Finding the row with the highest average in a numpy array 
You don't need to worry about the 0s, they shouldn't effect how the
averages compare since there will presumably be one in each row. Hence, you
can do something like this to get the index of the row with the highest
average:
>>> import numpy as np
>>> complete_matrix = np.array([
... [0, 1, 2, 4],
... [1, 0, 3, 5],
... [2, 3, 0, 6],
... [4, 5, 6, 0]])
>>> np.argmax(np.mean(complete_matrix, axis=1))
3
Reference:
numpy.mean
numpy.argmax

Average of 2d list by only adding single row and finding the average of that single row 
>>> L = [['x','y',1], ['x','y',1], ['x','y',2]]
>>> sum(entry[1] for entry in L) / float(len(L))
1.3333333333333333
This is same as:
>>> sum(entry[2] for entry in L) / float(len(L))
since the last position is index 2.

what is the average time, that an average process, running on an average kernel, using an average scheduler, gets in one active cycle? 
Linux uses 100 milliseconds as the scheduler quantum, if that's what you
were asking, in your own, convoluted way :)
There's nothing saying a process has to use their entire quantum and, in
fact, if they release early, I think their priority gets bumped up a bit as
a reward.

Finding an average SQL 
I'm going to guess a little bit on what's going on from your comment, so I
think your JOIN is off a bit. Try this:
Select Company.company_id, company.Company_Name,
avg(UserJobRating.Total_Rating)
from company
inner join jobs on jobs.Company_id = company.company_id
inner join UserJobRating on jobs.Job_id = UserJobRating.Job_ID
group by company.company_id
SQL Fiddle Demo
Without seeing your table definitions, this is a bit of a guess, but I
would bet you're producing a Cartesian Product with the UserJobRating table
with this statement:
on Job_id = UserJobRating.Job_ID

SQL finding average between dates 
Declare @dt_to datetime
Declare @dt_from datetime
set @dt_to = convert(datetime,'201378')
set @dt_from = convert(datetime,'2013715')
Update tableName
Set avg_paid_volume = (cns_amt / datediff(d,@dt_to,@dt_from))
datediff is key here

Finding the average of n numbers with Python 
You only need one loop to work. Just ask you question, get the input, and
loop. When you enter no, then the loop will exit and compute your average.
print("This program 'is' designed to find the average of n numbers you
input
") #print statement that introduces the average finder
counter = 0 #this counter will count how many numbers the user has inserted
into the program and will be used as denominator
sum_of_numbers = 0 #this number is set as 0 as currently the sum is 0, as
more numbers are inputed, they will be added together
first_question = input('''Would you like to enter a number? Type "yes" if
you do, and "no" if you don't.
''') #takes input of yes or no to see whether user wants to find average of
numbers
while first_question == "yes" :
ent_num = int(input("Enter y

Finding Average using nested queries on another table 
Here's an example that you can execute in LINQPad
EDIT: updated to show handling of nulls for sub query
void Main()
{
var restaurants = new List<Restaurant>();
restaurants.Add(new Restaurant(1, "McDonalds"));
restaurants.Add(new Restaurant(2, "Wendy's"));
restaurants.Add(new Restaurant(3, "KFC"));
var comments = new List<Comment>();
comments.Add(new Comment(1, 1, "I love clowns!", 9.5));
comments.Add(new Comment(2, 1, "Disgusting", 1.0));
comments.Add(new Comment(3, 1, "Average", 5.0));
comments.Add(new Comment(4, 2, "Hmmm tasty", 8.5));
comments.Add(new Comment(5, 2, "Yuck", 4.0));
// Edit  removed comment for KFC, updated code below to handle nulls
var restaurantsWithRatings = restaurants.Select(r => new {
Re

Finding average file size in MB in given directory 
You could use the Average extension method:
// using System.Linq;
string filePath = @"DesiredFilePath";
double averageFileSize = Directory
.EnumerateFiles(filePath)
.Average(x => new FileInfo(x).Length);

having issues with finding the average run time of a block 
Your method is mostly ok so far, except you don't need to branch out i == 1
from i > 1 – { 1.times { yield } is functionally equivalent to just
calling yield.
yield doesn't return anything on its own. It is a keyword that indicates
the block given to the method should be called, and can optionally be fed
variables that would in turn get passed to the block, e.g:
class String
def each_character_in_reverse_order
each_char.to_a.reverse_each do char
yield char
end
end
end
"hello".each_character_in_reverse_order do c
puts c.upcase
end
#=>
# O
# L
# L
# E
# H
In the case of the tests you've linked to, the return values of the blocks
are complete inconsequential, as they are only interested in how long it
takes to run the block. But as you can see in the exa

