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DateTime input format?
Running that in debug mode, I get the following conversion failure: ConvertBack cannot convert value '30/01/2013' (type 'String'). BindingExpression:Path=Date; DataItem='MainWindowViewModel' (HashCode=19342748); target element is 'TextBox' (Name=''); target property is 'Text' (type 'String') FormatException:'System.FormatException: String was not recognized as a valid DateTime. It looks like it uses a default converter which uses something along the lines of DateTime.Parse. The following fails with the same exception: var date = DateTime.Parse("30/01/2013"); It looks like your only options is to write your own converter.

Categories : Wpf

C# DateTime format with input from a string
A DateTime has no format. It just represents a date and a time. If you want to display it in a specific format, convert it back to a string with the appropriate format specifiers: string format = "yyyy.MM.dd HH:mm:ss:ffff"; string eventdatetime = "2013.07.12 15:32:04:4687"; DateTime x = DateTime.ParseExact(eventdatetime, format, CultureInfo.InvariantCulture); var display = x.ToString("yyyy.MM.dd HH:mm:ss:ffff"); Furthermore, zzzz designates the timezone. You want ffff which designates fractions of a second.

Categories : C#

Display DateTime value in dd/mm/yyyy format in MVC4
All you have to do is type format you want in html helper. ie. @Html.TextBoxFor(m => m.ResgistrationhaseDate, "{0:dd/MM/yyyy}") and you don't need to provide date format in model class.. it will work perfectly..

Categories : Asp Net Mvc

template-toolkit datetime in ISO format as input
Sure, you should use DateTime module, and DateTime::Format::Strptime to parse and format (transform from DateTime to string and viceversa.

Categories : Perl

Input string was not in a correct format with DateTime
you should always use DateTime.TryParseExact. string[] formats = { "dddd, dd MMMM yyyy" }; //your format here DateTime dt; if (DateTime.TryParseExact(dpLeaveFromStd.SelectedDate.GetValueOrDefault(), formats, CultureInfo.InvariantCulture, DateTimeStyles.None, out dt)) { }

Categories : C#

Setting DateTime display format at runtime with MVC3
This uses Razor syntax but same principle applies @{ var dateFormat = (DateTime)Viewbag.PreferredDateFormatForUser //Just grab it from where ever you have it } @Html.TextBox("ScheduleDateTime", model.ScheduleDateTime.ToString(dateFormat)) Here is the reference for custom date time format strings http://msdn.microsoft.com/en-us/library/8kb3ddd4.aspx

Categories : C#

why my basic date picker couldn't convert the input into the datetime format ?
Try this .. Dim queryString As String = "select * from smsdw.lot_act where tran_dttm <= cdate('" & bdp1.Value.ToString & "') and tran_dttm > cdate('" & bdp1.Value.ToString & "')"

Categories : Vb.Net

Covert c# datetime format to java datetime format
Your format string doesn't match the input date string : // 2013-07-03T19:16:02.3694 <-- date string static SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd"); You need to first parse the date string using the SimpleDateFormat with pattern yyyy-MM-dd'T'HH:mm:ss.SSSSSS and then you can format the Date object with dd-MM-YYYY pattern.Remember MM is for months , mm stands for minutes. String formattedDate = new SimpleDateFormat("dd-MM-YYYY").format( new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSSSS") .parse(reportItem.getString("AddedTime")));

Categories : C#

input string not in correct format...when converting a string to datetime...error?
Make sure your input string is using decimal point symbol for your current culture!. If your input string does not match these rules, decimal.Parse throws the Input string was not in a correct format exception If you for instance use the invariant culture: decimal.Parse("17.5", CultureInfo.InvariantCulture) The dot will be the accepted decimal point. You can read more about it over at MSDN There they also mention that the decimal.TryParse method is better suited for invariant culture parsing Also (obviously), make sure your input string is not null, empty, or containing any non-numerical characters (except for the one, optional, dot or comma, depending on your culture)

Categories : C#

format string in datetime c# to insert in MYSQL datetime column
Your line: string time = Convert.ToDateTime("10-10-2014 15:00:00"); Shouldn't compile. I can only guess that you don't have DateTime as type of your column in SQL Server, you should modify it to keep DateTime and then pass a DateTime type object, not a string.

