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jQuery $.post function failing
It looks like you're binding an event handler to a form submit button. The problem appears that the form is being submitted before $.post has a chance to handle the response. What you want to do is prevent the form from submitting. Try this: $('#sui').submit(function (e) { // added 'e' to catch the jQuery event e.preventDefault(); /* prevent the default action from happening, in this case submitting the form */ var email = $('#email').val(); var password = $('#password').val(); $.post('sign_in.php', { email: email, password: password }, function(data) { alert ('hi'); // never shows up alert (data); // never shows up $('#errors').text(data); }); }); As an aside, I

Categories : Jquery

Post Function in jQuery is not working
The ajax call is asynchronous. You should put the function refreshPage inside the success or complete function. This way the refreshPage function will be called right after the ajax call is finished and the page is ready to be refreshed with the new data. Extracted from jQuery api: Description: Perform an asynchronous HTTP (Ajax) request.

Categories : Asp Net Mvc

jQuery .post() function not working
check this $.post('addFolder.php', data); //data replace $data like => $.post('addFolder.php', $data); so now $("#addFolder").click(function(){ $(".folders").append("<p class='folder'>This is first folder<input type='checkbox' name='checkFolder'></p>"); $data = {'id':document.getElementById('id').value, 'text':document.getElementById('text').value}; $.post('addFolder.php', $data); });

Categories : PHP

JQuery ajax post function not working
I think this: .post("response.php",data1+"&"+data2,function(data){ Should be: $.post("response.php",data1+"&"+data2,function(data){

Categories : Javascript

Output from Ajax $.post() function jquery
}else{ $('body,html').animate({scrollTop: 20}, 800); $('#error').html(output); }); } should be: }else{ $('body,html').animate({scrollTop: 20}, 800); $('#error').html(output); } return false; }); or something like that, I am pretty sure the }); in the else is wrong.

Categories : Javascript

wordpress wp_mail() function with jquery $.post()
You should use the wordpress ajax hook in order to get wordpress classes. http://codex.wordpress.org/Plugin_API/Action_Reference/wp_ajax_(action) I would recommend cleaning the code a bit and adding a Nonce check, but your code should look something like this: js: jQuery.post( MyAjax.ajaxurl, { 'action': 'send_message', 'name':'name', 'email':'email', 'message':'message' }, function(response){ alert('The server responded: ' + response); } ); php: add_action( 'wp_ajax_send_message', 'do_send_message' ); function do_send_message() { if ( isset($_POST['name']) && isset($_POST['email']) &&isset($_POST['message']) ) { $name = $_POST['name']; $email = $_POST['email']; $message = $_POST['message'];

Categories : Jquery

Rails , Ajax , Post Function , Jquery
Try: $('form').submit(function() { var myForm = $('form').serialize(); $.ajax ({ url:'/comments/create', type:"POST", dataType:'json', data: myForm, processData:false, success: function (msg) { alert(msg); }, error: function (xhr, status) { alert(xhr.error); } }); }); If this doesn't work, please write what you're sending across the wire in your AJAX request. Use Chrome Console or Firebug to check and paste the POST results in here.

Categories : Ruby On Rails

Calling a function until jQuery .post finishes loading
Just call the addClass before the $.post() and be done with it $(".elmt").addClass("loading"); $.post("verify.php", { username: u, password: p }, function (r) { location.href = 'http://localhost'; });

Categories : Javascript

ajax search function using POST method without jquery
fist of all you pass this and not this.value then a short function i use for ajax is this var ajax=function(a,b,c){c=new XMLHttpRequest;c.open('GET',a);c.onload=b;c.send()} this has low support (no ie5 and ie6) but can be extended. then as u lauche the code directly from your element you can access your value directly inside the ajax. so: JS FormData() stores the whole content of your form the ajax() function posts to film.php in film.php u can retrieve the value with $_POST['zoekparameter'] the response executes fu() this is done by adding a eventListener in javascript to the input field which is keyup. var ajax=function(){ var fd=new FormData(document.querySelector('#form')); var c=new XMLHttpRequest||new ActiveXObject("Microsoft.XMLHTTP"); c.open('POST','film.php'); c.

