triplets = set([string1[i:i+3] for i in range(len(string1) - 2)]) result = not any(t in string2 for t in triplets)

Categories : Python

get specific string after first occurance of string regex sublime text 2 find & replace
I don't know that sublimetext2 but the regular expression would look like this: /include_once($pathToRoot.'header.php');(.*?)(</div>)/s The first group would be the string between the include and the closing div and the second group would be the closing div itself.

Categories : Regex

How construct this regex to find multiline string ended with first occurrence of a string?
You can use a lazy quantifier as Daniel Gimenez suggests it, or you can use this trick: $pattern = '~id="SomeDiv"[^>]*+>K(?>[^<]++|<(?!!--))*~'; explanations: K # reset all that has been matched before (?> # open an atomic group [^<]++ # all characters that are not <, one or more times | # OR <(?!!--) # < not followed by !-- )* # close the group and repeat zero or more times Capture groups are not needed since the result is the whole match. Note that the s modifier is not needed too since the dot is not used.

Categories : PHP

var X=Y transferrs string only before white space. Y = regex.exec(string);
match will return an array, not a string (or null if the string doesn't match). If you want the matched contents, those are in the first entry in the array: if (match) { $scope.userInputName = match[0]; } More in the specification and on MDN.

Categories : Javascript

How do you reject a string if preceded by another string using standard POSIX regex?
You want to use "Negative Lookbehind" (if it's supported by your regex engine.) effectively you say "I want to match X patern, as long as this other pattern does NOT preceed it." In your example, it looks like this: /(?<!read )(exception|error)/i see more about "lookaround" features here.

Categories : Regex

Need help writing a regex string to remove string with variable number
Include a pattern delimiter (in this case ~): $string = preg_replace('~::tt::[0-9]+::/tt::~', '', $string );

Categories : PHP

Regex match string UNTIL string in a comma separated line
Just use the following. Match from Passed, then everything, until Unique Passed.*Unique if [[ $line =~ Passed.*Unique ]]; then echo line matched $line done; fi EDIT: Since op revised his question to be a comma separated line. line=PassedShownWeekUnique,PassedShownDayUnique,PassedFailedWeek,PassedFailedDayUnique,Passed1Week,Passed1WeekUnique REGEX=Passed.*Unique IFS=','; for word in $line; do if [[ $word =~ $REGEX ]]; then echo matched $word fi done Output: matched PassedShownWeekUnique matched PassedShownDayUnique matched PassedFailedDayUnique matched Passed1WeekUnique

Categories : Regex

Find match of string in Regex, put into variable, tricky string
What you are after is (as in regular expression): {BaseClass.(?<inheritClassStr>.*?),Tuple.Create("(?<machineStateStr>.*?)",string.Empty)} to clarify: d that you used will math only numbers but identifiers in C# tend to contain letters as well. .* would math any character in greedy manner (so the more the better) so it is not a good choice here .*? will math any character but in not greedy manner (so as small set as possible) And there is no magic in C# so your declarations in regex wont get converted to variables but you need to access those like this: var inheritClassString = regex.Groups["inheritClassStr"].Value; And the @ on the beginning of string just indicates that c# compiler wont try to interpret special characters that can be put in otherwise not prefixed st

Categories : C#

RegEx. Check and pad string to ensure certain string format is used
You can replace space character with a blank one. In JS for example : "66882 5F 2".replace(' ','') // Will output "668825F2" "66882 5 F 2".replace(' ','') // Will output "668825F2" With regex, you can use "s" delimiter for white spaces First you eliminate spaces by replacing blank characters, then you use this regex ^1[5|6]([0-9]{5})0[5|6][A-Z]([0-9]{2})$

Categories : Regex

How to cut up a string from an input file with Regex or String Split, C#?
here's a start: string date; string subject; string from; string read; string to; foreach (string line in myString.Split(new string[] { Environment.NewLine }, StringSplitOptions.None)) { if(line.Contains("Subject=")) subject = line; else if (line.Contains("From=")) from = line; //...... }

Categories : C#

Regex - How to replace a string, without losing a part of string
REGEX <as+hrefs*=s*"/d+/(.+?)_-_(.+?).mp3/"s+classs*=s*"popover-with-html hidden-phone">.+?</a> Edit PHP code $pattern = '#<as+href="/d+/(.+?)_-_(.+?).mp3/"s+class="popover-with-html hidden-phone">.+?</a>#is'; $replacement = '<a href="melodie/$1_-_$2.mp3.html/" class="popover-with-html hidden-phone">$1 - $2</a>'; $my_clean_html_code = preg_replace($pattern, $replacement, $my_html_code); SAMPLE OUTPUT IN <a href="/29486389/Author_-_Name_of_Song.mp3/" class="popover-with-html hidden-phone">Andra - Inevitabil va fi bine.mp3</a> <a href="/29486389/Author2_-_sdfsd475.mp3/" class="popover-with-html hidden-phone"> Andra - Inevitabil va fi bine.mp3 </a> OUT <a href="melodie/Authodr_-_Name_of_Song.mp3.html/"

