w3hello.com logo
Home PHP C# C++ Android Java Javascript Python IOS SQL HTML videos Categories
ko.validation with multi-step wizard style models
you've applied the validation rules to the individual observables in your Name and Address model, but you are trying to use the grouped functionality without explicitly doing the grouping in each model: NameModel = function (model) { var self = this; //Observables self.FirstName = ko.observable(model.FirstName).extend({ required: true }); self.LastName = ko.observable(model.LastName).extend({ required: true }); ko.validation.group(self); return self; }; also, you will need to make modelIsValid a computed observable: self.modelIsValid = ko.computed(function() { return self.currentStep().model().isValid(); }); updated fiddle - http://jsfiddle.net/jnTjW/4/

Categories : Knockout Js

How do you dynamically create a multi-form wizard in Django from the same form?
I don't know if there's a way to do this in the exact way you describe, but the Django docs has a tutorial describing how to implement this use case.

Categories : Python

jquery form wizard for dynamic form pages available?
The Wicket-JqueryUI plugin provides the requested feature of having the dynamic form with form data coming from WEB SERVER and then navigating through the form back and forth with data persistence feature.

Categories : Jquery

Django form wizard with Ajax
I have never used FormData so I don't know if that's the source of the problem or not. Anyway I would recommend you to change the code to somewhat like this: $('#creation').on('submit', '#creation-form' , function (e) { e.preventDefault(); var post_data = $(this).serialize(); console.log('POST data:' + post_data); $.ajax({ url: '/create/', data: post_data, type: "POST", success: function (resp) { console.log(resp); $('#creation').html(resp); }, error: function (jqXHR, textStatus, errorThrown) { console.log(jqXHR); console.log(textStatus); console.log(errorThrown); } processData: false, contentType: false }); }); If it doesn't work, check the console and you will

Categories : Ajax

Using parsley on a wizard form (3 steps)
If your fields on second tab are hidden, you could just add ':hidden' property to the 'excludedFields' option. That way, each $(yourform).parsley('validate') would only validate visible fields (ie step1 then step2) If you do so, remember that you will have to manually bind parsley to your form and not with the data-validate="parsley"

Categories : Javascript

jQuery - Multiple step form (wizard)
is this what are you looking for??? $(document).ready(function() { var $pages = $(".steps-content").children("div"), $steps = $(".steps-wizard").children("div"), totalPages = $pages.length, count = 0; $(".navigation").on("click",function(e){ e.preventDefault(); var navigate = $(this).data("nav"); if(navigate == "next"){ count++; }else{ count--; } if(count > totalPages){ count = 0; } if(count < totalPages && count >=0){ $pages.removeClass('content-active').eq(count).addClass('content-active'); $steps.removeClass('step-active').eq(count).addClass('step-active'); } }); }); w

Categories : Jquery

Django Form Wizard with Conditional Questions
Try to replace __init__ method of your form with custom clean_are_you_cool method. So, if user submit value Yes you should check if how_cool field is populated too. You also should do this on client side to provide great user experience. Something like this with forms: def clean_are_you_cool(self): if self.cleaned_data.get('are_you_cool', None) == 'Yes': if self.cleaned_data.get('how_cool', None) is not None: # Actions for cool user. pass # Or if user not cool.

Categories : Python

jQuery - multiple step wizard form
Your code have some issues: hasClass: return a boolean value and tells you if you selector have or not a class index: is useless in your next click function you are changing the class but not toggling the visibility the steps bar is not handled With this code seems to working fine; check the use of find('.current') the get the current step child of .pg-wrapper and the use of next to move across the siblings. Code: var current; var navstep; $(function () { current = $('.pg-wrapper').find('.current'); navstep=$('.nav-step').find('.active'); $('.pg-wrapper div').not(current).hide(); }(jQuery)); $('#next').on('click', function() { if (current.next().length==0) return current.next().addClass('current').show(); current.removeClass('current').hide(); navstep.next().addCl