Python: Finding the average stock value for each month 
Inside the if loop the sum_float and count are not made a 0, so as a
program proceeds the average goes for multiple months.
So try doing that and it should solve your problem.
Also one more point with your logic is that are you that whether your list
of tuples is sorted one if not it can lead to complications with regards to
your logic.

Finding average of last 3 not null values from sqlite database 
I'm going to assume you have a column to_order which contains the order you
want to retrieve the rows in and col which contains your numbers:
select avg(col) from tbl where col is not null order by to_order desc limit
3;
If you have further questions, leave a comment.

Finding the average length of a column as per a particular case in MySQL 
I prefer the length() inside the case:
SELECT u.id,
AVG(LENGTH(m.body)) AS avg_msg_length,
AVG(CASE WHEN m.is_retired = 'Y' THEN LENGTH(m.body) END) AS
avg_msg_length_retired
FROM Users u LEFT OUTER JOIN
Messages m
ON u.id = m.sender_id
GROUP BY u.id;
The 'Y' should be whatever character or string indicates truth.
The problem with your query is that you are mixing character expressions
(is_retired) with numeric expressions (true). Be consistent with the
types.
For instance, this evaluates to false:
select 'true' = true;
But this evaluates to true:
select 1 = true;

Finding the average of double values from the command line? 
You probably meant:
for (int i = 0; i < args.length; i++)
As this is the main logical issue here, there are other (syntactic)
problems that needs to be addressed, that others have mentioned (see
@seanmk's answer, for instance, on the importance of scoping loops).
(Note: this was written before @seanmk's answer was updated with additional
information, when it only regarded the issue of brackets and scoping of
loops).

Finding Average of value based on count of rows in LINQ 
You could just use average:
var average = (from a in db.Reviews
where a.ReviewsRestaurantID.Equals(id)
select a.ReviewsRating).Average();
You could also do it with aggregate like this (if what you really want to
do is more complicated, here is an example implementation of average):
var result = db.Reviews.Where(r => r.ReviewsRestaurantID = id)
.Aggregate(new () { total = 0, count = 0, avg = 0.0 },
(o, n) => {
var result = new () { total = o.total+n.ReviewsRating, count =
o.count+1, avg = 0.0};
result.avg = result.total / result.count;
return result;
}, (r) => r.avg);

UIImage and Finding the Average UIColor of Center Pixels 
You are only iterating the pixels from startPoint to one less of endPoint.
Maybe using
for(int row = yStartPoint; row <= yEndPoint; row++)
// ...
for(int column = xStartPoint; column <= xEndPoint; column++)
will fix it?
Also you will have to adjust your rowPtr to start at your xStartPoint:
const UInt8 *rowPtr = rawPixelData + bytesPerRow * row + stride *
xStartPoint;
Else you will be starting at x = 0 every row.
And your average should be calculated like so:
int numberOfPixels = (yEndPoint  yStartPoint) * (xEndPoint  xStartPoint);
red /= numberOfPixels;
green /= numberOfPixels;
blue /= numberOfPixels;
return [UIColor colorWithRed:red / 255.0 green:green / 255.0 blue:blue /
255.0 alpha:1.0f];

To stop finding running average once the condition fails? 
sub = [767220, 769287, 770167, 770276, 770791, 770835, 771926, 1196500,
1199789, 1201485, 1206331, 1206467, 1210929, 1213184, 1213204,
1213221, 1361867, 1361921, 1361949, 1364886, 1367224, 1368005, 1368456,
1368982, 1369000, 1370365, 1370434, 1370551, 1371492, 1471407, 1709408,
1710264, 1710308, 1710322, 1710350, 1710365, 1710375]
def runningMean(seq, n=0, total=0): #function called recursively
if not seq:
return []
total = total + int(seq[1])
if int(seq[1]) < total/float(n+1) * 0.9: # Check your condition to
see if it's time to stop averaging.
return []
return runningMean(seq[:1], n=n+1, total=total) + [total/float(n+1)]
avg = runningMean(sub, n = 0, total = 0)
print avg
print sub[len(avg):]