Categories : PHP

Any idea for send POST for a function (url) via jquery-fancybox?
I'm solved the problem! I inserted a ajax request after opening fancybox. $(function() { $("*").on("click", ".fancypdf", function() { var data = $("form").serialize(); var url = this.value; console.log("Button=" + url); console.log("Data=" + data); $.fancybox({ type: 'ajax', autoSize: false, content: '<embed src="' + url + '#nameddest=self&page=1&view=FitH,0&zoom=80,0,0" type="application/pdf" height="99%" width="100%" />', beforeClose: function() { $(".fancybox-inner").unwrap(); } }); //fancybox $.ajax({ type: "POST", cache: false, url: url, data: data, success: function(d

Categories : PHP

Post value through load Jquery function that not visible in source?
if your conducting client server communication the traffic is always visible to the client side, no matter what you do. if you want security then you are to encode your client communication portion in some form of a binary code and then encrypt it some how. Which is still possible to be reversed. Having said all that you should use session to maintain the data you don't want the client to see

Categories : PHP

jQuery $.post function not hitting the server? failed error response
You are hitting the same-origin policy which means that you whilst you can make AJAX requests to another domain, you cannot read the response (that is why you callbacks are not firing). The solution here is to use either CORS (adding extra headers to your HTTP responses on the server side) or JSONP (making a custom response with a JSONP callback). I'd advice you to use CORS as it provides better error handling, whilst JSONP is more of a hack. If you want to use CORS, add the described headers in Wikipedia article to responses that must be cross-domain. You asked for an example of the solution, but the solution must be implemented on the server side for both JSONP and CORS.

Categories : Jquery

Using onblur jquery function to check validation data after submit POST?
You should try this <input id="createuser" type="submit" value="Đăng ký tài khoản" onclick="return myValidationFunction();" /> Return false if validation fails! The return false should stop the default submit behaviour

Categories : Jquery

Using one delete function for a post jquery request of php request
I think that you should have two functions in PHP: public function delete($content_page_id) { // Your delete code return "a string without format"; } public function deleteAjax($content_page_id) { return json_encode($this->delete($content_page_id)); } So, when the user has JS enabled, you call deleteAjax passing a parameter in your $.post function to let PHP know that JS is enabled: $.post(<?php echo current_url(); ?>'delete', { item_id : item_id, js: 1 }, function(data) { if (data.success) { var anSelected = fnGetSelected( oTable ); oTable.fnDeleteRow( anSelected[0] ); } }, 'json'); And if JS is disabled, call the other function. You should use an AJAX specialized controller instead a function in the same class.

Categories : PHP

jQuery post request interrupted: Only half of post parameters arrive
In order to find our more about what is happening, why not properly code you ajax request using jQuery's ajax function. Use all the callback functions to track what happened to your call or what came back? The element type is set to POST and the element data carries whatever object structure { ... } you like. $.ajax({ url : "save.php", type : "POST", data : { "ajax_call" : "SOME_CUSTOM_AJAX_REQUEST_REFERENCE", "data1" : data1, "data2" : data2, "data2" : data2, "dataN" : dataN }, //dataType : "html", contentType: "text/html; charset=utf-8", dataType : "json", contentType: "application/json; charset=utf-8", beforeSend: function () { //alert('before send...'); }, dataFilter: function () { //alert('dat

Categories : PHP

post and trigger a php file in server using jquery ajax post method
Try this it is working $.ajax({ type: "POST", url: "http://localhost/export/some.php", data: { dataString: "hi" }, cache: false, success: function(data){ alert(data); this.openDestinationURL(); } }); here is the php file <?php header('Content-Type: application/excel'); header('Content-Disposition: attachment; filename="sample.csv"'); $data =$_POST["dataString"]; $fp = fopen('php://output', 'w');//set the path fputcsv($fp, $data); fclose($fp); ?>

Categories : PHP

jQuery.post: I can't post more than one time unless I refresh the page
Try using the syntax like this : $("#fix<?php echo $error['id'] ?>").live('click',function(){ ..... }); $("#unfix<?php echo $error['id'] ?>").live('click',function(){ ..... }); Because when you click for the first time, you are replacing the html code dynamically, so for the next time, when you click that dynamically generated html code will not be noticed, so you have to use .live function. REFER

Categories : Javascript

JQuery $.post, PHP returns blank POST variables
You did not even call the function checkForm() method so I am not sure how your code works but I used $(document).ready(function() The following is the script: $(document).ready(function() { $("#rchar").submit(function(event){ alert("hahahaha"); var request; // abort any pending request if (request) { request.abort(); } // setup some local variables var $form = $(this); // let's select and cache all the fields var $inputs = $form.find("input, select, button, textarea"); // serialize the data in the form var serializedData = $form.serialize(); // fire off the request to /form.php request = $.ajax({ url: 'postregister.php', type: "POST", data:

Categories : PHP

$.post() Jquery post not working with a new array() to PHP
Your var arr should be an Object not an Array. Try something like: var data = { script: scrip, account: "max@hotmail.com", accounttag: "TH" } if (follow != "") data.followtag = follow; if (join != null) data.join = join; $.post("test.php", data); See http://api.jquery.com/jQuery.post/ for explanation of $.post.

