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MySQL LEFT JOIN with DISTINCT or LIMIT. Need to LEFT JOIN only one value
Try something like this: SELECT TransactionPartnerName, Amount FROM 18_8_ChartOfAccounts LEFT JOIN 2_1_journal ON AccountNumber = DebitAccount LEFT JOIN 18_6_TransactionPartners ON TransactionPartnerName = CompanyName WHERE VatReturnRowNumberForDebitTurnover = '61' AND Amount = 55 GROUP BY TransactionPartnerName;

Categories : Mysql

Distinct left join for foreign id
You can use SQL with subquery, like: SELECT messages.*, max_stamps.max_stamp FROM (SELECT MAX(timestamp) as max_stamp, `from` FROM messages WHERE messages.`to`=$currentUser GROUP BY `from` ) as max_stamps LEFT JOIN messages ON messages.`from`=max_stamps.`from` AND max_stamps.max_stamp=messages.timestamp -i.e. select max timestamps first in subquery, then use them for main table. (update) If you want get maximum id value, then use it in MAX(): SELECT messages.*, max_ids.max_id FROM (SELECT MAX(id) as max_id, `from` FROM messages WHERE messages.`to`=$currentUser GROUP BY `from` ) as max_ids LEFT JOIN messages ON messages.`from`=max_ids.`from` edit: misunderstood id, f

Categories : PHP

SQL query to select distinct rows from left table after inner join to the right table
your query should be like $query = " select t1.id, t1.title, t1.description, group_concat(t2.size SEPARATOR ",") as sizes from products as t1 inner join sizes as t2 on t1.id=t2.id where t1.id in (select t3.id from sizes as t3 where t3.size in (".$size_list .") group by t1.id, t1.title, t1.description " a bit of explanation. When you join two tables, you get all rows from table sizes for all id from table products, so id = 1 joined with 4 records and id = 2 joined with 2 records. So you have to aggregate this numbers into one record.

Categories : Mysql

DISTINCT is not working in join query Cakephp
DISTINCT in SQL Server applies to the entire row you are returning from your result set. So if your data contains, for example: mobileNo workNo homeNo name ... 1234 1234 5678 Joe ... 1234 867 5309 Stacy ... 1 555 5555 Sentinel ... Your DISTINCT will not remove Joe or Stacy, because the entire rows are not equal. On the other hand, if your data contained: mobileNo workNo homeNo name ... 1234 1234 5678 Joe ... 1234 1234 5678 Joe ... 1234 1234 5678 Joe ... 1234 1234 5678 Joe ... 1234 1234 5678 Joe ... 1234 867 5309 Stacy ... 1 555 5555 Sentinel ... Your query would return only a single entry with the name "Joe", because it would return only

Categories : Cakephp

LEFT JOIN is not working for 2 tables
ON topics.posted_by = " . mysql_real_escape_string($_GET['topic_id']) . " users.user_id you know this will produce ON topics.posted_by = 1 users.user_id for example which is invalid SQL syntax. Use WHERE instead ON topics.posted_by = users.user_id WHERE topics.id = (topic_id_variable) P.S.: Using mysql_ is highly not recommended. You should change the API.

Categories : PHP

Left Excluding join not working
You just want to join to the rosters table once: SELECT c.name, c.date FROM clocks c LEFT JOIN roster r ON c.date = r.date AND c.name = r.name WHERE r.date IS NULL This query return all name/dates from the clocks table where there is no corresponding row in the rosters table. Only 1 join (with 2 parts to the join predicate) is necessary.

Categories : SQL

Linq-to-SQL left join on left join/multiple left joins in one Linq-to-SQL statement
I guess I found the solution: var queryOne = from s in db.sprawa join st in db.strona on s.ident equals st.id_sprawy into tmp1 where tmp1.Any() from st2 in tmp1.DefaultIfEmpty() join ss in db.stan_szczegoly on s.kod_stanu equals ss.kod_stanu join b in db.broni on st2.ident equals b.id_strony into tmp2 where tmp2.Any() from b2 in tmp2.DefaultIfEmpty() select new { }; In other words where table.Any() after each into table statement. It doesn't make translation any better but has sped up execution time from nearly 30minutes(!) to about 5 seconds. This has to be used carefully though, because it MAY lead to losing some records in result set.