Categories : PHP

regex to match entire string unless string is /
It is entirely wrong to use a regex for this purpose, but per your request: re = %r{(?!A/z)(A.*z)} "foo"[re] #=> "foo" " /"[re] #=> " /" "/ "[re] #=> "/ " "/"[re] #=> nil If you want to get the string unless a string is "/", the way to do it is: string unless string == "/"

Categories : Ruby

Parse String from string with Regex
you have to escape special characters. use this: Regex regex = new Regex(@".signature=(.*)(", RegexOptions.Singleline); var v = regex.Match(html); string funcName = v.Result("$1"); you can find a very good explanation about escaping special characters in regex here (2nd paragraph): http://www.regular-expressions.info/characters.html Edit: if you search for this specific function in an entire html page, you will have problems, that is because .*is greedy, which means it tries to get as much as possbile (see a good explanation about that here: http://www.regular-expressions.info/repeat.html (3rd paragraph)) a better way would be: Regex regex = new Regex(@".signature=([^(]+)(", RegexOptions.Singleline); var v = regex.Match(html); string funcName = v.Result("$1"); [^(]+ searches for a

Categories : C#

Display a raw string from a "regex-like" string
If you just print the string, it should show it to you without all the "" elements: a = [' abc '] print a[0] >>> abc If you want to keep all the stuff inside: a = [' abc '] print repr(a[0]) >>>' abc '

Categories : Python

regex string contains max one '#'
what you can do is call 'your line'.match(/#/g).length in you method and if the length is greater than 1 you can exclude those results. after that perform your match if this condition satisfies, by chaining.

Categories : Javascript

To the last tag (already in a string) RegEx
First of all, you need to remove the quotes around your regex—if they're there, the argument won't be processed as a regex. JavaScript will see it as a string (because it is a string) and try to match it literally. Now that that's taken care of, we can simplify your regex a bit: arrayValues[index].replace(/[sS]*?<Section>/, "---"); [sS] gets around JavaScript's lack of an s flag (a handy option supported by most languages that enables . to match newlines). s does match newlines (even without an s flag specified), so the character class [sS] tells the regex engine to match: s - a whitespace character, which could be a newline OR S - a non-whitespace character So you can think of [sS] as matching . (any character except a newline) or the literal (a newline). See Javas

Categories : Javascript

String to float and regex
D means Non-digits. You need to use d instead. Look here for details: http://en.wikipedia.org/wiki/Regular_expression#Character_classes Updated I see, that your approach is to replace all non-digits chars. To my mind, match needed information is more clear: >>> import re >>> s = "15,00 EUR" >>> price_string = re.search('(d+,d+)', s).group(1) >>> price_string '15,00' >>> float(price_string.replace(',', '.')) 15.0

Categories : Python

Regex How to remove last ; from a string?
The following regex should work for you: ;(?=[^;]*$) So your replacement code would become: (;(?=[^;]*$), ""); Here is an example of the regex working on RegExr.

Categories : Dotnet

String replace with regex in PHP
Regex expression: (<[^>]*)styles*=s*('|")[^2]*?2([^>]*>) Usage: $1$3 Example: http://rubular.com/r/28tCIMHs50

Categories : PHP

How to get a portion of a string using RegEx
I would use this expression: MSI_([^_]+)(?:_|$) The capturing group would match everything after the first underscore _ all the way to the second underscore or to the end or the string, whichever comes first.

Categories : C#

Regex adding ; to the string
Since you are already using a negative character class you can as well expand it to: [^/;]*$ It looks a little weird since you are selecting multiple characters using the star (*) but if you claim it works for you then this one should too.

Categories : Regex

How to use regex to replace the string
You will have to do this in three steps. First you will have to find the "Random(1,9)" string. You can use a regular expression with capture groups to parse out the value range. See http://docs.oracle.com/javase/tutorial/essential/regex/groups.html. Next you will have to generate your random number. Finally you can use String.replaceFirst to replace the string with the number you've generated. If you want to support multiple occurrences per string, repeat that until there are none left. Edit: That said, if your range is always 1 to 9, Jlewis071's answer is sufficient and straightforward.