Categories : C#

Adding date or time in datetime format to another datetime
*This is a method using DateTime:* $begin = new DateTime($start); $finish = new DateTime($end); $difference = $finish->format('U') - $begin->format('U'); // working version $minutesDiff = round(($difference/60), 0); $finalDate = new DateTime(); $finalDate->modify(sprintf('+%s minutes', $minutesDiff)); edit added missing bracket edit2 version without ->diff() method

Categories : PHP

Sql query for CONVERT datetime to a different datetime Format in SQL 2005?
http://msdn.microsoft.com/en-us/library/ms187928.aspx check out see Microsoft's explanation on date formats the one you're looking for is 20 or 120 BTW, you should supply with varchar with a number like this varchar(10)

Categories : SQL

populating datetime value from php into Jquery Moble text input datetime-local
$(document).ready(function() { $("#datetime-1").val(<?php YOUR CODE ?>); $("#datetime-2").val(<?php YOUR CODE ?>); }); Its a bit hacky but it should work, just make sure the format of the date is what jq mobile is expecting.

Categories : PHP

How to convert SCORM 2004 session_time format to a usable datetime format in SQL
Just worked out a solution for me. This would need to be put inside a SQL function for me and I would need to finish off the last bit where I decide what format I want. I am only updating around 900 rows and it is a 1 off update so performance isn't an issue. DECLARE @session_time varchar(200) = 'P50Y2M3DT4H5M6S' DECLARE @date varchar(100) = '' DECLARE @time varchar(100) = '' DECLARE @year varchar(20) = '0' DECLARE @month varchar(20) = '0' DECLARE @day varchar(20) = '0' DECLARE @hour varchar(20) = '0' DECLARE @minute varchar(20) = '0' DECLARE @second varchar(20) = '0' -- Remove the P SET @session_time = SUBSTRING(@session_time, 2, LEN(@session_time)-1) -- If we have a T IF PATINDEX('%T%',@session_time) > 0 BEGIN SET @date = SUBSTRING(@session_time, 0, PATINDEX('%T%',@session_

Categories : PHP

asp.net DetailView datetime field format doesn't match the SQL Server format
Check Your PC Date format and enter date of same format in due date if you enters the date time dynamically then use like this DateTime.Now.ToString(yyyy-MM-dd) here yyyy-MM-dd is my date format enter yours format in this and this is for current date you can use it for the date you desired

Categories : C#

Convert Datetime format to varchar format style workaround
Well you can convert both Dates in any format before you compare the two just use any of these: run this and you can select from them, make sure to convert both dates before Comparing Select convert(varchar, GetDate(), 100) as '100 Conversion', convert(varchar, GetDate(), 101) as '101 Conversion', convert(varchar, GetDate(), 102) as '102 Conversion', convert(varchar, GetDate(), 103) as '103 Conversion', convert(varchar, GetDate(), 104) as '104 Conversion', convert(varchar, GetDate(), 105) as '105 Conversion', convert(varchar, GetDate(), 106) as '106 Conversion', convert(varchar, GetDate(), 107) as '107 Conversion', convert(varchar, GetDate(), 108) as '108 Conversion', convert(varchar, GetDate(), 109) as '109 C

Categories : SQL

DateTime to XML format but keep the datatype as datetime
The dateTime object holds the date and time in a way that is independent of any formatting. The output format is chosen when you convert the value to a string. If it comes out as dd:mm:yyyy, that's because it's defaulting to the format used by the country/language configured for your machine. So the answer is, if you want the ISO format (which you refer to as XML format), then the time to request this is at the time you output the dateTime as XML; it's not a property of the date/time value itself.

