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How can I find the instance of a user in this javascript user system codebase?
I've never used it, but it's built using Mongoose and it exposes a db.users collection which you can query for user information. If you're interested in that, you can use it like so: db.users.findOne({ username: 'pinky' }, function(err, user) { // work with user here if it was found! }); You will have access to the following user properties and functions based off of the schema: var userSchema = new mongoose.Schema({ username: { type: String, unique: true }, password: String, email: String, roles: { admin: { type: mongoose.Schema.Types.ObjectId, ref: 'Admin' }, account: { type: mongoose.Schema.Types.ObjectId, ref: 'Account' } }, isActive: String, timeCreated: { type: Date, default: Date.now }, resetPasswordToken: String, twitter: {}

Categories : Javascript

Can .Find method return wrong results in multi-user environment
Well the docs state that Find... Uses the primary key value to attempt to find an entity tracked by the context. If the entity is not in the context then a query will be executed and evaluated against the data in the data source, So it searches the cache first. If what's in your cache is old (or doesn't exist in the database - and maybe never will) then that's what you get. It ONLY does a query if it can't find the entity in the cache. I wouldn't say it returns the "wrong" thing because of what it's defined to do. If you need to find data that might be changed by another user or that's guaranteed to exist in the database you'll want to stick with a query.

Categories : C#

How to find matches among two list of names
which and %in% would probably be good for this task, or match depending on what you are going for. A point to note is that match returns the index of the first match of it's first argument in it's second argument (that is to say if you have multiple values in the lookup table only the first match to that will be returned): set.seed(123) # I am assuming these are the values you want to check if they are in the lookup 'table' list2 <- sample( letters[1:10] , 10 , repl = T ) [1] "c" "h" "e" "i" "j" "a" "f" "i" "f" "e" # I am assuming this is the lookup table list1 <- letters[1:3] [1] "a" "b" "c" # Find which position in the lookup table each value is, NA if no match match(list2 , list1 ) [1] 3 NA NA NA NA 1 NA NA NA NA

Categories : R

How do I use find to search for symlink names under OS X?
You want find to follow the symlink. find -L, at least on FreeBSD which is pretty close to osx. angst(~/test2) > ll -l total 0 lrwxr-xr-x 1 antiduh antiduh 8B Jul 3 20:09 binlink@ -> /usr/bin -rw-r--r-- 1 antiduh antiduh 0B Jul 3 20:09 sekrits angst(~/test2) > find . . ./sekrits ./binlink angst(~/test2) > find -L . . ./sekrits ./binlink ./binlink/bc ./binlink/addr2line

Categories : Osx

Find and link instagram names
$(".post-text:contains('@')").each(function(){ var $this = $(this), username = $this.text().split('@')[1]; //take name after the @ symbol $this.addClass('arrow').data("link", "http://instagram.com/" + username); }); And here's the jsFiddle illustrating the solution.

Categories : Jquery

find numeric id names for all elements
var tdList = $('#tableid td').filter(function() { return !isNaN(this.id); }); DEMO The only potential problem is that an id like this -1.23 would be included, it's up to you to decide if this is a problem or not. EDIT If only positive integers are allowed, you could do something like this var tdList = $('td').filter(function() { return /^d+$/.test(this.id); }); DEMO Thanks @Sly and @jods

Categories : Javascript

SQL Server Query to find different names in two tables
Try: select coalesce(t1.Col1, t2.Col1) from [Table-1] t1 full outer join [Table-2] t2 on t1.Col1 = t2.Col1 where t1.Col1 is null or t2.Col1 is null SQLFiddle here. Alternatively: select Col1 from (select Col1 from [Table-1] union all select Col1 from [Table-2]) sq group by Col1 having count(*) = 1 SQLFiddle here.

Categories : SQL

How to change file and directory names with find?
First create a shell script like this: #!/bin/bash dir=$(dirname "$1") mv "$1" "$dir/$2" Then this find should work for you: find . -name "old_name" -exec ./ren '{}' 'new_name' ; This will find file with the name old_name from the current dir in all subdir and rename them to new_name

Categories : Linux

How can I find the names of missing parameters in Python?
This has changed in Python3.3 (at most), you get the missing argument names for free: >>> def getVolume(length, width, height): ... return length*width*height; ... >>> print(getVolume(height=3, width=3)); Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: getVolume() missing 1 required positional argument: 'length'

Categories : Python

Elegant way to use unix find for many file extensions and names
You can do it more succinctly with -regex, e.g. for your example: find -E $dir -regex '.*.(pl|sh|jar)' -o -regex '.*/File(A|B)' Note that Linux find lacks the -E switch - you will have to use -regextype posix-extended in place of -E if you're using Linux (thanks to @Ansgar for pointing this out).

