I would use a different approach using fabric, which is a great tool for executing remote commands. from fabric.api import run, env env.host_string = 'example.org' output = run('find /tmp -type f | wc -l') num_files = int(output) Now you have the number of files in your variable num_files. I was just using the find command to search for files recursively beginning at directory /tmp, and counted the returned lines with wc -l.

What you want is a suffix tree. This stores all suffixes of a (set of) strings in a trie (in your case, the set of words). Each leaf of the trie is associated with the the set of strings that have that suffix. When searching for a substring, you simply match the substring at the root of trie; your substring must a prefix of some suffix or there is no match. Discovering the existence of a match is linear time in the length of the substring. To determine all matching words, you have to enumerate all leaves of the trie accessible from the point where the match completes. That is a tree walk problem; if the tree has significant branching, it might be bit expensive. You could precompute, for each trie node, the set of associated words; this is likely to be pretty big, but now you have an

Do you really need to sort and all? If you need to delete files which are more than 7 days old, get the lastModifieddate and substract it from current time. if the difference is more than 7*24*60*60 seconds then you can delete it. All you need is a for loop after the f.listFiles() line. Not actual code - use to get to the working code. long timeInEpoch = System.currentTimeMillis(); // slightly faster than new Date().getTimeInMillis(); File f = new File("/tmp"); if (f.isDirectory()) { final File[] files = f.listFiles(); for(int i =0; i < files.length ; i++ ) { if( timeInEpoch - f.lastModifiedDate() > 1000*60*60*24*7 ) files[i].delete(); } System.out.println(fileList); }

Not a optimized one but you can use. String[] extensions = {"zip","rar"}; Collection<File> fileList = listFiles(FilePath2,extensions,false); File[] fileArray = new File[fileList.size()]; int x = 0; for (Iterator iterator = fileList.iterator(); iterator.hasNext();) { fileArray[x] = (File) iterator.next(); x++; } File temp; for(int i=1; i< fileArray.length ; i++) { for(int j=0; j<fileArray.length-1; j++) { if(fileArray[j].lastModified() > fileArray[j+1].lastModified()) { temp = fileArray [j]; fileArray [j] = fileArray [j+1]; fileArray [j+1] = temp; } } } for(int i=0; i< fileArray.length-2 ; i++) { deleteQuietly(file

for the second NP_len_*.fa pattern the regex can be like .+NP_len_d{1,3}.fa and for the first one where you do not want the N us this .+?[^N]P_len_d{1,3}.fa this one will match all patterns just except N before P. I have considered that folder names might grow in future about you xaa part. you can alternatively match for string of length 3 also.

you need to do deep cloning, A simple way is to serialize the vector and desalinize it again. You will get the expected result. Note: Objects in the vector should be serializable (or) create a new vector, Then iterate over the existing vector and colne each object in the vector and add to new it to new vector

In recent versions of rsync, you can use the -F option and put a file ".rsync-filter" in the directory src, containing: - dir1/*** That seemed to work for me. I'm assuming that your hierarchy above is all under "src/".

WPF does not have the native capability to disable the Maximize button alone, as you can do with WinForms. You will need to resort to a WinAPI call. It's not scary: [DllImport("user32.dll")] private static extern int GetWindowLong(IntPtr hWnd, int nIndex); [DllImport("user32.dll")] private static extern int SetWindowLong(IntPtr hWnd, int nIndex, int dwNewLong); private const int GWL_STYLE = -16; private const int WS_MAXIMIZEBOX = 0x10000; private void Window_SourceInitialized(object sender, EventArgs e) { var hwnd = new WindowInteropHelper((Window)sender).Handle; var value = GetWindowLong(hwnd, GWL_STYLE); SetWindowLong(hwnd, GWL_STYLE, (int)(value & ~WS_MAXIMIZEBOX)); }