Categories : Javascript

Django form wizard unique URL design
Perhaps this would work: from apps.profile.views.login import SignupWizard, SIGNUP_FORMS from apps.profile.forms import MultiPartSignupFormStep1, MultiPartSignupFormStep2, MultiPartSignupFormStep3, MultiPartSignupFormStep4,MultiPartSignupFormStep5 step1 = (('step1', MultiPartSignupFormStep1),) other_steps = ( ('step2', MultiPartSignupFormStep2), ('step3', MultiPartSignupFormStep3), ('step4', MultiPartSignupFormStep4), ('step5', MultiPartSignupFormStep5), ) wizard_step1 = SignupWizard.as_view(step1, url_name='wizard_step1') wizard_other_steps = SignupWizard.as_view(other_steps, url_name='wizard_other_steps') urlpatterns = patterns('apps.profile.views.login', url(r'^$', wizard_step1, name='wizard_step1'), url(r'^account/signup/(?P<step>.+)/$', wizard_other_s

Categories : Django

django form wizard ajax next step
I'm using this code, and It's working for me. I don't put any action inside the form, as you can see. I use the jquery 'on' function when the form is submited because all the form is reloading and changing inside the div#creation. Then the ajax url must be the one that displays your form. In my case, the first step of the form is rendered also through ajax with get, when I click on some button. That's why there's isn't any form in the div at first. (I'm using bootstrap's modals). <div id="creation"> <!-- form to be display through ajax --> </div> The template that is reload in the FormWizard Class in views is the following html: template_name = 'creation_form.html' Code por creation_form.html: <form id="creation-form" action="#" method="post"> {% csr

Categories : Ajax

Bootstrap Form Wizard, Validation Error
I just tried to reproduce your problem, but the following code works for me (almost all copied from your base code). <!DOCTYPE html> <html> <head> <link href="bootstrap/css/bootstrap.min.css" rel="stylesheet" /> <link href="bootstrap-wizard.css" rel="stylesheet" /> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script> <script src="bootstrap/js/bootstrap.min.js"></script> <script src="bootstrap-wizard.min.js"></script> </head> <body> <div id="wizard" class="wizard"> <div class="wizard-card" data-cardname="card2"> <h3>User Accounts</h3> <label>User</label> <input type="text

Categories : Jquery

How can i bypass validation on page when clicking next in a asp.net Wizard?
Sorted the problem out.. The solution is to move all the validators to the last step of the wizard. here is my code as an example: <asp:WizardStep ID="WizardStep4" runat="server" Title="Step 4 - Finalize booking"> <h2>Finish</h2> <asp:ValidationSummary ID="ValidationSummary1" runat="server" HeaderText="Errors"/> <asp:RequiredFieldValidator runat="server" ID="RequiredFieldValidator7" ErrorMessage="Customer ID required" ControlToValidate="txtUserID" Font-Bold="true" ForeColor="Red" Display="None"></asp:RequiredFieldValidator><br /> <asp:RequiredFieldValidator ID="RequiredFieldValidator8" runat="server" ErrorMessage="Customer first name required" ControlToValidate="txtUserFName" Font-

Categories : C#

Bootstrap Modal, iFrame and Smart Wizard form
Resolved. I had decided to give up on the iframe and code the smart-wizard form directly into the modal but I encountered the same problem. After playing around a bit I discovered that bootstrap requires the newest jquery so I replaced the "js/jquery-1.4.2.min.js" from the smart-wizard code with http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js and the iframe method now works.