Categories : Bash

Find nearest neighbor names from KKNN package
Here's a slightly modified version of your example: full= data.frame( name=c("McGwire,Mark","Bonds,Barry","Helton,Todd","Walker,Larry","Pujols,Albert","Pedroia,Dustin"), lag1=c(100,90,75,89,95,70), lag2=c(120,80,95,79,92,90), Runs=c(65,120,105,99,65,100) ) library(kknn) train=full[full$name!="Bonds,Barry",] test=full[full$name=="Bonds,Barry",] k=kknn(Runs~lag1+lag2,train=train, test=test,k=2,distance=1) This predicts Bonds to have 80.2 runs. The Runs variable acts like a class label and if you call k$CL you'll get back 65 and 99 (the number of runs corresponding to the two nearest neighbors). There are two players (McGwire, Pujols) with 65 runs and one with 99, so you can't tell directly who the neighbors are. It appears that the output for kknn does not include a list of the neares

Categories : R

find and replace a word with another in all file names of a directory
Use find with the -exec option to call rename on every file and subdirectory containing "owner" in its name: find path/to/my/directory/ -depth -name "*owner*" -exec /usr/bin/rename owner user {} + If you don't have rename, you can use a mv command with bash parameter expansion: find path/to/my/directory/ -depth -name "*owner*" -exec bash -c 'mv "{}" $(old="{}"; new="${old##*/}"; echo "${old%/*}/${new/owner/user}")' ; bash -c '...' invokes the bash shell on the one-liner surrounded by single-quotes. The one-liner acts as a mv command that renames all occurrences of "owner" in the basename of the matching filename/subdirectory to "user". Specifically, find substitutes every {} after the -exec with the matching file/subdirectory's pathname. Here mv accepts two arguments; the first i

Categories : Linux

Linq to Find and eliminate duplicate file names
Use the GroupBy method: IEnumerable<FileData> dats = FastDirectoryEnumerator .EnumerateFiles(myDirectory.FullName, "*.zip", SearchOption.AllDirectories) .Where(f => f.Size / 1024 > 750) .Where(f => !f.Name.EndsWith(".reg.zip")) .Where(f => f.Name.StartsWith("2001")) .GroupBy(f => f.Name) .Select(g => g.First()); Or in query syntax: IEnumerable<FileData> dats = from f in FastDirectoryEnumerator.EnumerateFiles(…) where f.Size / 1024 > 750 && !f.Name.EndsWith(".reg.zip") && f.Name.StartsWith("2001") && group f by f.Name into g select g.First(); This will return the first FileData with each name. If you want to get just the unique Name values, it's actually a bit easier

Categories : C#

Find color names for colors close to colorBrewer palette
See if this is useful. (It's an LI distance on rgb space): col.dist <- function(inp, comp) sum( abs(inp - col2rgb(comp) ) ) colors()[ apply(col2rgb(brew10), 2, function(z) which.min( sapply(colors(), function(x) col.dist(inp=z, comp=x) ) ) ) ] #----------- [1] "paleturquoise3" "moccasin" "lightsteelblue" "salmon" [5] "lightskyblue3" "sandybrown" "darkolivegreen2" "thistle2" [9] "gray85" "orchid3" Looks like it might have succeeded looking at: display.brewer.pal(10,"Set3") (Although I have never see a thistle that color, and I would have thought number 7 to be more of a "lightolive" than a "darkolive".) You would proably get faster response, although this seemed acceptable, if you made the call to colors on

Categories : R

How To Pass Find results to CP such that File Names with Spaces work
Try this: find . -name *.pdf -print0 | xargs -0 -n 1 -Ifoo cp --parents foo /new_path/ Or find . -name *.pdf -exec cp --parents {} /new_path/ ;

Categories : Bash

How to find all the source lines containing desired table names from user_source by using 'regexp'
To find company as a "whole word" with a regular expression: SELECT * FROM user_source WHERE REGEXP_LIKE(text, '(^|s)company(s|$)', 'i'); The third argument of i makes the REGEXP_LIKE search case-insensitive. As far as ignoring the characters . ; , '' "", you can use REGEXP_REPLACE to suck them out of the string before doing the comparison: SELECT * FROM user_source WHERE REGEXP_LIKE(REGEXP_REPLACE(text, '[.;,''"]'), '(^|s)company(s|$)', 'i'); Addendum: The following query will also help locate table references. It won't give the source line, but it's a start: SELECT * FROM user_dependencies WHERE referenced_name = 'COMPANY' AND referenced_type = 'TABLE';

Categories : Regex

Need a sql query to find all 3 part names with spaces in 'customer info' table
SELECT * FROM CustomerInfo WHERE length(Custfullname) - length(replace(Custfullname, ' ', '')) >2 This is not perfect,it just selects the names where empty spaces are >2

Categories : Mysql

Find SQLite Column Names in Empty Table/View in an attached database
PRAGMA AttachedDbName.table_info(your_table_name) Another technique: prepare a statement of the form select * from your_table_name;, then use sqlite3_column_count, sqlite3_column_name et al. You don't need to actually run the statement, just prepare it.