Categories : PHP

post is not taking params with it. JQuery post
Ignore this answer It just reflects the question not having all the parameers shown as the code was pared down for SO. The only reason I didn't delete it is that the comments seemed interesting at the time. Perhaps you need to put more parameters in the post: $.post("humanResourceFunctions.php/", { command:"changePermissionStatus", empId: empId, ... all the others }, function(data, status){ alert(data); } );

Categories : Jquery

jQuery errors "x.ready.promise is not a function" and "Modernizr.prefixed is not a function" / jQuery.noConflict
replace $ with jQuery if you have small amout of scripts.. or wrap them in: (function ($, window, document) { //code }(jQuery, window, document)); or jQuery(document).ready(function() { //code }); or (function(window, undefined) { 'use strict'; //code })(this);

Categories : Jquery

Jquery post not working , send multiple selected checkbox through jquery to php script
This is how your form should look. <form id="my_form"> <input type="checkbox" name="items[]" value="1" /> <input type="checkbox" name="items[]" value="22" /> <input type="checkbox" name="items[]" value="321" /> </form> Then in your php, you can iterate through all the $_POST['items'] If you want to use jQuery to post, you can use this, but is not necessary as you can add a method and action to the html in your form: $('#senditems').on('click', function(){ var form_data = $('#my_form').serialize(); $.post({ url: "your_php.php", data: form_data }); });

Categories : PHP

how to bind a jquery event handler on a jquery post returned data
Probably the reason is that you are using .bind or simple .change method, for elements that do not exist yet on page (appended only after ajax call). You should use .on method with delegated events approach (or for jquery 1.7 and older you may use .live method ) $("#container_div").on("click", "#list_id li", function(event){ //list element clicked });

Categories : Jquery

PHP Using Get Post in WHERE function
Right now, query compares field to the actual string 'formdata'. You'll want to grab the formdata, if you're POSTing, like this: $result = mysqli_query($con, "SELECT * FROM table WHERE field = '" . $_POST['formdata'] . "'"); Although, note that you'll need to use prepared statements to make this secure. See here and here.

Categories : PHP

Add post->ID into wordpress function?
It was impossible to use post->ID inside my function, but inside my form I could echo the post->ID because it's inside a metabox on the post. Inputs are great for storing data. <div class="post-id"> <input type="text" name="thepostid" value="<?php echo the_ID() ?>" id="someid"> </div> I use jQuery and ajax to take the data, here is a snippet. jQuery('.post-id input').each(function() { // Save original name attr to element's data jQuery(this).data('name', jQuery(this).attr('name') ); jQuery(this).attr('name', 'brash-post-id[postid]['+jQuery(this).attr('name')+']'); }); A snippet of adding it to ajax. // Data to send $data = $data.add( jQuery('.post-id').find('input') ); // Post layer

Categories : PHP

How to post in jQuery?
$(function () { $(".button_post").click(function () { var text_t = $(".Textarea").val(); // text_t has to be in the click function it order for it to update with the new content when you click post (otherwise it will be empty like the textbox was when the page loaded) $(".comment_list").text(text_t); // li does not have a value, use html() or text() }); }); FIDDLE More details $(function(){ var text_t=$(".Textarea").val(); First of all doing the above will load the value of the textbox when the document is ready, thus text_t will be empty in your case (the textbox has no value when the page loads) $(".button_post").click(function(){ $(".comment_list").val(text_t); }); The second problem comes here, li does not have a value attribute so you can

Categories : Jquery

JQuery Post URL
I normally leave the routing as a default and change the controller in the jQuery call. Routing Code routes.MapRoute( "Default", // Route name "{controller}/{action}/{id}", // URL with parameters new { controller = "Home", action = "Index", id = UrlParameter.Optional } // Parameter defaults ); jQuery Code $.ajax({ type: 'GET', dataType: 'json', timeout: 300000, //5 minutes (in milliseconds) url: '/YourApplicationName/YourContollerName/YourMethodName', //...

Categories : Jquery

What is the jquery post url?
NodeJS will run as a web server with its own url. When you launch the server you must specify a url . I guess most of the examples use some localhost address with a port. You can then post to that address. It should not be a php address unless you go via a php page on your own web server

Categories : Javascript

jquery .post() is sent as .get()
GET is the default way to send a form, and your form is probably submitted the regular way and not with javascript as there are syntax errors, and if the form is inserted dynamically you'll need delegated event handlers: $('#target').on('submit', '#JqPostForm', function (e) { e.preventDefault(); $("#despliegaresultados, #paginacion").empty(); $.post("php/prueba.php", $('#JqPostForm').serialize(), function (data) { $.each(data, function (i, item) { // NOTE: Ajax is async, the below values are only accessible // after the ajax call has completed var total = item.total, datos = item.datos; }); }, "json"); });

Categories : Jquery

Run javascript function then post for download
You could go for window.location.href in your success function: $.ajax({ type: "POST", dataType: "json", url: "exportLeads.php", data: { 'idArray' : ids }, success: function(data) { if (data.success) window.location.href = "/link-to-your-download-script"; } }); You would have to change the response to json_encode and split the functionality into two scripts, one for the export and one for the download script (with a unique id or sth.)

