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DateTime format wrong
In C# the + operator is overloaded for most system types, just add them together. So you should also just take the Date object from the picker, instead of converting it to a string. Edit: Now the final DateTime will be the result of adding the Date from the RadDatePickers and the Time from the RadTimePickers. DateTime StartDate = Convert.ToDateTime(RadDatePickerStart.SelectedDate); DateTime EndDate = Convert.ToDateTime(RadDatePickerEnd.SelectedDate); TimeSpan StartTime, EndTime; if (RadTimePickerStart.SelectedDate != null) StartTime = RadTimePickerStart.SelectedDate.Value.TimeOfDay; if (RadTimePickerEnd.SelectedDate != null) EndTime = RadTimePickerEnd.SelectedDate.Value.TimeOfDay;

Categories : C#

format string in datetime c# to insert in MYSQL datetime column
Your line: string time = Convert.ToDateTime("10-10-2014 15:00:00"); Shouldn't compile. I can only guess that you don't have DateTime as type of your column in SQL Server, you should modify it to keep DateTime and then pass a DateTime type object, not a string.

Categories : C#

Output format datetime in yii
Your validation rule definition is wrong. If you want to only accept a correctly formatted date from the user, the rule should read array ('time_start, time_end', 'date', 'format' => 'yyyy-MM-dd HH:mm:ss'), This sets up a CDateValidator with the correct date format, which you have to specify not using PHP DateTime conventions but with those of CDateTimeParser.

Categories : Mysql

Using toChar to output a date in W3C XML Schema xs:dateTime type format
Try: select to_char(sysdate, 'yyyy-mm-dd') || 'T' || to_char(sysdate,'hh24:mi:ss') || sessiontimezone from dual; Returns: 2013-08-16T13:00:51+00:00

Categories : SQL

input string not in correct format...when converting a string to datetime...error?
Make sure your input string is using decimal point symbol for your current culture!. If your input string does not match these rules, decimal.Parse throws the Input string was not in a correct format exception If you for instance use the invariant culture: decimal.Parse("17.5", CultureInfo.InvariantCulture) The dot will be the accepted decimal point. You can read more about it over at MSDN There they also mention that the decimal.TryParse method is better suited for invariant culture parsing Also (obviously), make sure your input string is not null, empty, or containing any non-numerical characters (except for the one, optional, dot or comma, depending on your culture)

Categories : C#

Is there a way to find the first string that matches a DateTime format string?
I'm not aware of anything other than DateTime.TryParse (or alternately, a RegEx) for doing this in .NET. I would set up a stream tokenizer, passing only candidate token pairs into DateTime.TryParse (based on some combination of minimum string length, an maybe substring checks for a pair of dashes on token 0 and a pair of colons on token 1, etc. Exact checks would depend on how many date/time formats you're supporting)

Categories : C#

C# DateTime format with input from a string
A DateTime has no format. It just represents a date and a time. If you want to display it in a specific format, convert it back to a string with the appropriate format specifiers: string format = "yyyy.MM.dd HH:mm:ss:ffff"; string eventdatetime = "2013.07.12 15:32:04:4687"; DateTime x = DateTime.ParseExact(eventdatetime, format, CultureInfo.InvariantCulture); var display = x.ToString("yyyy.MM.dd HH:mm:ss:ffff"); Furthermore, zzzz designates the timezone. You want ffff which designates fractions of a second.

Categories : C#

Convert string to DateTime and format
See http://msdn.microsoft.com/en-us/library/system.datetime.parse.aspx public class Example { public static void Main() { string[] dateStrings = {"2008-05-01T07:34:42-5:00", "2008-05-01 7:34:42Z", "Thu, 01 May 2008 07:34:42 GMT"}; foreach (string dateString in dateStrings) { DateTime convertedDate = DateTime.Parse(dateString); Console.WriteLine("Converted {0} to {1} time {2}", dateString, convertedDate.Kind.ToString(), convertedDate); } } }

