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Script for displaying respective WORK days, TRAVEL days and LEAVE days for a particular month
Let me help you figure out: First you need to prepare calendar data set for the month of June Use Pivot separately along with following and for the days of month June: Travel data Work Data Leave Data The pivot will work well on individual columns In order to appear These 3 data sets as one use dynamic query and use union all and also use case statements to appear T- Travel days etc.

Categories : Sql Server

Skipping weekends and splitting days with an event block of 3 days using fullcalender
There is no built in solution to do what you want and a multiple day event can't skip days inside of the interval; so I enjoy to find one, here is my solution! The script work like this; for the given start date I find the correct following two days according to weekends and set three variables with the single dates. For every date I find the number of week and using it I find if I have to create a multiple day event or more events. The most relevant code is: var firstDay = new Date(date.getTime()); while (firstDay.getDay() == 0 || firstDay.getDay() == 6) { firstDay.setDate(firstDay.getDate() + 1); } var secondDay = new Date(firstDay.getTime()); do { secondDay.setDate(secondDay.getDate() + 1); } while (secondDay.getDay() == 0 || secondDay.getDay(

Categories : Javascript

counts days inbetween then add class to those days with nested divs?
You mean something like this? $(function(){ var $class1 = $('.class1'); var $class2 = $('.class2'); var $afterClass1 = $class1.nextAll('.test'); var $beforeClass2 = $class2.prevAll('.test'); var count = $afterClass1.length + $beforeClass2.length; $('.count').html(count); }); http://jsfiddle.net/SAsty/ Edit: Better visualization http://jsfiddle.net/SAsty/3/ Edit 2: Do something like: var $allBetween = $afterClass1.add($beforeClass2); $allBetween.addClass('between');

Categories : Javascript

Query related to getting number of days in between of two days
C# code: int YourVersion() { DateTime dt1 = DateTime.Now; DateTime dt2 = DateTime.Now.AddDays(-10); int daysDiff = (dt2 - dt1).Days; return daysDiff; } int SeniorVersion() { DateTime dt1 = DateTime.Now; DateTime dt2 = DateTime.Now.AddDays(-10); TimeSpan ts = dt2 - dt1; int daysDiff = ts.Days; return daysDiff; } Compiled on VS2013, Release build, decompiled IL: Yours: .method private hidebysig instance int32 YourVersion() cil managed { // Code size 48 (0x30) .maxstack 2 .locals init ([0] valuetype [mscorlib]System.DateTime dt1, [1] valuetype [mscorlib]System.DateTime dt2, [2] int32 daysDiff, [3] valuetype [mscorlib]System.DateTime CS$0$0

Categories : C#

How can I get MySQL records from past 7 days, but only days that have a record, and return each day as a record?
You won't be able to get the same day results back as an array, but you can group it by date, with the titles comma separated: SELECT GROUP_CONCAT(title) AS titles, date FROM test WHERE date > DATE_SUB(CURDATE(), INTERVAL 7 DAY) GROUP BY date; Then in PHP, do something like this: foreach ($results as $row) { echo $row['date']; foreach ($row['titles'] as $title) { echo $title; } }

Categories : PHP

SQL Query to find users with no record within the last 30 days, but with a record within the last 90 days
select distinct(userid) from thetable where recorddate > DATE_SUB(now(), INTERVAL 90 DAY) and userid not in ( select userid from thetable where recorddate > DATE_SUB(now(), INTERVAL 30 DAY) ) I don't know mySQL well, so use the appropriate way for checking if a date is within the last x days I assume that a userid can be in the table multiple times, but you only want them returned once. Hence the "distinct"

Categories : Mysql

divide every row by VBA
You can build the range by building the range string, like this: Range("AL2:AS" & LastRow & ", BC2:BC" & LastRow) Notice that the .Row property of Range returns a Long which is the row number, so you have to declare : Dim LastRow As Long Finally this gives : Sub test2() Dim LastRow As Long Dim myCell As Range LastRow = Range("A" & Rows.Count).End(xlUp).Row For Each myCell In Range("AL2:AS" & LastRow & ", BC2:BC" & LastRow) myCell.Value = myCell.Value / 1000 Next myCell End Sub

Categories : Excel

How to divide by zero without error
You can simply return a NaN or an infinity, for example: return std::numeric_limits<float>::quiet_NaN(); or return std::numeric_limits<float>::infinity(); See std::numeric_limits, from header <limits>.

