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MVC3 Partial View : Not able to see html in View Source for Partial View render using Json object
Q1) Now I want go through the grid but when I try to inspect it I realize that there is no HTML code created in the browser's View Source. The HTML from your partial view will never appear in the page's source because it is not present in the initial HTTP GET. The View Source command in browsers displays the HTML received before any javascript is executed. Download and install fiddler and inspect the Ajax call in order to see the HTML that is returned from your controller. Q2 (implicit) Why is the partial view never displayed on screen? Your main view needs a div#dvgrid and your partial view needs to hosts the grid's content, like this: Main View : @{ ViewBag.Title = "Assign Price Values"; } @model IList<Bnym.Equinox.Accounting.Web.Portal.Models.Pricing.AssignCalculationsSou

Categories : Json

Redirecting after processing partial view with ajax results in next page loading inside the partial view's div.
Change the ajax form Ajax.BeginForm to a regular form Html.BeginForm so that the response is handled by the browser instead of the ajax callback. Alternatively you could manually redirect the browser on the ajax callback if it is successful.

Categories : Asp Net Mvc

Forwarding the partial view's details to HttpPost method of a controller when button in partial view is clicked
Have you tried this? @using(Html.BeginForm("Add", "AddCredit")) { @Html.HiddenFor(m=>m.CreditBalanceId) <div class="input-small" id="credit">@Html.EditorFor(m=>m.CreditToAdd) </div> <button type="submit" class="btn">Add Credit</button> }

Categories : HTML

MVC Ajax Edit button from partial view to re render other partial view
I call my controller through an ajax call $.ajax({ url: "@(Url.Action("Action", "Controller"))", type: "POST", cache: false, async: true, data: { data1: 'data1' }, success: function (result) { $(".Content").html(result); } }); Doing it this way I replace the contents of a div with the partial view that is returned from the controller. I don't know if it will make a difference but my method for the partial view I return PartialViewResult instead of ActionResult. Hopefully this helps.

Categories : C#

open a popup from partial view and reload the parent partial view
I use jquery ui dialog for work like this. There is no reason to load the partial right on the view. In my *.cshtml i have a div which will eventually become my dialog <div id="delegateDialog" class="actionDialog"></div> Then, when a specific button is clicked, this method would be called to load the dialog: var loadDelegateDialog = function(processInstanceID, serialNumber) { var $dialog = $('#delegateDialog'); var title = "Delegate Workflow #" + processInstanceID; var actionUrl = '@Url.ActionFor((TaskListController c) => c.GetDelegateDialog(Model.TaskListID, null, null))'; $.ajax({ url: actionUrl, type: 'POST', data: { processInstanceID: processInstanceID,

Categories : Javascript

Possible to add partial view into a pre-rendered partial view in MVC3/4 within browser request?
You can add partial views with ajax: Controller "MyController": public ActionResult GetPartial() { var identifier = Guid.NewGuid(); return PartialView("_MyPartial", identifier); } JS: function addPartial(){ $('<div></div>') .load('@Url.Action("GetPartial", "MyController")') .appendTo('#container'); } First partial view: <div id="container"></div> <input type="button" value="add" id="btnAdd" /> JS: $('#btnAdd').click(addPartial);

Categories : Dotnet

Refreshing partial view from another partial view, asp.net mvc4
You can use jQuery to refresh the div2 on click. 1) You can bind the click event and perform some action. e.g. $("#button1").click(function(){ /// Code to refresh div 2 } ) 2) You can raise an event and to the work in registered event.

Categories : Asp Net

Reload partial view with a button in the partial view
The reason this happens is because you are using: onclick="location.href='@Url.Action("RequestChangeVisibility", "ManageDepartment", new { change = @item.ModelId })'" This will refresh the whole page to the partial view result, so you only see that partial view. what you need to do is to do an ajax call to that controller, so you should use: <td><button name="button" class="button" onclick="RequestChangeVisibilityAjaxCall(@item.ModelId)">Change Visibility</button> then add the following javascript to the page: <script> function RequestChangeVisibilityAjaxCall(change) { $.ajax({ url: "../ManageDepartment/RequestChangeVisibility?Change=" + change, type: 'GET', success: function (data) { $('#Dep