Categories : Linq

Include 0 when using count() SQL Server Left Join not working
I just figured out the answer to my problem... because I put conditions in the where clause on behalf of the other tables that I joined, it filtered out what I wanted. So I changed the person table to the "driving table" and I took the conditions from the where clause and put them in the join statement as I was joining the tasks table as follows: SELECT convert(nvarchar, COUNT(t.personID)) AS count, CONVERT(decimal(4, 2), 1.0*COUNT(t.personID) / DATEDIFF(DAY, @startDate, @endDate) ) AS average, p.personID, p.firstname, p.lastname, c.companyname FROM Person p LEFT JOIN Tasks t ON t.personID = p.personID AND t.created BETWEEN @startDate AND @endDate JOIN Client c ON c.id = p.

Categories : SQL

Hibernate: where clause in left join is not working properly
When you query for an entity you are always going to receive the fully realized object mapping back. You cannot filter out what goes into the set of events by putting conditions on the query like that. If the query finds a Competition then you get the entire competition. The Competition is always going to have all of its children in there when you access the Set. Put another way that ORM query translates to plain language as: "Find me every competition that has at least one event that starts after the 13th" not "Find me every competition and only include events if they start after the 13th."

Categories : Java

Join Distinct Id on non-distinct id (MySql)
SELECT t.ID, t.val_string, t.val_int, t.val_datetime FROM table1 AS t LEFT JOIN (subquery) AS v_table ON t.ID = v_table.ID Sample fiddle

Categories : Mysql

MySQL left join with multiple rows on right, how to combine to one row for each on left (with the field I want from the right table concated)?
You need a group by: SELECT products.id, products.snipe_price, group_concat(barcodes.barcode) as barcodes FROM products LEFT JOIN barcodes on barcodes.product_id = products.id group by products.id; Without the group by, MySQL interprets the whole query as an aggregation query to summarize all the data (because of the presence of group_concat(), an aggregation function). Hence it returns only one row, summarized on all the data.

Categories : PHP

How to do this query in MySQL which one should I use using left join or right join or inner join?
Left Join will give all results from left table whether or not there are corresponding entries in the right table SELECT * FROM book tb LEFT JOIN author ta ON tb.BookCode = ta.AuthorID LEFT JOIN bookauthor tba ON ta.AuthorID = tba.BookCode; Also, Off topic of the question - shouldn't the AuthorShortN field be in the author table?

Categories : Mysql

criteria uses "inner join" instead "left join" approach by default making my query work not the way I planned
Use left join to achieve this. This should work, but I haven't tested it live. def result = A.withCriteria{ someObject { createAlias("importantObject", "io", CriteriaSpecification.LEFT_JOIN) or{ isNull('importantObject') // conditional 1 eq('io.interestingFlag', false) // conditional 2 } } } Eidt: based on this post: http://grails.1312388.n4.nabble.com/CriteriaBuilder-DSL-Enhancements-td4644831.html this should also work: def result = A.withCriteria{ someObject { isNull('importantObject') // conditional 1 importantObject(JoinType.LEFT) { eq('interestingFlag', false) // conditional 2 } } } Please post your results on both solutions. Edit 2: This is a query that is exa

Categories : Grails

MySql LEFT JOIN within LEFT JOIN
You can try something like this SELECT a.title, a.title_url, q.path, q.medType, q.vpath FROM albums a LEFT JOIN ( SELECT pa.album_id, pa.photo_id, p.path, p.medType, p.vpath FROM ( SELECT album_id, MIN(photo_id) photo_id FROM photos_albums GROUP BY album_id ) pa JOIN photos p ON pa.photo_id = p.id ) q ON a.id = q.album_id WHERE a.user = '$site_user' AND ( a.title LIKE '$keyword%' OR a.title LIKE '% $keyword%') LIMIT 6