Categories : C#

Datetime string format alignment
datetime.datetime has format method. You need to convert it str. >>> '{:%Y/%m/%d}'.format(dt) '2013/06/26' >>> '{:>20}'.format(dt) '>20' >>> '{:>20}'.format(str(dt)) ' 2013-06-26 09:00:00' >>> import datetime >>> dt = datetime.datetime(2013, 6, 26, 9, 0) >>> l = [dt, dt] >>> template = "{0:>25} {1:>25}" >>> print template.format(*l) >25 >25 >>> print template.format(*map(str, l)) 2013-06-26 09:00:00 2013-06-26 09:00:00

Categories : Python

String was not recognized as a valid DateTime - Whats wrong?
Because 17/02/2012 is not a valid date, however, 02/17/2012 is. The date will be parsed as mm/dd/yyyy. One option is to use DateTime.ParseExact to parse a date with the dd as the first set of numbers. e.g. var startDate = DateTime.ParseExact("17/02/2012", "dd/MM/yyyy", null);

Categories : C#

Input string was not in a correct format with DateTime
you should always use DateTime.TryParseExact. string[] formats = { "dddd, dd MMMM yyyy" }; //your format here DateTime dt; if (DateTime.TryParseExact(dpLeaveFromStd.SelectedDate.GetValueOrDefault(), formats, CultureInfo.InvariantCulture, DateTimeStyles.None, out dt)) { }

Categories : C#

DateTime format using t-sql string functions in SQL Server query
Well, convert(varchar(25), getdate(), 120) returns: 1 1234567890123456789 2013-08-08 01:43:49 So change: substring(..., 6, 11) To: substring(..., 3, 14) And you'll get: 13-08-08 01:43

Categories : Sql Server

In SQL Server, convert 'mmmm dd,yyy' string to datetime format
While it's not recommended to store your date in string formats, you still could properly convert string to date. When you know exact format, avoid using cast and use convert - see possible formats here. set language english select convert(datetime, 'June 01, 2013', 107) ----------------------- 2013-06-01 00:00:00.000 Conversion from and to 107 format depends on your connection settings. If, for example, your connection language is not english, you could get an error set language norwegian select convert(datetime, 'June 01, 2013', 107) ----------------------- Msg 241, Level 16, State 1, Line 2 Conversion failed when converting date and/or time from character string.

Categories : SQL

I got correct reversed string in method but when i returned into main() it is showing wrong string as output
Try StringBuffer#reverse built-in reverse method. String str= "reverse"; StringBuffer sb= new StringBuffer(str); //reverse String result= sb.reverse().toString(); System.out.println(result); On the other side, the problem in your code is that you have are your class members that should have been method variables, which means you have too many states. Exactly the temp variable is the problem. To fix it, add this line to the beginning of your method: public String revString(String str) { temp = ""; //this line Character ch; A future hint Do not put variables as class members (fields) if you do not plan to use them in other methods/read the by other classes. Class members are used only for states. Localize all your variables inside the method. public static class RevStr

Categories : Java

What's wrong with this format string?
For those still looking for this answer, as the link that Blackbelt posted implies, the correct format for the string would be: <string name="q_title">Item %1$d of %2$d</string>

Categories : Java

How do I convert string date format to datetime date format?
This should do it: SELECT CONVERT(DATETIME, REPLACE('Sept. 23, 2013','.',''), 107) This removes dot in string and converts to datetime format 107. And this returns the string you wanted (MM/DD/YYYY): SELECT CONVERT(VARCHAR(10), CONVERT(DATETIME, REPLACE('Sept. 23, 2013','.',''), 107), 101) For other format types see: http://www.sqlusa.com/bestpractices/datetimeconversion/ and http://www.sql-server-helper.com/tips/date-formats.aspx Edit: It turns out it works for me because of Slovenian locale (Sept.). This one should work in English locale: SELECT CONVERT(VARCHAR(10), CONVERT(DATETIME, SUBSTRING('Sept. 23, 2013', 0, 4) + ' ' + SUBSTRING('Sept. 23, 2013',6,9), 107), 101) As a function.