Reading a text file of student names and text scores and finding an average 
Oops:
int i =Integer.parseInt ("TS");
This doesn't make sense. What number is "TS" supposed to represent?
Edit: you state:
I know that TS is not a valid number that's why I was trying to cast it
to a number
You can't "cast" letters to a number, again it makes no sense.
You need to read in the Strings in the file and then parse those Strings,
not some letters you make up.
What your code should do is:
read in each line in the file in a for loop
inside this loop, split the String using String's split(" ") method.
Use Integer.parse(...) to parse the 3rd item in the array returned.
So would I use Integer.parse(String [] TS)?
No, this won't even compile since you're trying to pass a String array into
a method that takes a String parameter.

Average of array with two objects 
you can use linq for this, something along the lines of
var average = readings.Average(r => r.value);
Note: Average Computes the average of a sequence of numeric values.
MSDN Link:
http://msdn.microsoft.com/enus/library/system.linq.enumerable.average.aspx

mongoDB  average on array values 
Positional notation in aggregation seems to still be unsupported, check out
this ticket.
As @Sammaye says you'd need to either unwind the array first, or replace
your coordinates array with an embedded lng/lat embedded doc, which would
make this trivial.
Given the array structure, you might unwind and project the lat/lng like
this:
myColl.aggregate([
// unwind the coordinates into separate docs
{$unwind: "$myCoordinates"},
// group back into single docs, projecting the first and last
// coordinates as lng and lat, respectively
{$group: {
_id: "$_id",
lng: {$first: "$myCoordinates"},
lat: {$last: "$myCoordinates"}
}},
// then group as normal for the averaging
{$group: {
_id: 0,
lngAvg: {$avg: "$lng"},
latAvg: {$avg: "$lat"}
}}
]);

Calculate the average of points in a array  Javascript 
Try the following:
function groupAverage(group) {
var sum = 0;
var count = group.length;
for (var i in group) {
sum += parseInt(group[i].split(',')[2], 10);
}
return sum / count;
}

12 month moving average from Java array 
the problem with this code is that it outputs the moving average as the
values converted to double
That is to be expected, since you calculated the averages as doubles. If
you simply want to convert the double averages to integers, then use
Math.round(double); e.g.
System.out.println(i + " " + k + " " +
Math.round(a.avgNumerator[i]));

ECMA5 array methods  Finding the first object of a kind in an array 
There isn't a builtin method for that in ES5.
ES6 is adding Array.prototype.find for this
http://people.mozilla.org/~jorendorff/es6draft.html#sec22.1.3.8
console.log(things.find(getBob));
Here's a polyfill adapted from https://gist.github.com/dcherman/5167353
(function() {
function polyfill(fnName) {
if (!Array.prototype[fnName]) {
Object.defineProperty(Array.prototype, fnName, {
value: function( predicate /*, thisArg */ ) {
var i, len, test, thisArg = arguments[ 1 ];
if ( typeof predicate !== "function" ) {
throw new TypeError();
}
test = !thisArg ? predicate : function() {
return predicate.apply( thisArg, arg

ArrayIndexOutOfBoundsException while calculating Mean / Average values from array of pixels 
You don't show the stack trace (edit: now you do, thanks), which would
indicate which line is throwing the exception.
However at first glance it appears your issue is here:
for (int x = 0; x < width; x++) {
for (int y = 0; y < height; y++) {
int index = 0;
for (int filterX = filterWidth / 2; filterX < filterWidth / 2;
filterX++) {
for (int filterY = filterHeight / 2; filterY < filterHeight
/ 2; filterY++) {
A = (pixels[x+filterX+width*(y+filterY)])>>24 &
0xFF;
R = (pixels[x+filterX+width*(y+filterY)] >> 16) &
0xFF;
G = (pixels[x+filterX+width*(y+filterY)] >> 8) &
0xFF;
B = pixels[x+filterX+width*(y+filterY)] & 0xFF;
...