Categories : C#

Get custom datetime format from standard format
Here's some code do get the patterns: var c = new CultureInfo("fr-FR"); Console.WriteLine(c.DateTimeFormat.LongDatePattern); Console.WriteLine(c.DateTimeFormat.ShortDatePattern); Console.WriteLine(c.DateTimeFormat.FullDateTimePattern); The result from a console app is the following dddd d MMMM yyyy dd/MM/yyyy dddd d MMMM yyyy HH:mm:ss

Categories : C#

Javascript datetime format in database format
dateToString : function (unformatted) { if (!unformatted) { return null; } var year = unformatted.getFullYear(); var month = unformatted.getMonth() + 1; var day = unformatted.getDate(); if (month < 10) { month = '0' + month; } if (day < 10) { day = '0' + day; } return [year, month, day].join('-'); } feel free to add time formatting

Categories : Javascript

how to change date format of datetime format in php
I'd certainly hope that date values aren't actually stored in a textual format at all, any more than numbers are. It's a bit like asking the database to store numbers as hex instead of decimal. You should separate the inherent values within the data from the textual format applied to them when you present them. Normally I'd recommend formatting the data at the client side instead (which typically has more user context) but you can specify a format in the SELECT statement as well: SELECT DATE_FORMAT(StartDate, '%d-%m-%y') FROM SomeTable Likewise when inserting or updating data, I would try to use parameterized SQL so that you don't specify dates as text at all - normally the client library should be able to pass the data on to the database in a native binary format. In general, you sho

Categories : PHP

Convert "m/d/y" date from a form text input field to a mysql datetime "friendly" input?
strtotime() is smart, but it's not psychic or a genius, and when it screws up, it screws up bigtime. Don't use it, especially with ambiguous formats like m/d/y. There's no guarantee it won't be treated as as d/m/y. Use date_create_from_format() instead, which lets you explicitly specify the input format. This is far more reliable, since you'll be in control over how the d and m portions are handled: $ts = date_create_from_format('m/d/Y', '08/06/2013'); $start_date = $ts->format('Y-m-d H:i:s');

Categories : PHP

i'm trying to display user defined number of checkboxes and display the value of the checked boxes in another textbox
See: http://jsfiddle.net/Xar2d/ I think you were going for something like this: $(document).ready(function () { $("#btn1").click(function () { $v = $("#txt").val(); for (i = 0; i < $v; i++) { var box = $('<input type="checkbox" class="chkbx" name="chkbx" value="Option' + i + '">Option ' + i + '<br/>'); $("#display").append(box); } }); $(document).on("change", ".chkbx", function () { $("#show").val(""); var selected = []; $(".chkbx:checked").each(function () { selected.push($(this).val()); }); $("#show").val(selected.join(", ")); }); });

Categories : Jquery

Verifying user input for a magic square game/Comparing arrays (user-defined&programmer-defined)
IMO you should maintain a multi-dimensional array for better code readability that is int[3][3] instead of 3 int[3]'s. Below is my try public static void main(String [] args) { int[][] input=new int[3][3]; int[][] defined={{8,1,6}, {3,5,7}, {4,9,2}}; Scanner sc=new Scanner(System.in); //Take input //Outer loop for(int i=0; i<3; i++) { System.out.println("Enter value for Row number - "+(i+1)); //Inner loop for(int j=0; j<3; j++) { input[i][j] = sc.nextInt(); } } //Compare boolean matches = true; for(int i=0; i<3; i++) { //Inner loop for(int j=0; j<3; j++) { if(input[i][j] != defined[i][j]) { matches = false; break; }

Categories : Java

XSLT format a xml data file to multiple table display using HTML format
When this stylesheet is executed, it starts by applying templates to the root node, /. This fires your xsl:template match="/". While that template is being applied, the context node is /. So when it processes <xsl:apply-templates select="testsuites"/> <xsl:apply-templates select="testsuite"/> <xsl:apply-templates select="testcase"/> <xsl:apply-templates select="failure"/> each of those XPath expressions is evaluated relative to /. So for the first one, you're asking it to apply templates to /testsuites (immediate child[ren] of the root node named testsuites). That's fine, because there is such a node. But for the second one, you're asking it to apply templates to /testsuite (immediate children of the root node, named testsuite). No such node exists. Th