Categories : C++

Divide datetime from xml
Well given any particular element, you can cast to DateTime: var timeElement = doc.Descendants("TIME").First(); var dateTime = (DateTime) timeElement; You can then use the Date and TimeOfDay properties to split the date from the time of day: DateTime date = dateTime.Date; TimeSpan time = dateTime.TimeOfDay;

Categories : C#

divide div with percentage
That is because of the gap between the two child div elements in HTML code. you need to remove the gap between the two div's to which you are giving display: inline-block. Just remove it. It will work fine. <div class="container"> <div class="col1"> col1 </div><div class="col2"> <!-- removed whitespace --> col2 </div> </div> Working Fiddle For more information go through this link There are many other ways to fix this. which you can find here

Categories : CSS

Divide hex characters
NumberStyles is a bit esoteric but it's how you do it: int offset = int.Parse(textBox10.Text, System.Globalization.NumberStyles.HexNumber); int offset2 = offset / 2; textBox11.Text = String.Format("{0:X}", offset2); Of course, you might need more processing and validation of the user input. Look at int.TryParse and different int sizes (e.g. Int64), too.

Categories : C#

Divide with Javascript
<script type="text/javascript" language="JavaScript"> //is better that add a variable var p=10/5; document.write(p + "<br />"); //Divide 10 by 5 to get 2 //or document.write(float(10/5) + "<br />"); //Divide 10 by 5 to get 2 </script>

Categories : Javascript

multiply by 0.5 rather than divide by 2
It's true that some (if not most) processors can multiply faster then performing a division. But, it's like the myth of ++i being faster then i++ in a for loop. Yes, it once was, but nowadays, compilers are smart enough to optimize all those things for you, so you should not care about this anymore. And about bit-shifting, it once was faster to shift << 2 then to multiply with 4, but these days are over, most processors can multiply in one clock cycle, just like a shift operation. A great example of this was the calculation of the pixel address in VGA 320x240 mode. They all did this: address = x + (y << 8) + (y << 6) to multiply y with 320. On modern processors, this is actually many times slower then address = x + y * 320; So, just write what you think and the com

Categories : C

Divide by Zero Anomaly in PHP
You get an error with the first version, because you have a syntax error. PHP treats the dot in 0. as a decimal point, not a concatenation operator. The correct code would be either: ($x/0) . ">"; // This version is my preference Or: $x/0. . ">";

Categories : PHP

divide two SUM of Two interval
Since Your Query Returns 24 rowsTry Like This Select t.*,(Sum(Case when row<=12 then Index else 0 End)/ Sum(Case when row>12 then Index else 0 End)) as Result from ( SELECT ROW_NUMBER() OVER(ORDER BY [Year] DESC,[Month] DESC) AS Row,[Year], [Month], PCode_9, [Index] FROM tbl08 WHERE PCode = @Code AND (([Year] * 12 + [Month]) <= @CurrentYearMonth) AND (([Year] * 12 + [Month]) >= @FCurrentYearMonth) AND row > 12 <-- ERROR ORDER BY [Year] DESC,[Month] DESC ) t

Categories : SQL

Is it possible to divide a Array in VBA
You can split like this Sub split_array() Dim array1(1 To 2) As String Dim array2(1 To 2) As String Dim array3(1 To 2) As String array1(1) = "Test1" array1(2) = "Test2" array2(1) = array1(1) array3(1) = array1(2) End Sub But I suspect that is not the best way to do it. I think you would do much better using 3 (probably long integer) variables to represent positions in the array. 1 to represent the 1st element, 1 to represent the last element and 1 to represent the mid element. Dim lLowerSearchElement As Long Dim lUpperSearchElement As Long Dim lMiddleSearchElement As Long Dim array1(1 to 999) as string lLowerSearchElement = 1 lUpperSearchElement = 999 lMiddleSearchElement = (lUpperSearchElement + lLowerSearchElement) / 2 You can then check if the if the element is equal to, grea