Categories : Twitter

FuelUX Wizard is not submitting my form when click on 'finished'
I landed on this when my form, with a button of type submit, in a Fuel UX wizard wouldn't actually trigger a submit Checkout my jsFiddle which seems to work var wizard = $(".wizard").wizard(); wizard.on('finished', function (e, data) { $("#form-in-wizard").submit(); console.log("submitted!"); });

Categories : Javascript

Django Form Wizard BooleanFields always returning False
Sorry I gave you the wrong field class. Instead MultipleChoiceField it should be ModelMultipleChoiceField, since you select from models. Something like this works in my case: forms.py (form for first step) class FirstStepForm(forms.Form): def __init__(self, *args, **kwargs): super(FirstStepForm, self).__init__(*args, **kwargs) self.fields['countries'] = forms.ModelMultipleChoiceField(queryset=Country.objects.all()) views.py class MyWizard(SessionWizardView): def render(self, form=None, **kwargs): response = super(MyWizard, self).render(form, **kwargs) grids_data = self.get_cleaned_data_for_step('0') or {} print grids_data return response

Categories : Python

Eclipse JFace Wizard jump to next page programatically
You first need a reference to the wizard page where you want to go. If you don't have it already through other means, you can find all wizard pages via this API: getWizard().getPages() Next, you make the following call: getContainer().showPage( desiredPage )

Categories : Eclipse

Django form wizard: Delete temporary files stored by intermediate steps
Django says on the documentation that you have to manage these files yourself, so: You can set the uploading path to /tmp (if you are using Linux), so that they are automatically deleted. Another approach is that you can write a script to run periodically and delete them.

Categories : Django

Can I have unique urls to the multi step signup form built using Django Wizard.
NamedUrlWizardView should provide the functionality you are looking for.

Categories : Django

How to use ModelState to clear my form after I post my form data,my view model is a viewmodel which has two models?
In such case you will have to remove each property of StudentModel from your ModelState i.e. Syntax: ModelState.Remove("PropertyName"); Example: ModelState.Remove("Id"); ModelState.Remove("Name"); ModelState.Remove("Marks"); Edit: For specific model property in among two ModelState.Remove("StudentModel.Name");

Categories : Asp Net Mvc

How can I save the order a list of hidden form inputs which represent an array in ASP.NET MVC?
I have discovered a blog post from Phil Haack which contained the answer. By using arbitrary indexes in a seperate hidden input with the name of my collection + .Index, the model binder seems to handle it and maintain the order. @using(@Html.BeginForm("Save", "MyController", FormMethod.Post)) { <input type="submit" value="Save"/> @Html.HiddenFor(x=>x.Id) <ul id="sortable2" class="connectedSortable"> @{ int count = 0; } @foreach(var item in Model.CollectionOfThings) { <li class="ui-state-default"> @Html.Hidden("Things.Index", "item" + count) @Html.Hidden("Things[item" + count + "].Id", item.Id) @Html.Hidden("Things[item" + count + "].Title", item.Title)

Categories : Asp Net Mvc

Sonata Admin: How to represent a Many to Many in the edit form when the associated entity has thousands of records?
Could pcdummy/AjaxCompleteBundle be of any interest? I have just stumbled upon this today. And I would also suggest creating separate intermediate users_roles entity (and an admin for it). Then, using sonata_type_collection, you can add Group:userGroups field into Group admin. Remember to not include group field in UsersGroupAdmin form config.

Categories : PHP

Form - How to save page info on button click on form instead of navigation to next page
You must use Ajax , this how for examle: $("#ui-block-a input[type='submit']").click(function() { var url = "Page2.HTML"; $.ajax({ type: "POST", url: url, data: $("#fhome").serialize(), // serializes the form's elements. success: function(data) { alert(data); // show response from the php script. } }); return false; });

Categories : Jquery

[google form]Creating form with a script : Page Break and go to page issue
You only need to change the order of your operations; you do not need to keep the operations on item together. Here's an example, using your code: function createForm() { var title = 'Multipage Form Test'; var description = 'Stackoverflow question 17083500'; var form = FormApp.create(title) .setDescription(description) .setConfirmationMessage('Thanks for responding!'); var page1 = form.addPageBreakItem() .setTitle('First page'); var item = form.addMultipleChoiceItem(); var page2 = form.addPageBreakItem() .setTitle('Second page'); var page3 = form.addPageBreakItem() .setTitle('Third page'); item.setTitle('Question') .setChoices([ item.createChoice('Yes',page2), item.createChoice('No',page3) ]); Logger.log(fo