numpy array: replace nan values with average of columns 
This isn't very clean but I can't think of a way to do it other than
iterating
#example
a = np.arange(16, dtype = float).reshape(4,4)
a[2,2] = np.nan
a[3,3] = np.nan
indices = np.where(np.isnan(a)) #returns an array of rows and column
indices
for row, col in zip(*indices):
a[row,col] = np.mean(a[~np.isnan(a[:,col]), col])

SQL query to compare individual average with a group average 
You don't need the first ; since it is a statement terminator.
Change this :
SELECT Person, Avg(Score) AS PersonAverage FROM TblScores GROUP BY Person
HAVING (((Avg(Score))>(SELECT Avg(Score) AS AverageOfAllScores FROM
TblScores;)));
with this :
SELECT Person, Avg(Score) AS PersonAverage FROM TblScores GROUP BY Person
HAVING (((Avg(Score))>(SELECT Avg(Score) AS AverageOfAllScores FROM
TblScores)));

Finding matching objects in array: array or object 
My guess is you're a Java or C++ programmer because your thinking is
classcentric.
The Ruby way is duck typing. For classification pairing to work, you need
only know if the items in a list respond_to? a type method and a pairedby=.
It would be pretty standard Ruby to implement this operation as a mixin
on arrays.
You should probably not split such simple functionality across two classes
unless there is a need to access the inner function, i.e. pair_with_next.
One reason: By splitting the function you pretty much doom yourself to
O(n^2) performance when O(n) is trivial to obtain. Make one pass. Keep a
queue of A indexes. When you see a B, remove the head index from the
queue. That's the A that matches the current B. Continue until complete.
If the queue is empty, assign nil

Finding a way to create a list of array from another complex array 
use array_merge_recursive for example
$ar1=array('color'=>"green");
$ar2=array('color'=>"blue");
$result = array_merge_recursive($ar1, $ar2);
output :
Array
(
[color] => Array
(
[0] => green
[1] => blue
)
)

Have user enter scores or check grade average in 2 dimensional array? 
Here'a a hard to catch bug in your code:
while (keepGoing);
The correct way to declare a loop is this:
while (keepGoing) {
// body
}
That ; at the end of the loop condition has the effect of creating a loop
without a body, so nothing is being repeated! the code below the loop is
executing exactly once.

Is n operations of O(1) average time each considered O(n) in average? 
Given that you are traversing all your array the second time, yes that is
O(n) * O(1) (and not O(n)+O(1) as previously stated from me) (for hash
lookup in average time), so you are talking about an algorithm of O(n)
complexity .

Finding missing array in array of arrays 
I hope that this helps you,
function findDeselectedItem(CurrentArray, PreviousArray) {
var CurrentArrSize = CurrentArray.length;
var PreviousArrSize = PreviousArray.length;
var deselectedItem = [];
// loop through previous array
for(var j = 0; j < PreviousArrSize; j++) {
var checkArray = PreviousArrSize[j];
// loop through 2nd array to match both array
for(var i = 0; i < CurrentArrSize; i++) {
// look for same thing in new array
if (CurrentArray[i].indexOf(checkArray) == 1)
deselectedItem.push(CurrentArray[i]);
}
}
return deselectedItem;
}

finding if the strings in an array is exists in another array 
Do :
for (int y = 0; y < question.length; y++) {
}
instead of <=. The problem outcomes from the fact you don't have a
question[question.length] element.
Also, I don't see where you declare the y variable.
Update: Here's a complete sample:
String[] questions = {"adorable", "able", "adventurous"};
String u = "able adorable asd";
String[] t = u.split(" ");
for (int y = 0; y < questions.length; y++) {
for (int w = 0; w < t.length; w++) {
if (t[w].equals(questions[y])) {
System.out.print(t[w] + " ");
break;
}
}
}
This prints:
adorable able