Categories : Arrays

Divide ul into multiple columns
Just use CSS columns and screw older browsers (they can live with a single column): FIDDLE ul { -webkit-columns: 2; -moz-columns: 2; columns: 2; }

Categories : Jquery

How to divide an array into three different parts?
size has to be an int value. when you get index out of bound exception simply add the size variable in the watch window to validate that you indeed have an integer value for it. Better Round off the size value to become an integer, since division by 3 will not give you integer value when it is not a multiple of 3. You can cast it to integer as well. If your length value is multiple of 3, your code should work fine.

Categories : Java

How to use mako template for divide?
You need to add division to future_imports argument of the Template: >>> from mako.template import Template >>> print Template("${a/b}").render(a=1, b=2) 0 >>> print Template("${a/b}", future_imports=['division']).render(a=1, b=2) 0.5 >>> print Template("${'{0:.2f}'.format(a/b)}", future_imports=["division"]).render(a=1, b=2) 0.50 Quote from docs: future_imports – String list of names to import from __future__. These will be concatenated into a comma-separated string and inserted into the beginning of the template, e.g. futures_imports=['FOO', 'BAR'] results in from __future__ import FOO, BAR. If you’re interested in using features like the new division operator, you must use future_imports to convey that to the renderer, as otherwis

Categories : Python

How can I divide rows with a NULL?
You can do this with correlated subqueries (which work in all databases) or with window functions (which don't work in all databases). Here is the code using correlated subqueries for the Monday columns: select time, (case when (select Monday from t t2 where t2.time < t.time order by t2.time limit 1 ) is null then Monday else 0 end) as Monday, (case when (select Monday from t t2 where t2.time < t.time order by t2.time limit 1 ) is null then (select count(*) from t t2 where t2.time >= t.time

Categories : SQL

How to divide page to sections by DIV?
i think what you want is: <body> <div style="float:right; width: 20ex;background-color:red;inline;width:50%;"> my menu content.... </div> <div style="float:right; background-color:green;display:inline;width:50%;"> <table style="width:100%; border-style:solid;border-width:5px; border-color:yellow;"> <tr><td>some content...</td></tr> </table> </div> </body> try it and tell me if thats what you want

Categories : HTML

How can I divide two HQL Count Results?
You can use a group by clause to express this. Here's how you could do it in Grails: def countByAction = People. executeQuery("select active, count(*) from People group by active")*. toList(). collectEntries{it} println (countByAction[true]) println (countByAction[false])

Categories : Spring

divide the page in three parts using div tag
float:left is your friend HTML: <div id="wrapper"> <div id="first"></div> <div id="second"></div> <div id="third"></div> </div> The CSS: div { display: block; } #wrapper { width: 400px; height:400px; } #first { float:left; width: 33%; height: 100%; background: red; } #second { float:left; width: 67%; height: 30%; background: green; } #third { float:left; width: 67%; height: 750%; background: blue; } Example: http://jsfiddle.net/Vkmq3/1/

Categories : HTML

HTML divide and conquer
I think what you are asking is if you can separate parts of an HTML page into smaller pages, so you can separate concerns. In PHP this can be accomplished by referencing other files by a require() or include(). But I still don't believe this really answers your question. ASP.NET MVC allows you to render partial views within a webpage through `RenderPartial() but you didn't mention anything about using this. You can find more at http://www.asp.net/mvc/videos/mvc-2/how-do-i/how-do-i-work-with-data-in-aspnet-mvc-partial-views

Categories : PHP

Divide two variables returns NaN
toFixed builds a string (for example "0.013"). When you add a number using (c1)+(Km), it gives a string like this one : "0.01339.069145169761036" And dividing a number by a string using v1t / v1b gives NaN. Why are you using toFixed? There doesn't seem to be any good reason to do so. But if you really want to use it, apply parseFloat to the result before using it in a computation.