Categories : Forms

Pass Data From Input Form on One Page To a Select Form on Another page?
You can pass variables via GET and POST. To pass variables to a page via GET, call the page like so: /myPage.php?myParam=1 Then, you could run the following PHP: <?php echo $_GET['myParam']; ?> Which would output "1." To pass variables via POST, post your data to the page like so: <form action="myPage.php" method="post"> <input type="text" name="myInput" /> <input type="submit" value="Submit"> </form> Then, on myPage.php you could run the following: <?php echo $_POST['myInput']; ?> Which would output whatever was contained in the textbox before you clicked submit. Edit: It looks like you are trying to submit data from one page and have that appear in the next page as an option in your select menu. Try this on page1.php: <fo

Categories : PHP

Form for multiple models
You can create two separate forms having the required fields, for each model. Then show both forms in the template inside one html element. Both forms will get rendered and then submitted individually. You can then process the forms separately in the view. class TopicForm(ModelForm): class Meta: model = Topic fields = ("title", ..) class PostForm(ModelForm): class Meta: model = Post fields = ("body", ..) In view: form1 = TopicForm() form2 = PostForm() In template: <form ...> {{ form1 }} {{ form2 }} </form> You can easily use form.save() and all other functions, without doing it all yourself.

Categories : Python

Rails 3.2 app with no models, which form validation to use?
You only need ActiveModel::Validations to enable validations. Please take a look at the API docs for the module. According to docs: class Person include ActiveModel::Validations attr_accessor :first_name, :last_name validates_each :first_name, :last_name do |record, attr, value| record.errors.add attr, 'starts with z.' if value.to_s[0] == z end end you can also use validates_presence_of :name syntax.

Categories : Ruby On Rails

How do i combine index form of 2 models together?
Your question isn't very clear, but let me give an example and hopefully it will help you. Let's say you have 2 models, a Project and Tasks. A Project has many tasks and tasks belong to a project. I'm assuming that you have a helper method called current_user (like the one Devise gives you) which refers to current user. If you want to list all the users projects in the index action of a controller let's say Projects#index you would have @projects = current_user.projects Now in your view you can loop through this like so <% for project in @projects do %> <%= project.name %> <%= project.description %> <% for task in project.tasks do %> <%= task.name %> <% end %> <% end %> Now your view would display both the Projects and the ta

Categories : Ruby On Rails

Ruby on Rails, two models in one form
You can use fields_for for the second model, which works like form_for but doesn't generate the form tags. See the docs.

Categories : Ruby On Rails

MVC 4 - detail page with two models
You use a ViewModel. Basically, it's a wrapper for everything: public class BlogDetailViewModel { public Post Post { get; set; } public IList<Comment> Comments { get; set; } public Comment NewComment { get; set; } } Then, your view takes a model of type BlogDetailViewModel. You would use NewComment for the new one: @Html.TextBoxFor(x => x.NewComment.Email) @Html.TextBoxFor(x => x.NewComment.CommentContent) ..etc. In your controller.. you construct it: return View(new BlogDetailViewModel() { Post = thePostVariable, Comments = getCommentsForPost(), NewComment = new Comment() }); On post, your NewComment member will contain the new comment data.

Categories : C#

CakePHP: Validating one form with 2 unrelated models
The answer at http://stackoverflow.com/a/4775385/82135 is correct. As my models are not related, the answer marked as correct on that question did not work for me.

Categories : Validation

Saving to two models via intermediate form - Django
Since coding_form is not an instance of ModelForm and hence coding_form.save() will not work and will not return a model instance. You can access form data by using coding_form.cleaned_data dictionary.