Categories : HTML

Input String not in correct format (Format Exception not handled)
Don't do the string conversion in the first place: double hours = (double) oleDbDataReader1["Hours"]; Unless your value is actually a string in the database (in which case you should fix that) there's no reason to convert it into a string. (If it's not a type mapped to double, you should change what you cast it to, of course.) EDIT: If it's non-numeric in the database, then you probably do need to use double.Parse - but you might want to specify the culture. For example, assuming they're all of the form "10.2" rather than "10,2" (as some cultures would use) you would want something like: double hours = double.Parse((string) oleDbDataReader1["Hours"], CultureInfo.InvariantCulture);

Categories : C#

Format DateTime
Try to use this (in your hibernateObject class): @Temporal(TemporalType.TIMESTAMP) @DateTimeFormat(pattern = "yyyy-MM-dd hh:mm:ss") public Date getStartDate() { return startDate; } public void setStartDate(Date startDate) { this.startDate = startDate; } When you do as you show date object actually has no changes. Only thing that happens: you create String that contains formatted date. So you can specify DateTimeFormat pattern to store date in that pattern instead. Also note, that "hh" string in your date pattern actually will give you value from 1 to 12. It is AM/PM hour. To get 0-24 hours value use "HH" instead (see http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html, "Date and Time Patterns" section)

Categories : Java

DateTime Format for .NET
var res = DateTime.Now.ToString("MM/dd/yyyy hh:mm:ss tt", CultureInfo.InvariantCulture); Read Standard Date and Time Format Strings On MSDN for more information Below is another way of achieving same format Console.WriteLine(date1.ToString("G", CultureInfo.CreateSpecificCulture("en-us"))); // Displays 4/10/2008 6:30:00 AM

Categories : C#

How do I convert string date format to datetime date format?
This should do it: SELECT CONVERT(DATETIME, REPLACE('Sept. 23, 2013','.',''), 107) This removes dot in string and converts to datetime format 107. And this returns the string you wanted (MM/DD/YYYY): SELECT CONVERT(VARCHAR(10), CONVERT(DATETIME, REPLACE('Sept. 23, 2013','.',''), 107), 101) For other format types see: http://www.sqlusa.com/bestpractices/datetimeconversion/ and http://www.sql-server-helper.com/tips/date-formats.aspx Edit: It turns out it works for me because of Slovenian locale (Sept.). This one should work in English locale: SELECT CONVERT(VARCHAR(10), CONVERT(DATETIME, SUBSTRING('Sept. 23, 2013', 0, 4) + ' ' + SUBSTRING('Sept. 23, 2013',6,9), 107), 101) As a function.

Categories : Asp Net

hadoop input format for hadoop streaming. Wikihadoop Input Format
As far as I know, there is no difference in how inputs are processed between Hadoop streaming jobs and regular MapReduce jobs written in Java. The inheritance tree for StreamWikiDumpInputFormat is... * InputFormat * FileInputFormat * KeyValueTextInputFormat * StreamWikiDumpInputFormat And since it eventually implements InputFormat, it can be used in regular MapReduce jobs

Categories : Hadoop

C Sharp DateTime Format
Edited To Note: This looks to be a bug with Windows 7. When changing the short date pattern via the control panel, using the "additional settings" tab as in the OP's post, both the CurrentCulture and CurrentUICulture's date separator gets changed as well. When you modify the short date format, it looks like the first non-format character is picked up as the date separator for the current culture. Both CurrentCulture and CUrrentUiCulture are modified to reflect that [unintended] customization. Looks like some [bright] developer made the [unwarranted] assumption that nobody would ever have a short date format that included something like day of the week. Nice catch! Are you going to report the bug to Microsoft? If you use the invariant culture to format dates, etc., user settings won't af

Categories : C#

Can't change DATETIME format
Use DATE_FORMAT(date, format): DATE_FORMAT(s.date,'%d-%m-%Y')

Categories : PHP

Output format datetime in yii
Your validation rule definition is wrong. If you want to only accept a correctly formatted date from the user, the rule should read array ('time_start, time_end', 'date', 'format' => 'yyyy-MM-dd HH:mm:ss'), This sets up a CDateValidator with the correct date format, which you have to specify not using PHP DateTime conventions but with those of CDateTimeParser.