Categories : Mysql

Oracle left outer join with is null in JOIN vs WHERE condition (example)
The EXISTS/NOT EXISTS equivalent query is obtained by placing the NULL condition in the WHERE clause, not in the OUTER JOIN clause. By the way this is what we observe from your result: No condition 6403 is not null in where cond 6401 is null in where cond 2 2 rows from the main tables have no corresponding ids in the joined table. When you place the condition in the OUTER JOIN clause, you're telling Oracle to OUTER JOIN your main table to a subset of rows from the joined table. Since c.flh_stato is never null, the condition is redundant and we get the same result as the no-condition query: No condition 6403 is NOT null in OUTER JOIN cond 6403 With the condition c.flh_stato IS N

Categories : Oracle

Join - Left join with a filter on both tables, return zero if no match
Since you want A no matter what, do not include any hard conditions on B in your where clause. All columns of B will be NULL for rows not matched by A. Move those conditions to your JOIN. Like this: SELECT a.[Batch No_], b.[Lot No_], b.[Open], a.[Current Stock], isnull(b.Amount,0) a.[Batch Value] FROM [sb] AS a LEFT OUTER JOIN [ile] AS b ON a.[Batch No_] = b.[Lot No_] and 1 = b.[Open] WHERE (a.[Current Stock] = 1) Then you can use ISNULL or COALESCE in your SELECT clause to force b.amount to be 0 when B is not matched.

Categories : SQL

Left Join table only if another join passes some criteria
Your version 1 doesn't need to be a sub query, you just need () around the INNER JOIN section... SELECT A.* FROM TableA A LEFT JOIN ( TableB B INNER JOIN TableC C ON B.CID = C.CID AND C.PassesTest ) ON B.BID = A.BID I've also put what you have as a WHERE clause in the INNER JOIN predicate. Also, be aware that in neither your sub-query version nor this example, does the entire of TableB necessarily get joined to TableC before being joined to TableA. SQL is compiled to an execution plan, and the optimiser has many options to prevent this from happening. Just because you have it written like that doesn't mean that the RDBMS will follow it blindly without optimising.

Categories : SQL

In SQL left outer join, how to join first occurrence only?
I'm still confused about the reason, but with your modification it is quite easily possible. By left joining the same table grabbing any (the lowest in this case) Misc column, you can get a record for only one of the occurrences of each Cateogory in TableA. Then you can left join TableB only on those rows where a record was found in that grouped subquery. select a.Category, a.Misc, b.Num from TableA a left join ( select Category, min(Misc) as MinMisc from TableA group by Category) c on c.Category = a.Category and c.MinMisc = a.Misc left join TableB b on b.Category = a.Category and mc.Category is not null

Categories : Mysql

Left join using Linq without the "messy" join
In order to follow Craig Stuntz you need to have associations that your logic can follow. So to model your Many-Many you would have an intermediate table that had a 1-Many association back to Questions and Answers. You could use Cost here and have a zero cost for no cost. So Question(QuestionId) 1 -> 1..* Cost(QuestionId) Answer(AnswerId) 1 -> 1..* Cost(AnswerId) Question(QuestionId) 1 -> 0..* Cost(UnitQuestionId) Question(QuestionId) 1 -> 0..* Cost(ReplacementQuestionId) Then in your model create the associations Question (Property = Costs) -- (Property = Question) Costs Question (no mapping) -- (Property = UnitQuestion) Costs Question (no mapping) -- (Property = ReplacementQuestion) Costs Answer (Property = Costs) -- (Property = Answer) Costs This query should match the behaviour