Categories : C#

"Cannot Resolve Partial View X" in Umbraco 6 Html.Partial
Fixed. The issue was with the model I was passing to the document type view from the controller. In the Umbraco documentation it says, you can create a controller to hijack the Umbraco route and serve up your own view with a custom model, like so: public ActionResult Index(RenderModel model) { SearchResultsViewModel viewModel = new SearchResultsViewModel return CurrentTemplate(viewModel); } and in my view I had: @inherits UmbracoViewPage<SearchResultsViewModel> However, it seems as though, in order to do that, you must make sure your custom view model in inherits from RenderModel with a constructor that takes RenderModel as a parameter and then sets some properties on the base object, like so: public class SearchResultsViewModel :RenderModel {

Categories : Asp Net Mvc

Utility to view partial classes as if they were not partial
You should create a Class Library i is meant for re-usability. But you will still need the 2 files if you want to be able to modify the interface visually. VS need them to display at design time. In the library just right click the solution explorer and choose add existing item then browse for the form your want and select the form1.cs and add that, the designer file should get imported automatically.

Categories : C#

Trouble rendering a partial view on the same page as main view using Ajax.ActionLink()
I was able to get it working. The problem was where I added in the script source. This: <script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.js")" type="text/javascript"></script> Needs to be placed inside your layout file towards the bottom like this: @Scripts.Render("~/bundles/jquery") <script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.js")" type="text/javascript"></script> @RenderSection("scripts", required: false)

Categories : Ajax

How to prevent view from passing its model to the partial view, but instead pass null?
I understand the reason you want to not pass the model is so that your inputs are emptied out? If this is the case, you can rather pass a new Model to this partial: @Html.Partial("Child", new Model()) Since the Model is new, it won't have any values populated.

Categories : Asp Net Mvc

post a form using ajax inside a partial view which loaded on another view
This way worked for me. Adapted to your situation: @model Stockala.Models.Keyword @using (Ajax.BeginForm("Create", "Keyword", new AjaxOptions { HttpMethod = "POST", InsertionMode = InsertionMode.Replace, UpdateTargetId = "keywords-div" })) { <div id="keywords-div"> //Rest of the form body </div> } remove the '()' from your "new AjaxOptions ()"

Categories : Asp Net Mvc

Submit button in a partial view is invoking the POST action method of the main view.
Given the symptoms, this is most likely because you've placed your partial view inside of an existing <form> element from where you are rendering this partial view. e.g. <form> @Html.RenderAction(...) </form> Whereat you are rendering another form and it's bubbling up to the top parent form.

Categories : Asp Net

Delete partial view info with parent view in asp.net MVC4
When you use scaffolding,by default it does not map child entity. In your view you need to add partial view, and you also need to write code to display and save them properly. First thing I would suggest to add a default constructor in the BranchInfo class: public class BranchInfo { public BranchInfo() { BranchName = ""; Description = ""; EntryDate = DateTime.Now; EntryBy = ""; ContactDetails = new ContactDetails(); } [Key] public int CompanyId { get; set; } public int BranchTypeId { get; set; } public string BranchName { get; set; } public string Description { get; set; } public DateTime EntryDate { get; set; } public string EntryBy { get; set; } public ContactDetails ContactDetails {get;set;} } And w

Categories : Asp Net

Laravel 4 - including a "partial" view within a view (without using Blade template)
You can nest your partials in views try this View::make('folder.viewFile')->nest('anyname', 'folder.FileName'); Then access the nested view file from your template {{ $anyname }} this way you don't have to include files in your view and this should work for .php file also.

Categories : PHP

Render partial view (with controller action) from another view
You could use a child action and the Html.Action helper. Phil Haack wrote a nice blog post about child actions here: http://haacked.com/archive/2009/11/17/aspnetmvc2-render-action.aspx

Categories : Asp Net Mvc

In an action can I select a partial view to include in my view?
Sure, just dump the value (or a boolean or whatever else you want to make it more readable) into the ViewBag or ViewData or ViewModel, then read from it on your view: @if (Model.RadioButtonValue == 1) { @Html.Partial("Part1") } else { @Html.Partial("Part2") } or <% if ((string)ViewData["radiobutton"] == "1") { %> <%= Html.Partial("Part1") %> <% } else { %> <%= Html.Partial("Part2") %> <% } %> You could also put the name of the partial itself in the ViewBag/ViewData/ViewModel, rather than having the conditional in the view: @Html.Partial(Model.ThePartialName)

Categories : Asp Net Mvc

ASP.NET MVC Validation in Partial View and return to Parent view
You need to show the parent view not the child one, so the action should look like: [HttpPost] public ActionResult SubmitReview(ChildViewModel model) { var parentViewModel = write init code here; parentViewModel.ChildModel = model; if (ModelState.IsValid ) { return View("Index", parentViewModel ); } ModelState.AddModelError("", "Some Error."); return View("Index", parentViewModel ); }

