w3hello.com logo
Home PHP C# C++ Android Java Javascript Python IOS SQL HTML videos Categories
Efficient calculation of polynomial coefficients from its roots

You can do this in O(n^2) very easily if you incrementally build your polynomial. Let's define:

p_k(x) = (x-x_1)*...*(x-x_k)

That is p_k(x) is the multiplication of the first k (x-x_i) of p(x). We have:

p_1(x) = x-x_1

In other words the array of coefficients (a) would be (indices start from 0 and from left):

-x_1 1

Now assume we have the array of coefficients for p_k(x):

a_0 a_1 a_2 ... a_k

(side note: a_k is 1). Now we want to calculate p_k+1(x), which is (note that k+1 is the index, and there is no summation by 1):

p_k+1(x) = p_k(x)*(x-x_k+1)
=> p_k+1(x) = x*p_k(x) - x_k+1*p_k(x)

Translating this to the array of coefficients, it means that the new coefficients are the previous ones shifted to the right (x*p_k(x)) minus the k+1th root multiplied by the same coefficients (x_k+1*p_k(x)):

           0   a_0 a_1 a_2 ... a_k-1 a_k
- x_k+1 * (a_0 a_1 a_2 a_3 ... a_k)
-x_k+1*a_0 (a_0-x_k+1*a_1) (a_1-x_k+1*a_2) (a_2-x_k+1*a_3) ...
(a_k-x_k+1*a_k-1) a_k

(side note: and that is how a_k stays 1) There is your algorithm. Start from p_1(x) (or even p_0(x) = 1) and incrementally build the array of coefficients by the above formula for each root of the polynomial.

© Copyright 2018 w3hello.com Publishing Limited. All rights reserved.