Categories : Misc

LEFT JOIN Significantly faster than INNER JOIN
Try this one. Same result, different approach: SELECT c.ID, p.ID FROM (SELECT Child.ID, JoinTable.ParentID FROM MainTable AS Child JOIN JoinTable ON Child.ID = JoinTable.ID) AS c INNER JOIN (SELECT Parent.ID, JoinTable.ID FROM MainTable AS Parent JOIN JoinTable ON Parent.ID = JoinTable.ParentID AND Parent.SomeOtherData = Child.SomeOtherData) AS p ON c.ParentID = p.ID If it does not help, use cte: ;WITH cte AS (SELECT Child.ID, JoinTable.ParentID FROM MainTable AS Child JOIN JoinTable ON Child.ID = JoinTable.ID) SELECT cte.ID, Parent.ID FROM cte INNER JOIN MainTable AS Parent ON Parent.ID = cte.ParentID AND Parent.SomeOtherData = cte.SomeOtherData

Categories : SQL

SQL INNER JOIN DISTINCT RESULT
Well, the query is returning distinct results. If you were refering to EmployeeId, NAME and Department, then you could try something like SELECT DISTINCT s.EmployeeId, e.NAME, e. Department FROM SelfAnswers AS s Inner Join Employee As e ON s.EmployeeId=e.EmployeeId

Categories : Sql Server

sql nested join inner and left join
You can put a conditional inside count, so I think the following does what you want: SELECT COUNT(DISTINCT (case when tr.hasPatterns = 1 and pt.tracking_id is not null then lg.ip when tr.hasPatterns = 0 then lg.ip end)), tr.name FROM `logs` as lg INNER JOIN `trackings` as tr ON ( tr.server_id = lg.server_id ) AND -- Other conditions LEFT JOIN `patterns` as pt ON ( pt.tracking_id = tr.id ) AND (lg.url LIKE pt.pattern ) WHERE GROUP BY tr.id EDIT: This is returning what you want: SELECT COUNT(DISTINCT (case when tr.size = 0 and pt.tracking_id is not null then lg.ip when tr.size > 0 and l

Categories : Mysql

SQL Query Distinct Inner Join Issue
Possibly: select * from (SELECT DISTINCT Name from Names WHERE Haircolor='Red') uniquenames INNER JOIN (SELECT * FROM Names) allnames ON uniquenames.Name = allnames.Name - it depends on what you actually want to see. UPDATE: SQLFiddle for original answer here. However, a better answer (if using MySQL) might be: select * from Names WHERE Haircolor='Red' group by Name (Note that the specific row returned for each Name matching the hair colour is essentially random.) SQLFiddle here. Further Update: For SQLServer, try: with cte as (select n.*, row_number() over (partition by name order by address) r from Names n WHERE Haircolor='Red') select NAME, HAIRCOLOR, ADDRESS, PHONE, EMAIL from cte where r=1 - this will return the first row (by address, alphabetically) for each name - SQL

Categories : SQL

MYSQL JOIN and GROUP / DISTINCT
If you use WHERE instead of HAVING you would be able to use GROUP BY / DISTINCT and catch 'm all like so: SELECT u.id AS USERID FROM `GEO` g JOIN `LOCATIONS` l ON l.`AREA` = g.`ID` JOIN `USER` u ON l.`ID` = u.`ID` WHERE (6371 * ACOS(COS(RADIANS({$lat})) * COS(RADIANS(g.latitude)) * COS(RADIANS(g.longitude) - RADIANS({$long})) + SIN(RADIANS({$lat})) * SIN(RADIANS(g.latitude)))) <= {$radius} GROUP BY u.`ID` This may be optimized by using an 'early' pre-aggregated filter. I.e. by applying the WHERE on the ON as early as possible. Though this may look 'weird', it can be significantly faster. In your case this would look like this: SELECT u.id AS USERID FROM `GEO` g JOIN `LOCATIONS` l ON (6371 * ACOS(COS(RADIANS({$lat})) * COS(RADIANS(g.latitude)) * C