Categories : Asp Net

Error : String was not recognized as a valid DateTime while converting to date format in c#
Your date string needs to be this: Thu Jul 18 2013 17:39:53 +0000 Whatever is producing your string needs to have the year value after the month and day and before the time, like above. string date = "Thu Jul 18 2013 17:39:53 +0000"; var theDate = Convert.ToDateTime(date); Note: This will produce a valid .NET DateTime object. UPDATE: If you cannot change the string produced, then use the ParseExact method with a custom format, like this: string date = "Thu Jul 18 17:39:53 +0000 2013"; var theDate = DateTime.ParseExact(date, "ddd MMM dd H:mm:ss zzz yyyy", CultureInfo.InvariantCulture);

Categories : C#

convert DateTime to string according to customCultureInfo in G((combination of date and Time) format
try this: DateTime date1 = new DateTime(2008, 4, 10, 6, 30, 0); Console.WriteLine(date1.ToString("G", DateTimeFormatInfo.InvariantInfo)); // Displays 04/10/2008 06:30:00 Console.WriteLine(date1.ToString("G", CultureInfo.CreateSpecificCulture("en-us"))); // Displays 4/10/2008 6:30:00 AM Console.WriteLine(date1.ToString("G", CultureInfo.CreateSpecificCulture("nl-BE")));

Categories : C#

Covert c# datetime format to java datetime format
Your format string doesn't match the input date string : // 2013-07-03T19:16:02.3694 <-- date string static SimpleDateFormat formatter = new SimpleDateFormat("yyyy-MM-dd"); You need to first parse the date string using the SimpleDateFormat with pattern yyyy-MM-dd'T'HH:mm:ss.SSSSSS and then you can format the Date object with dd-MM-YYYY pattern.Remember MM is for months , mm stands for minutes. String formattedDate = new SimpleDateFormat("dd-MM-YYYY").format( new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSSSS") .parse(reportItem.getString("AddedTime")));

Categories : C#

why a string is added in wrong format to the razorview?
Razor automatically html encodes any string so it turns your " into &quot;. To turn off the html encoding you need to use the Html.Raw method (MSDN): <li @Html.Raw(AddClasses())>tekst</li>

Categories : Asp Net

Why am I not getting the output in the string format?
Encode the bytes in Base64 encoding (How do I convert a byte array to Base64 in Java?) Or Hex: Convert from byte array to hex string in java System.out.println( Hex.encodeHexString( bytes ) );

Categories : Java

Not valid datetime error due to wrong fomat of datetime in calender extender
Some Code to catch something like this and don't cause an Exeption: if (DateTime.TryParse(txtDate.Text, out dateValue)) { dr["Date"] = dateValue; } else { Debug.Write("TextBox Value '{0}' isn't a valid datetime.", txtDate.Text); }

Categories : C#

Set format of string in PyYaml output file?
Try using YAML scalar: YAML Scalar import yaml from collections import OrderedDict class literal(str): pass def literal_presenter(dumper, data): return dumper.represent_scalar('tag:yaml.org,2002:str', data, style='|') yaml.add_representer(literal, literal_presenter) def ordered_dict_presenter(dumper, data): return dumper.represent_dict(data.items()) yaml.add_representer(OrderedDict, ordered_dict_presenter) d_temp = OrderedDict(l=literal('hi if x = y: print z ')) d = OrderedDict(yaml=literal(yaml.dump(d_temp))) print(yaml.dump(d)) Output: yaml: | l: | hi if x = y: print z Hope it works for you...

Categories : Python

output format in string builder, jaxb sax
SAX is one way parser - you can only read XML with it. JAXB is a too much unless you want to extensively work with XML. DOM is a good alternative, but only an alternative - StringBuilder for simple XML is simpler and as long as produce the correct XML it is perfect.