Categories : Mysql

SQL DateTime Format Convert
Assuming you are using a datetime field, you are not going to change the format of the date being stored that way. You can achieve your output format this way, I used getdate because i am not sure what you are trying to do: SELECT stuff(convert(varchar(25), getdate(), 100), 1, 3, datename(month, getdate()))

Categories : Sql Server

MVC DateTime format can not be parsed
This is a tricky area. There are many factors involved. One of the reasons can be that the web browser is set for US english. How about setting the culture information of the thread. You can do it either using Thread.CurrentThread.CurrentCulture or in the web config <globalization enableClientBasedCulture="true" culture="auto:en-NZ" uiCulture="auto:en"/> .

Categories : Asp Net Mvc

DateTime format wrong
In C# the + operator is overloaded for most system types, just add them together. So you should also just take the Date object from the picker, instead of converting it to a string. Edit: Now the final DateTime will be the result of adding the Date from the RadDatePickers and the Time from the RadTimePickers. DateTime StartDate = Convert.ToDateTime(RadDatePickerStart.SelectedDate); DateTime EndDate = Convert.ToDateTime(RadDatePickerEnd.SelectedDate); TimeSpan StartTime, EndTime; if (RadTimePickerStart.SelectedDate != null) StartTime = RadTimePickerStart.SelectedDate.Value.TimeOfDay; if (RadTimePickerEnd.SelectedDate != null) EndTime = RadTimePickerEnd.SelectedDate.Value.TimeOfDay;

Categories : C#

Datetime format does not match
It's because you don't have the format you specified. You have the format: '%Y-%m-%d %H:%M:%S' There are multiple solutions. First, always generate the data in the same format (adding .00 if you need to). A second solution is that you try to decode in one format and if you fail, you decode using the other format: try: dt = datetime.datetime.strptime(time, '%Y-%m-%d %H:%M:%S.%f') except ValueError: dt = datetime.datetime.strptime(time, '%Y-%m-%d %H:%M:%S')

Categories : Python

Format this datetime without seconds or AM/PM
You are looking for a custom Date and Time format. Try this: MyDateTime.Value.ToString("HH:mm")

Categories : Asp Net

DateTime is not in proper format
There's several ways to do this. Either: Change the regional settings for the user running your web application Use the correct CultureInfo object when formatting Set the default CultureInfo object on the current thread Escape the slashes To provide a CultureInfo object when formatting: @Html.DisplayFor(modelItem => item.EndDate.ToString("dd/MM/yyyy", CultureInfo.GetCulture("en-US"))) To set the default CultureInfo object: Thread.CurrentThread.CurrentCulture = CultureInfo.GetCulture("en-US"); To escape the slashes, use single quotes: [DisplayFormat(ApplyFormatInEditMode = true, DataFormatString = "{0:dd'/'MM'/'yyyy}")] Note that all the code ends up in DateTime.ToString(string) or one of its overloads, so that's the place to look for clues to this.

Categories : C#

DateTime Format Handling
You can use ParseExact DateTime.ParseExact(datestring, "dd.MM.yyyy", System.Globalization.CultureInfo.InvariantCulture); you already know format so you can go for this, but make sure the string is in same format and never changes.

Categories : C#

Adding Int to DateTime in format DD/MM/YYYY
You can do the following, DateTime today = DateTime.Parse(maskedTextBox1.Text); DateTime answer = today.AddDays(Convert.ToInt32(zpocdnu.Text)); maskedTextBox2.Text = answer.ToString() ;

Categories : C#



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