Categories : PHP

mysql distinct results after join
Move all the nvdproducts checks into a subquery, so you can use SELECT DISTINCT there to prevent duplication. SELECT DATE_FORMAT(published,'%Y-%m'), severity, COUNT(severity) FROM nvdcve LEFT JOIN (SELECT distinct cve_id FROM nvdproducts WHERE (nvdproducts.company='linux' and nvdproducts.product='linux_kernel' AND nvdproducts.version IN (SELECT Kernel from Versions.VIEW_kernel)) OR (nvdproducts.company='apache' and nvdproducts.product='http_server' AND nvdproducts.version IN (SELECT Httpd from Versions.VIEW_httpd)) OR (nvdproducts.company='sendmail' and nvdproducts.product='sendmail' AND nvdproducts.version IN (SELECT Sendmail from Versions.VIEW_sendmail)) OR (nvdproducts.company='mysql' and nvdproducts.product='mys

Categories : Mysql

SQL: JOIN two tables with distinct rows from one table
You can do something like this: In first CTE - assign rankings for VirtualLicenses within the Product groups. In second CTE - assign rankings for Licensce within the Product groups (order by exp. date) And at the end just join the two subqueries on productID and ranking. WITH CTE_VL AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY ProductId ORDER BY vl.VirtualLicenseId ASC) RN FROM dbo.VirtualLicense vl LEFT JOIN dbo.Product p ON vl.ProductName = p.Name ) ,CTE_License AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY ProductId ORDER BY ExpiryDate ASC) RN FROM dbo.License ) SELECT VirtualLicenseId, LicenseId FROM CTE_VL vl LEFT JOIN CTE_License l ON vl.ProductId = l.ProductID AND vl.RN = l.RN SQLFiddle DEMO

Categories : SQL

Get Distinct rows from a result of JOIN in SQL Server
You are getting duplicate because there are multiple photos per album. To get one, use row_number(): SELECT Album_Name AS Album_Name, a.Album_Date AS Album_Date, a.Page_ID AS PageID, p.Image_ID AS Image_ID, p.Image_Small AS Image_Small FROM Album_Name a left outer JOIN (select p.*, row_number() over (partition by Album_Id order by Image_ID) as seqnum from Album_Photos p ) p ON a.Album_ID = p.Album_ID and seqnum = 1;

Categories : SQL

Join two tables and show distinct records
As you are joining on the PART_ID column, the result you are getting is what you would expect to get. For example, there are two C0001 in the LOG-OUT table and these will join to the same C0001 in the PART RETURN table as there is nothing to distringuish the rows in the return table from each other: PART LOG-OUT TABLE -> PART RETURN TABLE C0001 07/29/2013 501 -> C0001 09/04/2013 STORE C0001 10/01/2013 605 -> C0001 09/04/2013 STORE You need another criteria to join on, or you need to join on some more unique identifier in order to achieve the results you are looking for.

Categories : Ms Access

how to select distinct columns in join querys
This selects the distinct values. Is it what you want? SELECT distinct Tracking.GTIM FROM Tracking INNER JOIN Vehicles_Device_Rel ON Tracking.M = Vehicles_Device_Rel.Device_ID WHERE (Vehicles_Device_Rel.VehicalNumber = 'test')

Categories : SQL

Join two tables and display distinct list of column
A join will do: SELECT s.skill_name, CASE WHEN c.candidate_id IS NOT NULL THEN '(X)' ELSE '()' END has_skill FROM skills s LEFT JOIN CandidateToSkillMap c ON s.skill_id = c.skill_id WHERE c.candidate_id = 1 If it joins the right side successfully and thus c.candidate_id will be not null, then it means the person has that skill and you mark it else - don't.

Categories : PHP

How to select distinct pairs in MySQL join (same table) with transitivity?
Group on only one side and take the MIN() of the other: SELECT MIN(a.ID) a, b.ID b FROM mytable a JOIN mytable b ON b.text = a.text AND b.ID > a.ID GROUP BY b.ID See it on sqlfiddle.

Categories : Mysql

How to select only distinct result based on particular creteria from tables using join
This should help get you on your way. You need to use a where clause. SELECT a.callnumber, b.callnumber FROM table a INNER JOIN table b ON a.callnumber=b.callnumber WHERE a.callduration > value AND b.callduration > value.