I think that -eq and -ne match the given string and don't support wildcards. Only -like supports wildcards for pattern matching. You can however use a regular expression with the -notmatch switch to achieve what you want. Since it's a regular expression now you need to use .* instead of *. And the beginning is marked with ^. So you end with this {$_.Name -notmatch "^reports.*|^category.*"} The whole command Get-Item -Path ($AppDir + "reports*.dbf") | Where-Object {$_.Name -notmatch "^reports.*|^category.*"}

Based on my solution, I am just posting the code so that it might be useful for some one looking for same scenario : /** * Delete keys/objects from buckets with matching prefix * @param bucket * Bucket in which delete operation is performed * @param prefix * String to match the pattern on keys. * @return */ @Override public void deleteFilesInS3(String bucket, String prefix) throws IOException { try{ List<KeyVersion> keys = listAllKeysWithPrefix(bucket, prefix); DeleteObjectsRequest multiObjectDeleteRequest = new DeleteObjectsRequest(bucket); multiObjectDeleteRequest.setKeys(keys); s3EncryptionClient.deleteObjects(multiObjectDeleteRequest); }catch(MultiObjectDeleteException e){

Further investigation has revealed that this was not a reflection or assembly loading problem. The problems I was experiencing was due to build issues inside the assemblies I was reflecting on. The errors were obscure and it made the problem look like something it wasn't. Thanks to SWeko for noting to look into the inner exceptions. That comment helped a lot!!

This is where find in combination with xargs will help. find /path/to/files -name "pattern*" -print0 | xargs -0 ls Note from comments: xargs will help if you wish to do with the list once you have obtained it from find. If you only intend to list the files, then find should suffice. However, if you wish to copy, delete or perform any action on the list, then using xargs instead of -exec will help.

You can use the maven-resource-plugin for such purposes like this: <project> ... <build> <plugins> <plugin> <artifactId>maven-resources-plugin</artifactId> <version>2.6</version> <executions> <execution> <id>copy-resources</id> <!-- here the phase you need --> <phase>validate</phase> <goals> <goal>copy-resources</goal> </goals> <configuration> <outputDirectory>${basedir}/target/extra-resources</outputDirectory> <resources> <resource> <directo

From the UNIX philosophy: Write programs that do one thing and do it well. Write programs to work together. I don't like the GNU extension for recursive directory searching. The tool find does a much better job, has a cleaner syntax with more options and doesn't break the philosophy! $ find foo/*/VIEW -name "*.groovy" -exec grep method {} ;

If this is really an issue ( with tens of thousands of filenames to search, and thousands of different searches to be done ) then the simplest ( without writing huge amounts of code ) might be to cache the filenames in a indexed database table and then use SQL to do the count. After the work of copying the filenames to the database and indexing the table, any decent SQL engine should do an excellent job on each individual search - I would use SQLite myself. The snag will be keeping the cache up to date. How much this is a pain will depend on exactly what your attempting to do.

Maven uses different folders for source and other files (so called ressources). From srcmainjava it compiles all .java files and packages the resulting .class files into the jar. All other files in that directory are getting ignored to my knowledge. Now if you want other files to be packaged too, put them in srcmain esources instead. EDIT To manually specify a resource directory add <resources> <resource> <directory>D:Windchill_MarketERP ConnectorSourceCodeBuildsrc1srcmain esource</directory> </resource> </resources> to your <build> section

try this @XmlAccessorType(XmlAccessType.NONE) public class B { @XmlElement private String aString;// you don't need to create the class A (aString is like bString lement) @XmlElement private String bString;

I'm not sure but maybe problem is that the destination path (rajeesh@10.0.2.2:backup/) is not absolute? Also if you what to sync your files in the same device, maybe you should try to not use ssh? And do something like that: rsync -rvz /mnt/sdcard/some_directory /backup

Set the flatten property to false. There is a clear explanation on the grunt copy github readme https://github.com/gruntjs/grunt-contrib-copy Excerpt: $ grunt copy Running "copy:main" (copy) task Created 1 directories, copied 1 files Done, without errors. $ tree -I node_modules . ├── Gruntfile.js ├── dest │ └── src │ ├── a │ └── subdir └── src ├── a └── subdir └── b 5 directories, 4 files Flattening the filepath output: copy: { main: { expand: true, cwd: 'src/', src: '**', dest: 'dest/', flatten: true, filter: 'isFile', }, }, $ grunt copy Running "copy:main" (copy) task Copied 2 files Done, without errors. $ tree -I node_modules . ├── Gruntfile.js ├──