How to select subarrays in numpy 1D array with minimal, average and maximal area values? 
For max:
areasplit[argmax(sum(areasplit==0, axis=0)), :]
replace argmax with argmin for min: have you considered there may be
several array meet you criteria?
Example:
>>> from numpy import *
>>> a=array(range(81))
>>> b=split(a, 9)
>>> b#be careful it is a list of arrays not just an array
[array([0, 1, 2, 3, 4, 5, 6, 7, 8]), array([ 9, 10, 11, 12, 13, 14, 15, 16,
17]),
array([18, 19, 20, 21, 22, 23, 24, 25, 26]), array([27, 28, 29, 30, 31, 32,
33, 34, 35]),
array([36, 37, 38, 39, 40, 41, 42, 43, 44]), array([45, 46, 47, 48, 49, 50,
51, 52, 53]),
array([54, 55, 56, 57, 58, 59, 60, 61, 62]), array([63, 64, 65, 66, 67, 68,
69, 70, 71]),
array([72, 73, 74, 75, 76, 77, 78, 79, 80])]
>>> b=array(split(a, 9)) #I prefer to use b.reshape((1,9)

What is wrong with this code? program that outputs minimum, maximum and average of integers in C using Array 
your for loop is wrong
for(i=1; i++;)
this should be
for(i=1;i<5; i++) //because you already scanned a[0].. you need to scan
till a[4]
use avg=a[0]; instead of avg=0;
in for loop you need to write use if (a[i]<min) instead of else
Modified code
#include <stdio.h>
void main()
{
int i,a[5],min,max;
float avg;
printf("
Enter any number : ");
scanf("%d",&a[0]);
max=a[0];
min=a[0];
avg=a[0];
for(i=1;i<5;i++)
{
printf("
Enter any0 Number : ");
scanf("%d",&a[i]);
if(a[i]>max)
max=a[i];
if( a[i]< min )
min=a[i];
avg=avg+a[i];
}

Finding subarray sum in an integer array 
When S is not too large, we can count the distinct sums with one (fast)
polynomial multiplication. When S is larger, N is hopefully small enough to
use a quadratic algorithm.
Let x_1, x_2, ..., x_n be the array elements. Let y_0 = 0 and y_i = x_1 +
x_2 + ... + x_i. Let P(z) = z^{y_0} + z^{y_1} + ... + z^{y_n}. Compute the
product of polynomials P(z) * P(z^{1}); the coefficient of z^k with k > 0
is nonzero if and only if k is a subarray sum, so we just have to read off
the number of nonzero coefficients of positive powers. The powers of z,
moreover, range from S to S, so the multiplication takes time on the order
of S log S.

SQLite select average from one table and update average field from another table using trigger 
To compute the average value of a specific field dynamically, use this
query:
SELECT AVG(value)
FROM table_1
WHERE field = 'field_a';
If you want instead a view that looks like your table_2, you can define it
like this:
CREATE VIEW view_2 AS
SELECT field,
AVG(value) AS average_value
FROM table_1
GROUP BY field;
If you really want table_2 to be an actual table, you could compute the
average values like this:
UPDATE table_2
SET average_value = (SELECT AVG(value)
FROM table_1
WHERE table_1.field = table_2.field);
If you want table_2 to be an actual table, and want to update only those
values that have changed, use a trigger like this:
CREATE TRIGGER update_average_value_after_insert
AFTER INSERT ON table_1
FOR EACH ROW
BEGIN
UPDATE

Finding the first nonNil element in an array 
You can use Enumerable#find:
@group_list.find { x !x["list"].blank? }
#=> first nonnil and nonempty list in group_list

Finding smallest value in array 
array1.Min()
See this
With the Min method we find the minimum element or the minimum value
after a transformation.

Finding result in a PHP Array 
$yourlike is not mysqli_result.
Replace this line
$likearray = mysqli_fetch_array($con, $yourlike);
with this one
$likearray = mysqli_fetch_array($con, $check_like_res);

Finding parent in PHP Array 
Try:
foreach ($arr as $key => $value) {
foreach ($value["children"] as $child) {
if ($child["id"] == $you_look_for) return $key; // or $value["id"]
?
}
}
This  however  will only return the first id of an array containing a
child with id $you_look_for.

Finding index of a value in an array 
Of course it's possible. Computers are amazing.
var positions = [];
for (var i = 0; i < arr.length; ++i)
if (arr[i] === 69)
positions.push(i);
At the end of that loop, the array "positions" will contain all the indexes
of the array where 69 was found.
You could generalize this:
function indexes(arr, value) {
var rv = [];
for (var i = 0; i < arr.length; ++i)
if (arr[i] === value)
rv.push(i);
return rv;
}
and then:
var i69 = indexes(arr, 69);