Categories : Javascript

PHP Multiple divide string with php
If I'm understanding correctly, then this should work: $parts = explode(' || ', $title); //title ... $output = '<span class="title">'; $pos = mb_strpos($parts[0], '#|'); if($pos !== false){ $output .= '<span class="color">'.mb_substr($parts[0], 0, $pos).'</span><span class="no-color">'.mb_substr($parts[0], $pos + 2).'</span>'; } else { $output .= $parts[0]; } $output .= "</span> "; if(isset($parts[1])){ //subtitle ... $output .= '<span class="subtitle">'; $pos = mb_strpos($parts[1], '|#'); if ($pos !== false) { $output .= '<span class="no-color">'.mb_substr($parts[1], 0, $pos).'</span><span class="color">'.mb_substr($parts[1], $pos + 2).'</span>'; } else { $output .=

Categories : PHP

Divide two numbers from two tuples in a bag
If you have preconditions on your data, like "each key has at most 2 tuples", then I'd recommend not using GROUP, which is not designed to handle what you have in mind. Instead, you can SPLIT your dataset in two and then JOIN the pieces back together. This way you can keep each key's tuples straight. For example: SPLIT G INTO typeA IF type == 'A', typeB IF type == 'B'; I = JOIN typeA BY query, typeB BY query; J = FOREACH I GENERATE typeA::query, (float)typeA::count/typeB::count;

Categories : Apache

when/why do we need to divide a class into many classes?
We use OOPs Concept in Android(core java) Application Development. If we split our one class in many class it gives a good sense of maintainability, re-usability, Security and Easy change in Coding during Development. As for example:- Util class for Database handling, Network Class for Internet connection , Dialog class for different type dialog and so... This way we can categories our coding and change or re use it any time. So it is good practice to follow the OOPS concept during Development. Thanks

Categories : Android

Divide the interval [0,1] into (3j-2) subintervals
[Edit hard wrong understanding of OP's goal. Hopefully closer now.] You have N intervals (boxes), where N=(3*j-2). With j=1 you have 1 box with corners at (0,0) and (1,1) Randomly a x,y is generated, each in the range 0.0 to 1.0 Given this x,y find which of N boxes contains this point. Look into each existing box and see if (x,y) is in range. Faster methods exists, but this is a starting point. Sub-divide this box at this point, thus making 3 more boxes. Repeat as desired #include <ctype.h> #include <stdlib.h> #include <stdio.h> #include <memory.h> double drand() { return rand()/(1.0 + RAND_MAX); } typedef struct Box_s { double x0, y0, x1, y1; } Box_t; #define Box_N (303) int Box_Count = 0; Box_t Box[Box_N]; void Box_Init() { memset(Box, 0, size

Categories : C++

How does one divide changes among multiple branches in git?
The problem with git stash and multiple branches is that once it is popped you have to stash again for the next branch. To get around this it is easy enough to just use a temporary branch. git checkout -b temp_branch git commit -a -m 'Changes that will go to several branches.' git checkout W git cherry-pick -n temp_branch (fixup all files here here) git commit -a -m 'Changes for W.' git checkout X git cherry-pick -n temp_branch (fixup all files here here) git commit -a -m 'Changes for X.' git checkout Y git cherry-pick -n temp_branch (fixup all files here here) git commit -a -m 'Changes for Y.' git checkout Z git cherry-pick -n temp_branch (fixup all files here here) git commit -a -m 'Changes for Z.' git branch -D temp_branch

Categories : GIT

How to divide a constant by range(366)?
I'm assuming 0.07 / range(366) should return a list of 0.07 divided by the corresponding element in range(366)? In that case, you can either use a list comprehension: sm1 = [sm + ((0.07/t) * sm)) for t in xrange(1,366)] or, since you applied the numpy-tag to the question, initialize t as a numpy array: t = numpy.mgrid[1:366] sm1 = sm + (0.07/t) * sm then element-wise division will be used as well. In both cases: mind that indexing and hence the range-list, starts at zero, so the first element in these lists will be Inf.