Categories : C#

Getting data from ajax Partial View to use in the parent View
You could solve this by doing some manual JavaScript programming instead of falling back to the Ajax class in asp.net. By using jQuery (or other libraries, I just prefer jquery because its widely used and tends to get the job done most of the time) you can execute Ajax calls just as easily as by using asp.net ajax, and in addition store variables and stuff. You could start by putting this in your partial view @foreach(Category category in Model.Categories) { <li><a href="#" onclick="return loadCategory('@category.CategoryId');">@category.Name</a></li> } Clicking the link will now cause the browser to call the loadCategory JavaScript function, which you'll find below <script type="text/JavaScript"> var s_currentCategory = -1; var loadCateg

Categories : C#

How to pass value from partial view to parent view in asp net mvc3
Try like this in your partial: @{ var test = ViewContext.ParentActionViewContext.ViewData["testData1"]; var test2 = ViewContext.ParentActionViewContext.ViewData["testData2"]; }

Categories : Asp Net Mvc

Backbone load a view within a view (as partial)
Since Backbone views can populate the browser with html dynamically, you only need to have one div element for content. This div element will then serve as a placeholder for the nested view generated by the view managing the tabs. I had to solve a very similar problem and here is what I did: First, define a control structure to bind a tab title to a view constructor: var Tab = function( title, viewConstructor ) { this.title = title; this.viewConstructor = viewConstructor; }; _.extend( Module.prototype, { render : function( options ) { this.view = new this.viewConstructor( options ); return this.view.render(); }, close : function() { if( this.view ) { this.view.close(); } } }); Then, define all your tabs in an array: var tabs = [ new

Categories : Javascript

Display Partial view in same View mvc4
Put breakpoint in both of the AccountDetails action methods. I think that the load method use get method in the request and your second action method is decorated with HttpPost attribute. Try use the ajax method of the jQuery: jQuery.ajax

Categories : C#

Python strip. can't strip newlines but using f.read()
rstrip or lstrip or strip only removes whitespaces from edges. Do this to clean up the whitespaces inside of a string. import sys file = sys.argv[1] with open(file, 'r') as infile: data = infile.read() clean_data = ''.join(data.split()) print clean_data

Categories : Python

What is the difference between view & partial view in mvc
As far as i know, a partial is used as part of a view and can be shared across multiple views to provide extra functionality for those views. Also, views can be broken down to partials to make editing easier and eliminate redundancy. Hope it helps a little

Categories : Misc

ASP.NET MVC 4, Partial View
It sounds like you need to pass the correct model to the partial view. By default calling a partial view passes the model which the parent view has. So if you are passing the 4 lists to the main view then each partial call should include the correct IEnumarable object for the view. You can pass a model with a partial call like this: @Html.Partial("_partialName", model) Hope this helps

Categories : Asp Net

about partial view's path on Asp.Net MVC
I believe MVC automatically searches through all files and folders in Views/Shared so I think all you need is: @Html.Partial("_category") Beyond that if you're in a specific area then it searches both main/root views folder and the current areas views folder. If you're trying to access partial from one area while you're currently in another then you're doing something wrong.

Categories : Asp Net Mvc

Regarding loading of partial view in mvc
@Html.Action("Load", "Home") Will execute the "Load" ActionResult in your "HomeController". This Action may return any of these (ref: MSDN): ContentResult EmptyResult FileResult HttpUnauthorizedResult JavaScriptResult JsonResult RedirectResult RedirectToRouteResult ViewResultBase While @Html.Partial("_LoadView") Will insert your partial view "_LoadView" into your current view. If you're familiar with web forms, think of your partial views as .ascx (user controls). Edit: Example of usage of @Html.Action(): Say you have this view: <p>Here is my name: @Html.Action("Name")</p> And this is my controller (As you see, I use the overload of Html.Action() that implicit uses the controller you're routed to): public class FooController : Controller { // // GET: /F

Categories : Asp Net Mvc

Pagination in Partial View
Judging from the code you provided it seems that you are setting the ajaxUpdateContainerId to "result" but there is not any control with that id on your page you can set the id in .GetHtml() method by providing HtmlAttributes. So the edited line would look something like this: @grid1.GetHtml(htmlAttributes: new { id="result" },tableStyle: "WebGrid", headerStyle: "Header", alternatingRowStyle: "alt", columns: ViewBag.Columns) Please check this link for more details