Categories : Java

Regex for First Line (Only) that Contains a String
Try match method. Here is an example: list = <<EOF [Home] (202) 121-7777 C (202) 456-1111 [mobile] 55 55 5 55555 [Work] (404) 555-1234 [Cell] (505) 555-1234 W 303-555-5555 M 777-555-5555 c 12346567s EOF Update #match line with "c" letter in line, even that are part of word puts list.match(/^.*C.*$/i) #match line with "c" letter in line, that are not a part of word puts list.match(/^W*CW.*$/i)

Categories : Ruby

Capitalization of String using Regex
you can use toLowerCase() for that Converts all of the characters in this String to lower case using the rules of the default locale. This is equivalent to calling toLowerCase(Locale.getDefault()). SEE HERE

Categories : Java

How can I get all matches of a regex in a string?
You can get all the matches like this: my @matches = $page =~ /<h1[^>]*>(.*?)</h1>/ig; print "@matches "; (But note that on yahoo.com, there is a single h1 tag)

Categories : Regex

Pig - String extraction using regex
Your data seems to be well formatted so i guess you can use the following expression to match the timestamps, notice it will only capture the hours in a group. If you need other parts of the timestamps just surround it with the parentheses ( and ). d{4}-d{2}-d{2}s(d{2}):d{2}:d{2}

Categories : Regex

how to use regex with variables instead of string?
You need to escape the escaped RegExp sequences: var foo2 = function (className) { return new RegExp("(?:^|\s)" + className + "(?!\S)", "g"); //----------------------^^^---------------------^^^ }; Your original function would return: foo("ASD") // returns: /(?:^|s)ASD(?!S)/g but we're after this: foo2("ASD") // returns: /(?:^|s)ASD(?!S)/g

Categories : Javascript

RegEx - String Help - Stata
If you have Stata 8 or later you could try: split Songwriter, p(,) split given Songwriter and p(,) will parse (split) on commas and throw those commas away. It will create Songwriter1, Songwriter2, etc.

Categories : Regex

PO Box RegEx At the Start of a String
What do you expect from us? You don't even give us valid/invalid strings. Have you tested your regexes somehow? What I see at the first glance, without knowing something about valid input is: One caveat that I can see is that the PO Box pattern has to be at the start of the string Do you want to match it only at the start of the string or not? You need to know that and define it in your pattern. If you don't want to, then remove the start of the string anchor ^ and replace it with a word boundary . {1} is superfluous, you can just remove it. For {0,1} there is a shortform ?, I like this better, because it is shorter. ^box((s){1}|[0-9]{1}) matches either "box" followed by a whitespace OR followed by a digit. Is this really what you want to match? (.) in the first regex: Why do you grou

Categories : C#

Is it possible to cut off the beginning of a string using regex?
I think this will work: var str = "/foo/bar/baz/hello/world/bla.html"; alert( str.replace( /^.*?(/[^/]*(?:/[^/]*)?)$/, "$1") ); This will allow for there being possibly only one last part (like, "foo/bar").

Categories : Javascript

how to deal with a string with regex
Try this String str="http://shop.vipshop.com/detail-97996-12358781.html"; String regex =".*detail-(\d+)-(\d+).html"; Pattern pattern = Pattern.compile(regex); Matcher matcher = pattern.matcher(str); if(matcher.matches()){ System.out.println(matcher.group(1) + "|" + matcher.group(2)); }

Categories : Java

Regex contain multiple string
You can use this pattern: a.*b|b.*a As in bool containsAandB = Regex.IsMatch(input, "a.*b|b.*a"); Or simply: bool containsAandB = input.Contains("a") && input.Contains("b"); If your dealing large inputs and you want to iterate over the string only once, a little bit of Linq can help: bool containsAandB = input.Where(c => c == 'a' || c == 'b') .Distinct().Take(2).Count() == 2;

Categories : C#

Regex with multiline string
If possible at all, can you generate the diffs separately? If you have access to the repository this should be the simplest solution. Otherwise, you cannot do it via regex - any line can start with --- or +++. The correct solution for splitting the changes is to actually parse the diff format and skip the indicated number of +, - lines and possible other indicators for each file chunk.

Categories : Python

Regex to eliminate particular String
If I understand your question correctly, you want to retrieve all of the lines that begin with 'call' and to make sure the call does not begin with loc_, in which case your regex appears to be somewhat of an overkill for the job. If you are using Java 8, I will offer you this solution: public List<String> functions(final String code){ return Arrays.asList(code.split(" ")).stream().filter(this::valid).map(s -> s.split(" ")[1]).collect(Collectors.toList()); } private boolean valid(final String code){ return code.startsWith("call") && !code.split(" ")[1].startsWith("loc_"); } If you're not using Java 8, surely you could modify the code above so it compiles with your version of the JDK.

Categories : Java

Using REGEX over splited string
It means the match is not found, and it returned None. Note that you might want to use re.search here instead of re.match. re.match matches only at the beginning of the string while re.search can search anywhere in the string. From the docs: Python offers two different primitive operations based on regular expressions: re.match() checks for a match only at the beginning of the string, while re.search() checks for a match anywhere in the string (this is what Perl does by default). If you already know that then you can handle that None using: if m: print (m.group()) else: #do something else

Categories : Python



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