Categories : Mysql

How can I add a where clause to a right outer join union left outer join?
The where clause goes after the from clause, and the join clauses are part of the from clause: SELECT * FROM public_tips LEFT OUTER JOIN likes USING (id) WHERE public_tips.id=2 UNION SELECT * FROM likes RIGHT OUTER JOIN public_tips USING (id) WHERE public_tips.id=2

Categories : SQL

Left Join vs Inner Join
For simple queries, no. For complex queries, it is possible. In the following query, changing the inner to a left can result in adding back records suppressed by the condition on B. SELECT * FROM A LEFT JOIN B INNER JOIN C ON B.c_id = C.id ON A.b_id = B.id WHERE B.status_xt IS NULL or B.status_xt <> 'foo'; (Note, the order of the ON clauses means that B is joined to C before their union is joined to A. Then the WHERE is applied. This order matters to behavior.)

Categories : Mysql

Zend DB Left Join
The problem is that vid column in your query belongs to two tables, but obviously can store only a single value in the result set. To resolve the problem, make an alias for it, stating explicitly which table should be used: $selectmatchedtime = $this->dbo->select() ->from(array('v'=>'table1')) ->joinLeft(array('vc'=>'table2'),'vc.vid = v.vid') ->columns(array('vid'=>'v.vid'));

Categories : PHP

Mysql one row left join
Your request is wrong. You did not specified an adequate join condition. Your JOIN is actually making a cartesian product of the two tables, that's all. If people.people_list is your foreign key to product_list : SELECT * FROM people INNER JOIN product_list ON (id_list = people_list) -- valid JOIN condition between two tables WHERE ids_list = 1 may be closer to your needs. However, I don't really understand your data structure and your real needs so you'll have to refine the query a bit, I guess...

Categories : PHP

SQL syntax -- LEFT JOIN
It seems you are trying to insert two field1 columns whereas your destination table has only one. It should be: INSERT into destinationTB SELECT sourceTB.field1 FROM sourceTB LEFT JOIN destinationTB ON sourceTB.field1 = destinationTB.field1 WHERE destinationTB.field1 IS NULL; Expand accordingly to every field that should get inserted. If your syntax gets too complicated you can resort to temporary tables too: CREATE TEMPORARY TABLE tempTB as SELECT sourceTB.field1 FROM sourceTB LEFT JOIN destinationTB ON sourceTB.field1 = destinationTB.field1 WHERE destinationTB.field1 IS NULL; INSERT into destinationTB SELECT tempTB.field1 FROM tempTB ; temporary tables do vanish after you complete the queries.

Categories : Mysql

LEFT JOIN 2 tables
Try: SELECT m.fname, m.lname, m.position, COUNT(d.mId) AS shifts FROM members as m LEFT JOIN duty_sched AS d ON d.mId = m.id AND month(d.shift_date) = $month WHERE m.active_mbr = '1' AND m.fname != 'memorial' GROUP BY m.id HAVING COUNT(d.mId)>0 ORDER BY m.lname, m.fname

Categories : Mysql

Left Join in Mysql?
These extra repeated values of StackId are coming from the join, just use DISTINCT to get those only 5 values: SELECT DISTINCT t1.StackID FROM t1 LEFT JOIN t2 on t1.StackID=t2.StackID; SQL Fiddle Demo

Categories : Mysql

How can i have INNER and LEFT JOIN in the same query?
An earlier answer, since deleted, recommended you remove all the parentheses from your query. However Access requires parentheses in the FROM clause when it includes more than one join. Since the problem is with the joins, start with a simpler query which focuses on them only. See whether this query runs without error. SELECT * FROM (T2 INNER JOIN TB ON T2.Col1 = TB.Col1 AND T2.Col2 = TB.Col2) LEFT JOIN T1 ON T2.Col1 = T1.Col1 AND T2.Col2 = T1.Col2 Once you get the joins correct, replace * with your field names and add your WHERE clause.

Categories : SQL



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