Categories : Django

How to surface two Django models on one page?
class ClientView(generic.ListView): # ... def get_context_data(self, **kwargs): context = super(ClientView, self).get_context_data(**kwargs) context['press'] = Press.objects.all() return context

Categories : Django

Why don't import models in all page django
Do not name your variable like your class accounts=accounts.objects.filter(twitterid=userid) Try fix it and see if that can help from models import * def info(request): yasin = "teksaas" if check_key(request): api = get_api(request) user = api.me() userid = user.id acc=accounts.objects.filter(twitterid=userid) if acc: return render_to_response('twitter_auth/info.html', locals()) else: registeracc=accounts(twitterid=412313,others='Hello im jsaon walker what your problem i cant unt') registeracc.save() return render_to_response('twitter_auth/info.html', locals()) else: return HttpResponseRedirect(reverse('main'))

Categories : Python

Single form, multiple models, using 3rd party application
If your two forms don't need to reference each other's data to validate, you can just instantiate them both in the view, using the prefix argument for at least one of them to keep them distinct. third_party_form = ThirdPartyForm() my_form = MyCustomForm(prefix="my_form") Then just make sure you add them both to the context and render both in the same <form> tag in the template. If you do need to reference data from one form to validate the other, inheritance sounds like the way to go to me.

Categories : Django

cakePHP: form with related models not automagic updating
There's no automagic way to do what you're asking. Since all the data for dropdowns have already beed displayed on load, the only way to change the second dropdown depending on the first select is via javascript. If you search for "dropdown on select" or something similar for cake, you'll find solutions to do it with ajax or plain js. I leave you one reference here. That one is done with ajax and a new action. But you could also do it with just js, doing a find for Regions and Properties and setting them in a json variable in js to be manipulated.

Categories : Forms

Submitting to two models with one form with jQuery file upload
Forget the way your doing it. Instead what you need to do is to split the forms up and put the one create photo form on top and remove the submit button. Then when the create product happens you look for all the photos the user has updated and that is not associated to the current product id new product page = form_for @photo, :html => { :multipart => true, :id => "fileupload" } do |f| %span Add files... = f.file_field :image %br = form_for @product,:url => products_path, :html => { id: "fileupload", multipart: true } do |f| %p = f.text_field :name, placeholder: "Name" %p = f.text_field :price, class: "auto", data: { a_sign: "$ " }, placeholder: "Price" %p.button.start = f.submit product controller def new Photo.where(:product_id =>

Categories : Ruby On Rails

How to do multiple models in the same page using backbone and RequireJS
You should have only one main.js file in a view, so <script data-main="js/mainCollector" src="js/libs/require.js"></script> <script data-main="js/mainTerm" src="js/libs/require.js"></script> <script data-main="js/mainTermCampaign" src="js/libs/require.js"></script> is wrong, use: <script data-main="js/main" src="js/libs/require.js"></script> , and put the logic into that main.js file. You wrote that mainCollector, mainTerm.js and mainTermCampaign.js are similar. which mean you have three routers in your app, which also seems like a bad thing, I think one should be enough. I think you should think again how to structure your code. You put the script tag into your body, which is also unusual, read require.js docs and try to use best pra

Categories : Backbone Js

Carry form input data from one page, to a php form that emails the data, and again through to the php redirect page
The easiest thing to do from submit.php is to set session data $_SESSION['name'] = array('myInput'=>$_POST['myImput']); Then after everything is set: header('location: info.php'); in info.php <?php session_start()// almost forgot call this at the top of submit.php and info.php first and access your session data: echo $_SESSION['name']['myInput']; on a side note, I would look at using AJAX from the form.php to the submit.php and have submit return a complete or fail status. Then carry the form data you want from there to info.php

Categories : PHP

Ember output vars form other controllers / models in a view
Normally the instance of the auth model would be set on the content property of your auth controller (typically handled by the router). Once the content is set then your template would work with no modifications. This gist might help you out as it as a login example using the router: https://gist.github.com/machty/5647589

Categories : Ember Js

How can I create and update two different models in the same page in ruby on rails?
You should check railscasts.com episode on nested forms. Episode 1 and Episode 2

Categories : Ruby On Rails



© Copyright 2017 w3hello.com Publishing Limited. All rights reserved.