Categories : PHP

Javascript function after Http post
I think, Iframe will not work for parent window Replace the line <iframe width="100%" height="300" src="file2.php"></iframe> by include_once("file2.php"); Above will work for you.

Categories : PHP

.click function with an Ajax post
Simply use .on(): $(document).on("click", ".add_button", function(){ // your event code }); When your js runs a click event is attached to all current elements with the .add_button class. However, you're adding extra buttons via ajax and these won't have trigger the same click event. To fix this use the code above. It attaches the event to the document so even if you add buttons once the page has loaded the click event will be triggered by them.

Categories : PHP

How to append always a value to when a jquery post happens?
try with $.ajaxSetup: $.ajaxSetup({ data: { "abc": new Date() //this will be set in every ajax request } }); and then use $.ajax(): $.ajax({ type: "POST", data: {.. your other data here }, url: "some url", success: function( respo ) { ... } }); you will get abc as added in ajaxSetup in your POST data, along with your other data

Categories : Jquery

jQuery $.post() and PHP issue
You are confusing server side code and client side code. PHP executes on the server, meaning that any links to resources should be file paths to where the actual files on the server are located. Javascript/JQuery is client side code, meaning that it runs in the user's browser, so any links should be urls not file paths. Instead of using a local file path on the server like you are now with: $.post('./php/show_client.php' ... Your url passed to $.post() should be a URL which accesses that PHP script. $.post('mysite.com/directory/show_client.php' ...

Categories : PHP

jQuery .post() not executing
To troubleshoot and isolate the problem, you need to determine if this is a backend or a frontend problem. Backend Check Try using something like Postman to hit the endpoint directly with the data that should be posted. If you never get that console.log to execute then you may have some problems with your routes. Frontend Check If that works, then look at the Network tab of your Dev Tools in Chrome and make sure that the request looks the same as the one you make in Postman.

Categories : Javascript

why is jquery not passing a post value
You have invalid HTML in the input tag. (It's missing an = sign.) <input type="text" id="calDate" size="15" name"calDate"/> should be: <input type="text" id="calDate" size="15" name="calDate"/> So your JS is setting the value since you're using the ID, but the name is what is used for posting a form, which is why it is empty.

Categories : PHP

jQuery post button name
You should try the following <form action="<?=$_SERVER['PHP_SELF']?>" method="post" id="IDD"> <input type="email" name="user_email" /> <input type="submit" name="login" id="loginButton" value="login"/> </form> The problem is, form doesn't send values of input type button. You should set it's type to submit if you want to receive its value on server. Note: if there are more than one submit buttons in your form, you'll only get the value of the button that was clicked. Update: You can use jQuery like below $("#loginButton").click(function (evt) { if (!conditonMeets) { // check what ever condition you have here return false; // this will stop form from submitting } }); Note: I have assigned an Id to Login button

Categories : Jquery

about jquery post method
$.post doesn't return a boolean value, so the result (a jqXHR object) will be converted to a boolean and be true, and thus the form will submit every time. Update: Since the submit() method will trigger the onsubmit event even when it's invoked manually, you'll need to store the successful results from the $.post and add a condition in check_username(). One of many possible ways to accomplish this: <form action="register/sumbit" method="post" onsubmit="return check_username()"> ... </form> var isUsernameValid = false; function check_username() { if(isUsernameValid){ return true; }else{ $.post(url, data, successHandler); return false; } } ... // in your $.post().done() handler... if(data=="true"){ //username doesn't exist

Categories : Ajax

JQuery Post - Why I can't see response?
You're not selecting your #result div properly, add a # before $("#result").html(data); the same goes for all your selectors var title = $("#title").val(); var content = $("#content").val(); Since your ajaxing your form you'll have to manually pass your button parameter, although an ajax parameter would be more appropriate. data: { title: title, content: content, gonderBtn: 'gonderBtn' },

Categories : PHP

jQuery/PHP Post Failure
The .load() method does not do what you think it does. Your question states getCalls.php does a select from SQL database -- but this won't happen if you use the jQuery .load() method, it will only work if you use AJAX. This is because the server must run the PHP, while .load() runs at the browser. The only way for the browser to request that PHP be executed (and data returned) is via AJAX. I suspect what you really want to do is to use AJAX, like this: function getCalls(){ $.ajax(function() { type: "POST", url: 'getCalls.php', success: function(recd_data) { $('#transportDiv').html( recd_data ); } }); } Please see the links at bottom of this SO post for more AJAX examples. Update: Restructured AJAX code for test discussed in com

Categories : PHP



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