That would be os.path.relpath(): >>> import os >>> filename = "C:/test/media/blog_images/2013/06/15/yay.gif" >>> blog_images = "C:/test/media/blog_images/" >>> os.path.relpath(filename, blog_images) '2013\06\15\yay.gif'

This should do the trick: [UIImage imageNamed:@"someImageName"]; EDIT: Some additional information: -imageNamed: will look through the entire main bundle of the application for an imagefile (preferrably an png) with the filename of "someImageName". You need not worry about its location or its extension, since it will be searched for in the mainbundle. Files that you import through the import-file-dialogue in xcode will be added to he main bundle. This means: If i have imported a file called myImage.png, calling [UIImage imageNamed:@"myImage"];from anywhere in my code will get me a UIImage-Object containing that image. Its amazingly simple, and maybe that startled you a bit ;) Look it up in the docs if you like: http://developer.apple.com/library/ios/#documentation/UIKit/Reference/UIIm

From the documentation: Use this property to construct a URL relative to the application root from a page or Web user control that is not in the root directory. So ApplicationPath gives you relative path, and you're treating it as an absolute path. With your current approach you could be interested with HttpRequest.PhysicalApplicationPath, but I'm not sure if this is sound. Also, consider using Path.Combine instead of concatenating strings yourself.

This can be done just using Copy-Item. No need to use Get-Childitem. I think you are just overthinking it. Copy-Item -Path C:MyFolder -Destination \ServerMyFolder -recurse -Force I just tested it and it worked for me.

Personally I wouldn't bother using grep, I'd simply use Python's own string filtering - however, that wasn't the question you asked. Since the filenames are remote and Python sees them as simply strings then we can't use any of Python's own file manipulation routines (e.g. os.path.isdir()). So, I think you have three basic approaches: Split each string by slashes and use this to build your own representation of the filesystem tree in memory. Then, do a pass through the tree and only display leaf nodes (i.e. files). If you can assume that files within a directory are always listed immediately after that directory, then you can do a quick check against the previous entries to see if this entry is a file within one of those directories. Use meta-information from rsync. I would suggest th

You can do this with awk, but there is simple grep solution: grep -f terms.txt directory/*xml -o

It depends on the complexity of your project, but the general approach is to put the abstractions in its own library, then reference it from your web project. The implementation classes you can place again in its own library. So the web project would not have a direct dependency on them

How about something like rsync -azrR --include='*.log' -f 'hide,! */' /media/primary /backup If you use man rsync and type 2343g it should take you to the line where it explains this filter. Basically it will hide everything that's not a directory (every file) from the pattern matching; however, since I've used the --include='*.log' flag as well it will override that and the pattern will match only .log files. You can also use the -nv flag to do a dry run and see what would happen.

Directly from the man page (http://linux.die.net/man/1/rsync): "Rsync finds files that need to be transferred using a lqquick checkrq algorithm (by default) that looks for files that have changed in size or in last-modified time. Any changes in the other preserved attributes (as requested by options) are made on the destination file directly when the quick check indicates that the file's data does not need to be updated."

For validation: If you want to check if all files were copied, you can do a simple glob or list for list of files in the remote dir. Then compare to the glob list of files in the target dir. set globResult [ exec rsh -l $user $host "cd $dir; ls -l | wc -l" ] Or if you go further, you can always checksum on both the remote and the target directory. As for the reason for failure, it could've been network or server issues. While you are doing rsync, have you check the return exit status to make sure rsync has completed successfully?