Categories : Asp Net Mvc

Cached partial view
You have to use ModelState.Clear(). When your are reposting your View its value is populated from ModelState. public ActionResult Save(Model m) { ModelState.Clear(); var db = new Db(); m.Prop = "New Value"; db.Save(m); return PartialView("_ModelForm", m); }

Categories : Asp Net Mvc

Use section in partial view
As discussed in this question, it is not possible to use sections in a partial view: Sections don't work in partial views and that's by design. You may use some custom helpers to achieve similar behavior, but honestly it's the view's responsibility to include the necessary scripts, not the partial's responsibility. I would recommend you using the @scripts section of the main view to do that and not have the partials worry about scripts. You should add the script reference to the main view that references the partial.

Categories : Asp Net Mvc

MVC 4 - Use a different model in partial view
There is an overload of @Html.Partial which allows you to send ViewData as defined in your controller - this is the method I generally use for partial views. In your controller define ViewData["mypartialdata"] as ViewDataDictionary. Then in your view @Html.Partial("_ModifyProfileInfo",ViewData["mypartialdata"])

Categories : Asp Net

Using reflections in partial view
Type modelType = typeof(model); Your model is a variable (property) here, not a Type. Use: Type modelType = model.GetType(); But seriously, one guideline in MVC is that Views should be simple. I am very skeptical about this kind of design.

Categories : C#

Asp.Net mvc 4 with jQuery partial view
You have to pass the id of that item which was being edited as routevalues in your return statement like below return RedirectToAction("ActionMethod", new { ItemID = value }); If you want to know more about Routing in ASP.Net MVC the link is given below: http://msdn.microsoft.com/en-us/library/cc668201(v=vs.100).aspx

Categories : Jquery

issue about partial view
Define the model class for your partial view as you have for the main view, set it to the type of your "item" class and call the renderer: @{ RenderPartial("..partialName...", item); }

Categories : Asp Net Mvc

MVC Partial view not rendering
Here is my partial view called _MessagingPartial.cshtml Your partial view should be called Messaging.cshtml coz that's the name of the controller action that rendered it. If you want to render a custom partial name, make sure you explicitly specify that: public ActionResult Messaging() { var model = new ViewModels.Messaging { MessageType = Utilities.MessageType.Success, MessageHeader = "Test", Message = "this is a test message" }; return PartialView("_MessagingPartial", model); } and if the partial is located in some non-standard location you could also specify the full path to it: return PartialView("~/Views/FooBar/Baz/_MessagingPartial.cshtml", model);

Categories : Asp Net Mvc

Adding Partial view with javascript
See below example HTML: <fieldset> <legend>Some Form</legend> <div id="divPartial"> </div> <input type="button" id="mybutton" value="Add new Item" /> </fieldset> Jquery: <script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js"></script> <script> $(document).ready(function () { $("#mybutton").click(function () { var url = "/Item/FilteredItemGallery/"; $.ajax({ url: url, cache: false, type: "POST", success: function (data) { $('#divPartial').html(data); /* little fade in effect */ $('#divPartial').

Categories : Javascript

Nested collection view partial in ASP MVC
Here is how you should do it; let's say this is your main Model: public class MainModel { public IEnumerable<Kid> Kids { get; set; } // Other properties } Do this in your main View: @model MyApp.Models.MainModel @Html.EditorFor(model => model.Kids) Then, create a partial view like below, name it Kid.cshtml, and place it under Views/Shared/EditorTemplates: @model MyApps.Models.Kid @* Your html helpers (input fields) *@

Categories : Asp Net Mvc

Partial view rendering issue
If you really need to make the list go into partialView1 and cant change the model signature (which is what you should do), you can use @Html.Action("ActionName", "ControllerName") to go to an action that returns a partial view. This would likely incur an extra database trip. To do it the correct way, you should change the partial view signature to accept the entire viewmodel, or at least a model that encompasses both List and model1.

Categories : Asp Net Mvc

Umbraco Partial View Macro
It sounds like all you need to do is add your macro to the content. In the Developer section of the Umbraco Admin backend click right on the Partial View Macro Files folder and select create. Leave the Create Macro checkbox ticked and enter a name for your macro. In the .cshtml file created, paste in your call to the partial view and save that. Then the bit it sounds like you missed is in the content rich text editor, place your cursor where you want the macro and select the Insert Macro from the top bar, where you save and publish and pick styles etc. and select the macro you have just created. One difference between my version of forms and yours is instead of @Html.Partial() I use @Html.Action().

Categories : Asp Net Mvc



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