Categories : Python

Trying to divide values from EditText
Instead of goalOutput.setText(finalGoal), write goalOutput.setText(""+finalGoal); (or, as the classy way, Integer.toStirng(finalGoal); ) @Edit Sorry, didn't see that the guy above answered first. He probably did it seconds before me!

Categories : Android

Divide a string into several lines
If you want to build your page this way, consider using (following the example given in Proper indentation for Python multiline strings ) edited to make the xml line show on the page, and make line breaks work: elements = Element.objects.all() my_xml = ('<html type=text/html encoding="utf-8">' '&lt;?xml version="1.0" encoding="utf-8"?&gt;<br>' 'description<br>' 'document title<br>' 'other_infos<br>') for elt in elements: my_xml += elt.title + '<br>' my_xml += elt.desc + '<br>' my_xml += '</html>' return HttpResponse(my_xml)

Categories : Python

0.0/0.0 in C# won't throw "Attempted to divide by zero."?
Unlike operations with integral types, which throw exceptions in cases of overflow or illegal operations such as division by zero, operations with floating-point values do not throw exceptions. Instead, in exceptional situations, the result of a floating-point operation is zero, positive infinity, negative infinity, or not a number (NaN): From Double on MSDN.

Categories : C#

How divide all items in an array by a double?
There are two problems: You're not initializing normal (or indeed creating an array to populate) You're not specifying which element you're trying to set within normal So you want: double[] normal = new double[v.length]; for(int a = 0; a < v.length; a++) { normal[a] = v[a] / sum; } return normal;

Categories : Java

How to divide a json into several parts in AngularJS
There are a couple of ways of solving your problem. Firstly, you could assign a scope value to every part in "items". For instance, assume this is your JSON array: [data1, data2, data3, data4, data5] And in your controller do this: $scope.data1 = items[0]; Do this for every part you need broken up. Keep in mind that the 'data1' part is arbitrary and that you can make up any name you want. Then in your html: <div class="dym" ng-repeat="stuff in data1"></div> Alternatively, you could have your html like this: <div class="dym" ng-repeat="item in items[0]></div> The first method is better if you also have to do some additional processing, and the other is good if the data structure is ready to go already.

Categories : Angularjs

php / mysql divide result displays as 6.2E-5
use type DECIMAL for such values. This would make your values display the way you mentioned.

Categories : PHP

Divide a integer value from map values in Java
Got It work. if(it.hasNext()){ Object id=it.next(); int val=(Integer) map.get(id); int finalval; if(val>score) { finalval= val-score; map.put(id, finalval); } else { val=(Integer) map.get(id); map.put(id, "0"); id=it.next(); val+=(Integer) map.get(id); if(val>score) { finalval=val-score; map.put(id, finalval); } else { map.put(id, "0"); id=it.next(); val+=(Integer) map.get(id); System.out.println(i

Categories : Java

Async Task to divide workload
Be careful with using ref parameters and passing them to tasks on separate threads. I think whats happening is by the time a task looks at the value, its already been changed on another thread. ie your StartWork method is looking at the current value of startRange/endRange, which keeps being changed. Try doing this: for (int i = 0; i < taskCount; i++) { GetRanges(ref startRange, ref endRange, total, i, startIndex); Console.WriteLine("startRange {0} EndRange {1}", startRange, endRange); var tempStartRange = startRange; var tempEndRange = endRange; tasks[i] = Task.Factory.StartNew(() => StartWork(tempStartRange, tempEndRange)); }

Categories : C#

How to divide ASCII code in Powershell
Could you use something like this? #Set value (I had to set a lower value because your value was way too large to process with a Int32 (and 64 I think) $value = 22949672 #Convert (had to multiply because dividing casues to small number to be save correctly(it rounds up and ruins the decoding later) Get-Content . est.txt -Encoding Byte | % { $_ * $value } | Set-Content . est2.txt -Encoding Ascii #Convert back Get-Content . est2.txt -Encoding Ascii | % { [byte]($_ / $value) } | Set-Content . est3.txt -Encoding Byte

Categories : Powershell



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