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jQuery json Ajax call no longer works after first time (including form submit, setTimeout)
To your ajax request add a cache: false. I had the same problem in my MVC application until setting that to false. You won't find good documentation on it though, it was something I dug up on a obscure website a while back. EDIT: I stand corrected, http://api.jquery.com/jQuery.ajax/

Categories : Javascript

Submit form values with jquery works but unable to submit standard html form after success
It's normal : $("#foo").submit(); This line at the end of your request.done method is triggering the submit of the form, which is probably triggering the AJAX request , which is triggering the request.done ... and so on infinitely :-) What I would do (try) is remove that line, and also remove the event.preventDefault(); statement you've got at the bottom, so that your submit will simply run as usual after you did your AJAX request.

Categories : Jquery

why capybara can't submit directly to put action?
Capybara is for Behaviour Driver Development. Who's behaviour? Human beings. Can a human being patch? Can he put? He can't. Only computers can. Can a human being visit, fill_in, click_button? Yes he can. This is what Capybara for. Bottom line, put computers' actions into unit testing and controller testing, mimic human beings in integration testing by Capybara.

Categories : Ruby On Rails

Django redirects to different view when form action is set to "."
Leave the form action as "" to post to the same url rather than having a . So in this case <form action="" method="post"> {% csrf_token %} {{ form.as_p }} <input type="submit" value="Confirm/> </form>

Categories : Python

How to Make multiple submit action on a single submit FORM?
You don't have to have a physical form on the page to submit to those end points. Post the data when you click your submit button using the jQuery post() function. http://api.jquery.com/jQuery.post/ <input id="email" type="text" name="email" placeholder="email" /> <br /> <input id="blast" type="button" value="GET FREE QOUTE" name="submit" /> post as json: <script type="text/javascript"> $(function(){ $("#blast").click(function(){ var email = $("#email").val(); $.post("pretong_newsletter.html", { newsletter_email: email }); $.post("jason_newsletter.html", { n_email: email }); $.post("register.html", { user_email: email }); }); }); </script> post as string: <script type="tex

Categories : Jquery

jQuery validate still redirects and opens form action path
Quote OP: "jQuery opens my form action instead of submitting the form without changing of page." Syntax errors will block the plugin from functioning and the default form action will happen on submit. Your code... }} submitHandler: function(form){ $(form).ajaxSubmit({ target: '#preview', success: function() { //$('form').find('input[type=text], select,input[type=file]').val(''); // } }); } You have at least two syntax errors inside your .validate() call. 1) Inside submitHandler, un-comment the closing brace, }, for the success callback function of ajaxSubmit(). See my comments... submitHandler: function(form){ $(form).ajaxSubmit({ target: '#preview', success: function() { //$('form').find('input[type=t

Categories : Jquery

How to get form submit button to do update action as opposed to create action
Generally you don't need template for edit form if nothing special. Just use create form and use form_for @instance. form_for will judge the instance and arrange form path automatically. If the instance is not persisted, it will point to #create. If the instance is a persisted object in db, it will point to #udpate automatically.

Categories : Ruby On Rails

html contact form with captcha submit to jquery&php .AJAX captcha validation request without form submit
<form id="RegisterUserForm" name="RegisterUserForm" action="" onsubmit="return submitform();" method="post"> <fieldset style="border: 0;"> <table width="100%"> <tr> <td width="150"> <div class="celebrationContent"> Name:</div> </td> <td class="style1"> <input id="Name" type="text" name="Name" style="border-style: none; background-color: #fffcc4; width: 275px;" /> </td> </tr> <tr> <td> <div class="celebrationContent"> E-mail id:</div>

Categories : Jquery

PHP: 2 forms different action pages, only 1 form action works
You have to change your code like this : <form method="get" action="approve.php?id=<?php echo $row[0] ?>"> <p> <input type="submit" class="btn btn-primary" value="Approve" /> </p> </form>

Categories : PHP

AJAX Form redirects, but supposed to update target?
Apparently my jqueryval bundle was not being rendered in my _Layout. I assumed since it was a default feature of MVC, it would have done so. Such is not the case. Be wary of which bundles are being rendered in your layout!

Categories : C#

Howto submit JSF ajax field during form submit
Regarding the <h:inputText> ajax behaviour: use <f:ajax> with the default event valueChange, which is the default event for all input components. This is indeed equivalent to omitting the event attribute: <f:ajax render="@this" /> Regarding the <h:commmandButton> component, don't forget to specify the execute attribute of <f:ajax>: <f:ajax execute="@form" /> otherwise it will default to @this, therefore rendering vane your effort.

Categories : Ajax

jQuery .submit() Not handling my form, instead the form action is taken
You need to prevent the default action, which is form submit. This can be done by using e.preventDefault() You can read more about it here $(document).ready(function() { $('#artist_signup').submit(function(e) { e.preventDefault(); $("#artist_message").html("<span class='error'>Adding your email address...</span>"); $.ajax({ url: 'inc/store-address.php', data: $('#artist_signup').serialize(), success: function(msg) { $('#artist_message').html(msg); } }); }); });

Categories : Jquery

How do I get the form submit alert to cancel form action?
http://www.html-form-guide.com/php-form/php-login-form.html this might be what you're looking for.