Categories : Java

Gets the index of the first String that starts with the target - give wrong output
You claim: My implementations works It doesn't look like it to me, based on the tests. Your code is much more complicated than it needs to be, which is making it hard to find the bug. The problem is that you've got two loops for no reason: while (!found && i < text.size()) //supply condition { for (String s : text) { } } Why have you got both of those loops? You're incrementing i multiple times within the inner loop... You'd probably find it easier to get all the tests to pass if you simplify it: public int getIndex(List<String> text, String target) { for (int i = 0; i < text.size(); i++) { if (text.get(i).startsWith(target)) { return i; } } return -1; } This is one of those cases where a dogmatic i

Categories : Java

Adding date or time in datetime format to another datetime
*This is a method using DateTime:* $begin = new DateTime($start); $finish = new DateTime($end); $difference = $finish->format('U') - $begin->format('U'); // working version $minutesDiff = round(($difference/60), 0); $finalDate = new DateTime(); $finalDate->modify(sprintf('+%s minutes', $minutesDiff)); edit added missing bracket edit2 version without ->diff() method

Categories : PHP

Sql query for CONVERT datetime to a different datetime Format in SQL 2005?
http://msdn.microsoft.com/en-us/library/ms187928.aspx check out see Microsoft's explanation on date formats the one you're looking for is 20 or 120 BTW, you should supply with varchar with a number like this varchar(10)

Categories : SQL

String.format to output correct syntax in Razor
Use MvcHtmlString.Create() From the specs: Creates an HTML-encoded string using the specified text value. In the posted code: MvcHtmlString.Create(String.Format("args.{0} = '{1}'", dynaform.RequiredModelName, dynaform.RequiredModel))

Categories : C#

Python -- TypeError on string format from binary output
Where you have this: def outFormat(raw): You probably want either this: def outFormat(self, raw): Or this: @staticmethod def outFormat(raw): The former if you eventually need access to self in outFormat(), or the latter if you do not (as currently is the case in the posted code).

Categories : Python

Java Format Output to Console / JTextArea with Multiple string values
Change your format string as follows: Add a width specifier to the first format specifier to specify the width of the first column Add a - flag on all the format specifiers to left align the values The updated format string would be "%-40s%-40s%-32s%-32s%-32s%-32s ". See the Format String Syntax for more details. Note that this solution has several limitations: It will only work when you use a fixed width font If any string is longer than the provided width, it will push the rest of the line out and the columns won't line up. The user will not be able to easily manipulate the data (column width, column order, sort order) The user won't be able to easily copy the output and paste directly into a spreadsheet. Alternatives include Using a JTable, which would be more flexible but t

Categories : Java

jquery date picker set date format as 'MM-DD-YYYY' from a string containing datetime
This: 2012-03-06 00:00:00 UTC is not a valid javascript date, so the datepicker can't accept the set of the value. Date object: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date setDate method: http://api.jqueryui.com/datepicker/#method-setDate Get the date in a compliant format, and than set the datepicker in this way. Code: $(document).ready(function () { var dbDate = "2012-03-06"; var date2 = new Date(dbDate); $(".datepicker").datepicker({ dateFormat: 'mm-dd-yy' }).datepicker('setDate', date2) }); Demo: http://jsfiddle.net/IrvinDominin/7ck7D/

Categories : Jquery

How to convert SCORM 2004 session_time format to a usable datetime format in SQL
Just worked out a solution for me. This would need to be put inside a SQL function for me and I would need to finish off the last bit where I decide what format I want. I am only updating around 900 rows and it is a 1 off update so performance isn't an issue. DECLARE @session_time varchar(200) = 'P50Y2M3DT4H5M6S' DECLARE @date varchar(100) = '' DECLARE @time varchar(100) = '' DECLARE @year varchar(20) = '0' DECLARE @month varchar(20) = '0' DECLARE @day varchar(20) = '0' DECLARE @hour varchar(20) = '0' DECLARE @minute varchar(20) = '0' DECLARE @second varchar(20) = '0' -- Remove the P SET @session_time = SUBSTRING(@session_time, 2, LEN(@session_time)-1) -- If we have a T IF PATINDEX('%T%',@session_time) > 0 BEGIN SET @date = SUBSTRING(@session_time, 0, PATINDEX('%T%',@session_

Categories : PHP

asp.net DetailView datetime field format doesn't match the SQL Server format
Check Your PC Date format and enter date of same format in due date if you enters the date time dynamically then use like this DateTime.Now.ToString(yyyy-MM-dd) here yyyy-MM-dd is my date format enter yours format in this and this is for current date you can use it for the date you desired