You dont't need to read a list from a file. You could simply try this in command prompt: xcopy "full path to your folder" "full path destination folder" /e Below is what you get if you type xcopy /? in command prompt: Copies files and directory trees. XCOPY source [destination] [/A | /M] [/D[:date]] [/P] [/S [/E]] [/V] [/W] [/C] [/I] [/Q] [/F] [/L] [/G] [/H] [/R] [/T] [/U] [/K] [/N] [/O] [/X] [/Y] [/-Y] [/Z] [/EXCLUDE:file1[+file2][+file3]...] source Specifies the file(s) to copy. destination Specifies the location and/or name of new files. /A Copies only files with the archive attribute set, doesn't change the attribute. /M Copies only files with the arc

You can customize this in the thrift file by using the namespace function: namespace java com.example.plot.gen namespace rb foo Now for files for Ruby will be in: - (out directory) -foo - my generated files

@echo off set "COPY_FROM=C:UsersmeDesktopDisc 1" set "COPY_TO=C:Testing est" md "%copy_to%" 2>nul cd /d "%COPY_FROM%" for /f "delims=" %%a in ('dir /b /s /a-d') do copy "%%a" "%COPY_TO%" pause

An alternative approach you may want to use to secure your list of thumbnails: $directory = 'thumb'; //where the gallery thumbnail images are located $files = glob($directory."/*.{jpg,jpeg,gif,png}", GLOB_BRACE); natsort($files); //sort by filename Then to render it out simply do this: <?php for($x = 0; $x < count($files); $x++): $thumb = $files[$x]; $file = basename($thumb); $nomargin = $x%4 == 0?" nomargin":""; $title = htmlspecialchars($file); ?> <div class="thumbs fancybox<?= $nomargin ?>" style="background:url('<?= $thumb ?>') no-repeat 50% 50%;"> <a rel="group" href="images/'.<?= $file ?>" title="<?= $title ?>"><?= $title ?></a> </div> <?php endfor;

I would use a hash to remember what ID corresponds to what name. #!/usr/bin/perl use warnings; use strict; my $table = 'file_2.txt'; my $column = 'file1.txt'; my %names; open my $TAB, '<', $table or die $!; while (<$TAB>) { my ($name, @ids) = split; push @{ $names{$_} }, $name for @ids; } open my $COL, '<', $column or die $!; while (<$COL>) { chomp; print @{ $names{$_} // [$_] }, " "; }

if (true) { if (!false) { //Some indented code; stringLiteral = string.format( "This is a really long string literal. " + "I don't want it to have whitespace at " + "the beginning of each line, so I have " + "to break the indentation of my program " + "I also have vars here: " + "{0} " + "{1} " + "{2}", var1, var2, var3); // OR, with lineskips: stringLiteral = string.format( "This is a really long string literal " + "I don't want it to have whitespace at " + "the beginning of each line, so I have " +

Finally, I've found what's wrong with it. Appeared that the reason for described behavior is a setting provided with default web.config file: <add name="django.root" value="%APPL_VIRTUAL_PATH%" /> After I removed it everything started working fine. Here is some info related to django.root variable applied to Apache.

It appears that info.EnumerateFiles was the issue. I got that idea from this answer. I switched that to info.GetFiles and I was then able to delete the directory after.

You can use normpath, realpath or abspath: import os goal_dir = os.path.join(os.getcwd(), "../../my_dir") print goal_dir # prints C:/here/I/am/../../my_dir print os.path.normpath(goal_dir) # prints C:/here/my_dir print os.path.realpath(goal_dir) # prints C:/here/my_dir print os.path.abspath(goal_dir) # prints C:/here/my_dir

The simplest way I know to convert a path to its canonical form is using cd command: oPath = cd(cd(iPath)); Note that this would fail if the path does not exist on your file system.

Add this rules to your .htaccess file in Root folder : To do this www.linku.biz/JackTrow <--- www.linku.biz/profile.php?us="JackTrow RewriteRule ^profile.php?us=(.*)$ /$1 [R=301,L] To do this : www.linku.biz/search however <--- www.linku.biz/search.php RewriteRule ^(.*).php$ /$1 [R=301,L] Your last one , i have not understood what you want exactly.