Categories : C++

Can't find AD user using the command get-aduser when the user is an object
You can assign the username to a variable and use it in the query: $name = $arr[0].username $user = get-aduser -filter {Name -eq $name} or use an expanded string instead of a script block: $user = get-aduser -filter "Name -eq '$($arr[0].username)'"

Categories : Powershell

Find and return value
Sub changeString(sample As String) ' Find the location of the first # and remove that portion Dim charNum As Integer charNum = InStr(1, sample, "#") sample = Right(sample, Len(sample) - charNum ) ' Remove everything from the | till the end charNum = InStr(1, sample, "|") sample = Left(sample, charNum - 1) End Sub

Categories : Vba

Find-doc but only return function name
I think I found it, it's the show function in repl-utils

Categories : Clojure

find by method return value in rails?
def self.min_loan(val) where("loan > ?", val) end #assuming that loan is the column name Then call Application.min_loan(1000) It will return applications have min_loan = 1000

Categories : Ruby On Rails

C++: How to use new to find store for function return value?
In a "real" program, yes, you would use std::string. It sounds like this example wants you to use a C string instead. So maybe something like this: char * cat(char first[], char second[]) { char *result = new char[strlen(first) + strlen(second) + 1]; ... Q: How do you "append"? A: Just write everything in "first" to "result". As soon as you're done, then continue by writing everything in "second" to result (starting where you left off). When you're done, make sure to append '' at the end.

Categories : C++

How do I find out when the user is being followed by the map or not?
You could add a OnCameraChangeListener, it will get called if the map is dragged. In its onCameraChange compare the CameraPosition#target LatLng with MyLocation. Here are the camera change and my location listeners in the same API: https://developers.google.com/maps/documentation/android/reference/com/google/android/gms/maps/GoogleMap.OnCameraChangeListener https://developers.google.com/maps/documentation/android/reference/com/google/android/gms/maps/GoogleMap.OnMyLocationChangeListener

Categories : Android

How i can return specified fields in mongodb find() coursor?
The PHP function for find does not work like that. Try: find(array(), array('name'=>1)) (basically omit the surrounding array) For reference here is the documentation page: http://php.net/manual/en/mongocollection.find.php

Categories : PHP

Find and replace

with return key entry in MySQL

Given your example, the <p> elements are not necessary. They can just be replaced with : UPDATE yourTable SET theColumn = REPLACE(theColumn, '<p>', ' ')

Categories : Mysql

Find a string as value in a dictionary of dictionaries and return its key
You created a list of only the dictionary values, but then try to loop over it as if it already contains both keys and values of those dictionaries. Perhaps you wanted to loop over each matched dictionary? l = [v for v in dictionary.values() if ":" in str(v)] d = defaultdict(list) for subdict in l: for k, v in subdict.items(): I'd instead flatten the structure: def flatten(dictionary): for key, value in dictionary.iteritems(): if isinstance(value, dict): # recurse for res in flatten(value): yield res else: yield key, value then just search: def GetKeyFromDictByValue(self, dictionary, value_to_find): for key, value in flatten(dictionary): if value == value_to_find: return key Demo:

Categories : Python

vlookup to find match and return another element in row
Modify and put this formula into the first cell of the second column on the first worksheet. Then copy and paste it down the column: =VLOOKUP(A1, Sheet2!A$1:B$100, 2, FALSE) Let's look at the parameters for this function: A1: This value, on this worksheet, is what we're searching for in the range given in the next parameter. When you copy and paste the entire formula down the column, it increments the row # with each row. In row 2, it will be modified to A2, and so on. Sheet2!A$1:B$100 : This is the range that we are interested in, on the second worksheet. It is the top left to bottom right cell. The $ symbol tells Excel not to change the row #'s when you copy and paste the formula down the column. Modify B$100 to fit the range of data you are interested in... something like B$30 if yo

Categories : Misc

Python - Find value anywhere within JSON and return location
If I understand well, each dictionary has the following structure: {"code": # some int "name": # some str none / "country" / "place" / whatever # some dict or list You can write a recursive function that handle one and only one dict: def foo(my_dict): if my_dict['code'] == root['place']: city = my_dict['name'] elif "country" in my_dict: city = foo(my_dict['country']) elif "place" in my_dict: # # and so on... else: city = None return city Hope this example will help you.