Categories : C#

Convert Datetime format to varchar format style workaround
Well you can convert both Dates in any format before you compare the two just use any of these: run this and you can select from them, make sure to convert both dates before Comparing Select convert(varchar, GetDate(), 100) as '100 Conversion', convert(varchar, GetDate(), 101) as '101 Conversion', convert(varchar, GetDate(), 102) as '102 Conversion', convert(varchar, GetDate(), 103) as '103 Conversion', convert(varchar, GetDate(), 104) as '104 Conversion', convert(varchar, GetDate(), 105) as '105 Conversion', convert(varchar, GetDate(), 106) as '106 Conversion', convert(varchar, GetDate(), 107) as '107 Conversion', convert(varchar, GetDate(), 108) as '108 Conversion', convert(varchar, GetDate(), 109) as '109 C

Categories : SQL

DateTime to XML format but keep the datatype as datetime
The dateTime object holds the date and time in a way that is independent of any formatting. The output format is chosen when you convert the value to a string. If it comes out as dd:mm:yyyy, that's because it's defaulting to the format used by the country/language configured for your machine. So the answer is, if you want the ISO format (which you refer to as XML format), then the time to request this is at the time you output the dateTime as XML; it's not a property of the date/time value itself.

Categories : C#

Javascript datetime format in database format
dateToString : function (unformatted) { if (!unformatted) { return null; } var year = unformatted.getFullYear(); var month = unformatted.getMonth() + 1; var day = unformatted.getDate(); if (month < 10) { month = '0' + month; } if (day < 10) { day = '0' + day; } return [year, month, day].join('-'); } feel free to add time formatting

Categories : Javascript

how to change date format of datetime format in php
I'd certainly hope that date values aren't actually stored in a textual format at all, any more than numbers are. It's a bit like asking the database to store numbers as hex instead of decimal. You should separate the inherent values within the data from the textual format applied to them when you present them. Normally I'd recommend formatting the data at the client side instead (which typically has more user context) but you can specify a format in the SELECT statement as well: SELECT DATE_FORMAT(StartDate, '%d-%m-%y') FROM SomeTable Likewise when inserting or updating data, I would try to use parameterized SQL so that you don't specify dates as text at all - normally the client library should be able to pass the data on to the database in a native binary format. In general, you sho

Categories : PHP

Get custom datetime format from standard format
Here's some code do get the patterns: var c = new CultureInfo("fr-FR"); Console.WriteLine(c.DateTimeFormat.LongDatePattern); Console.WriteLine(c.DateTimeFormat.ShortDatePattern); Console.WriteLine(c.DateTimeFormat.FullDateTimePattern); The result from a console app is the following dddd d MMMM yyyy dd/MM/yyyy dddd d MMMM yyyy HH:mm:ss

Categories : C#

CASTing a datetime to string if null value - keeping original datetime formatting
Replace cast with convert and appropriate style: Convert syntax & styles, eg: ISNULL(convert(varchar(20), fd.decision_date, 120), 'PENDING') as facility,

Categories : SQL

Getting "TypeError: must be string, not datetime.datetime" in Jinja2 template but I'm using strftime
The problem is that utcnow() returns a datetime.datetime object, not a string. If you check the line number in the exception, it’s likely the strptime call that’s failing—it can parse a string into a date, but it can’t parse a date. Example: #!/usr/bin/env python2.7 import datetime import jinja2 def format_isodate(timestamp): """Format a ISODate time stamp for display.""" date = datetime.datetime.strptime(timestamp, "%Y-%m-%d %H:%M:%S.%f") return date.strftime('%Y-%m-%d @ %H:%M:%S') e = jinja2.Environment() e.filters['isodateformat'] = format_isodate t = e.from_string('{{ change.submit_date|isodateformat }}') print t.render(change={'submit_date': "2013-07-04 20:06:05.088000"}) print t.render(change={'submit_date': datetime.datetime.now()}) The first print of a

Categories : Python



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