Categories : Python

Matcher.find() return false android
As commented by somebody else, I would usually use an html parser for extracting stuff from html. However, in your case where you're just pulling a single bit of information out of a string I can see why you want to use a regex. What you need to do is something like this - the issue with your regex was an extra d. Also if you enclose the bit you care about in parenthesis you can grab it using .group. import java.util.regex.*; public class R { public static void main(String[] args){ String Html = "<div class="title">Current Version</div> <div class="content" itemprop="softwareVersion"> 1.1.3 </div> </div> <div class="meta-info"> <div class="title">Requires Android</div> <div class="content" itemprop="operatingSystems"> 2.

Categories : Java

Regex to find pattern, return subpattern
You need to escape first set of parentheses as s.match( /url(([^)]+))/g ); Please, note that ok and oh ya would be part of the capturing groups instead of matches directly. You can retrieve the capturing groups as: var str = "lala url(ok) tee hee url( oh ya ) kk", re = /(([^)]+))/g, match ; while( (match = re.exec( str )) !== null ) console.log( match[0] + " : " + match[1] ); /* Prints: url(ok) : ok url( oh ya ) : oh ya */

Categories : Javascript

How can I find out what's changing the return address of a function in c++
The short answer is: The most portable way of determining if a floating-point exceptional condition has occurred is to use the floating-point exception facilities provided by C in fenv.h. although, unfortunately, this is far from being perfect. I suggest you to read both https://www.securecoding.cert.org/confluence/display/seccode/FLP04-C.+Check+floating-point+inputs+for+exceptional+values and https://www.securecoding.cert.org/confluence/display/seccode/FLP03-C.+Detect+and+handle+floating-point+errors which concisely address the exact question you are posing: Is there a method for checking problems like rounding errors automatically.

Categories : C++

Find and return an element from a TreeSet in Java
Class NodeSet { Set<Node> set = new TreeSet<Node>(); public Node findNode(int id) { Iterator<Node> iterator = set.iterator(); while(iterator.hasNext()) { Node node = iterator.next(); if(node.getId() == id) return node; } return null; } }

Categories : Java

how to return unique value and also find duplicate values? SQL
I'm not entirely sure if this is what you want, but it sounds like maybe? select min(t2.order_no), t2.field1, t2.field2, t2.field3, t1.cnt from table_name t2, ( select field1,field2,field3, count(*) from table_name group by field1,field2,field3 having count(*) > 1 ) t1 where t1.field1 = t2.field1 and t1.field2 = t2.field2 and t1.field3 = t2.field3 group by t2.field1, t2.field2, t2.field3, t1.cnt For each record returned in your deduplicating subquery, the outer query will attach to that record the smallest "order number" that matches the given combination of fields. If this isn't what you're looking for, please clarify. Some sample data and sample output would be helpful. EDIT: From your posted sample data, it looks like you're looking to just retur

Categories : SQL

How to find installed user of msi?
(If you have a sid, you can find out the user name, why not?) But the best way, if the msi is yours, is to save that information during the setup in a registry value, or .ini file you can read out later. There are two properties, "LogonUser", and "USERNAME", the latter is the user really installing. If you have no influence on the msi itself, I am not sure, if it is so easy. Interpreting sids seems a good way then. Nevertheless: The standard way is to use the API routines MsiGetProductInfo() or MsiGetProductInfoEx(). You can google in MSDN. But I am not sure if they always contain information if these data were not registered during setup dialog. So maybe they are empty after a silent install if there was no registration dialog? I have never used them to find the user who has installed

Categories : Wix

Find out the last page the user was on
request.referer will give you the url which issued the request. If you need more informations like the path, you can use URI and write in your controller something like: last_page_path = URI(request.referer).path

Categories : Ruby On Rails

JS - Can't find user location
The result that you are getting is not city id + city name, its a JSON. Read more about JSON. Suppose your result is: var result = FB.api('/me?fields=location'); then you can acces the city name with - var city_name = result.location.name;

Categories : Javascript

How can I find out the name of the user when in a ASP.Net Web API Controller?
Since you are using Forms Authentication you can try use the HttpContext class and the Identity property: var currentUser = HttpContext.User.Identity;

Categories : C#

Best way to find out if user is already registered
You can optimize your query.You can maintain a unique username(or your unique parameter) for user and when someone trying to register,You can pass that usename to query and check it is already registered or not

Categories : Java

Find out if a user has like a page
Page is passed only on facebok pages (if application is configured and added as a Tab to fanpage), not in apps.facebook.com (canvas) nor any your domain. On other hand i am using on apps per user (it changed recently so it may be outdated) // scope for user // $facebook <- assuming this is facebook sdk object // $params = array( // 'scope' => 'user_likes' <- to get likes we have to require this //); function fanGate() { $likes = null; try { $likes = $facebook->api('/me/likes'); } catch (Exception $e) {} $likeUs = false; if ($likes) foreach ($likes['data'] as $like) { if ($like['id'] == 'some id of page') $likeUs = true; } return $likeUs; } edit According to documentation to check if user likes

Categories : PHP



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