Categories : Forms

How to load a form using ajax, validate it then submit it using ajax?
you need to check the value of the plugin method valid so you need this if ($form.valid()) { // do stuff } not this if ($form.valid) { // always true, as presence of the plugin method is 'truthy' }

Categories : Jquery

Form validation error handling of Struts 1.3 after submit the form with Ajax call
As far as you stay on the same page when doing ajax call you could always return response via messages but doing it as success, not fail. You have also to turn validation framework off and use commons validator utils to perform validations by hands.

Categories : Jquery

Two form submit on same page, only the first one works. JQuery
Change the below, at the moment it's looking for the first input on the page, this will look for the first input within the form that's actually been submitted. var searchTerm = $("input:first").val(); To var searchTerm = $(this).find("input:first").val();

Categories : Javascript

$_GET PHP form variable AJAX check 404 then submit form
Firstly, if you don't have to use a string for your data, don't. You can use an array like so: $.ajax({ type: "POST", data: {'id': theid }, Which is cleaner and more maintainable. As for your question, your code is a little unclear, but what you probably should do is return false at the end of the submit() event to prevent the form from submitting, and then in the AJAX event, if it's cleared for submission, do a $('#getid').submit(). You may have to set some kind of flag (a hidden input or a data attribute) that you check on to avoid the AJAX-triggered submit from checking again, resulting in an infinite loop. A note here: 404s should cause the error() callback in the AJAX handler to fire, so a 404 won't trigger the success callback you have set up.

Categories : PHP

I want to delay a form action, but still have it submit before I redirect
I think what you want to do is to submit the form via ajax (using something like jquery form plugin http://malsup.com/jquery/form/), and then do your redirect from the success callback.

Categories : Jquery

Display a hidden DIV after a form submit action
$('form').submit(function(e){ $('#doutput').hide(); e.preventDefault(); // Or with: return false; }); Here in your script you are spelling doutput. replace it with output and to show use .css() function and define display: block !important; because you have displayed it in your inline style so to override this you need to set !important. Alternatively, define display: none; in the stylesheet instead of using in inline style and do the rest without setting !important

Categories : PHP

Javascript Form Submit with Email Action?
Since you've tagged the question php, have a look at php's mail function. http://php.net/manual/en/function.mail.php $to = 'you@domain.com'; $subject = 'Contact Form'; $message = '...' //concatenate the $_POST (or $_GET) variables to create this message mail($to, $subject, wordwrap($message, 70, " "); This function requires that your server has a properly configured to send mail - see the php documentation for requirements: http://www.php.net/manual/en/mail.requirements.php

Categories : PHP

php contact form submit just takes me to action URL
Your issue is with this line: if(isset($_POST['email'])) { Your form has no input with the name email therefore this test will never be true and the entire script is inside this condition. You are submitting $_POST['first_name'] or $_POST['telephone'] you should check if one of those two isset.

Categories : PHP

Different action on submit a form depending on input value
You'll want to use javascript to evaluate the contents of the text box. Depending on the value, change the action of the form then submit the form via javascript. You'll have to change your submit button to a regular button with an onClick event though. JavaScript: function EvaluateForm() { if( document.getElementById('searchText').value == 'A' ){ //submit to A document.ajaxSearchFrm.action = "myurlA.com"; } else{ //submit to b document.ajaxSearchFrm.action = "myurlB.com"; } document.forms["ajaxSearchFrm"].submit(); return false; } HTML: <form name="ajaxSearchFrm" action="" method="GET"> <input type="text" id="searchText" name="searchText" style="width:200px;">&nbsp;&nbsp; <input type="button" valu

Categories : HTML

how to include two submit buttons for a form with different action
Buttons are only added to the $_POST when and if they are pressed, and as you can only press one button at a time, you can just do this or something like it:- if ( isset( $_POST['download'] ) ) { do_dowload_stuff(); } if ( isset( $_POST['email'] ) ) { do_email_stuff(); }

Categories : PHP

jQuery submit form with click event with new action
html <input type="button" value="download" id="dwnld"/> js $('#dwnld').click(function(){ var form = $(this).closest('form'); form.attr('action',form.attr('action')+'.xls').trigger('submit'); }); or HTML <form name="test" action="test/test_new" id="formID"/> <input type="button" value="download" id="dwnld"/> js $('#dwnld').click(function(){ form=$('#formID') form.attr('action',form.attr('action')+'.xls').trigger('submit'); });

Categories : Jquery

How to maintain popup window after submit action form?
Use struts2-jquery plugin <%@ taglib prefix="s" uri="/struts-tags"%> <%@ taglib prefix="sj" uri="/struts-jquery-tags"%> <html> <head> <sj:head/> </head> <body> <div id="dialog-form"> <s:form action="product" method="post"> <textarea id="TextArea" name="productNbr"><s:property value='productNbr'/> <sj:submit method="finder" value="Search" /> </s:form> </div> </body> </html>

Categories : Jquery

Change form action based on submit button
There are two typos: obtn instead of obutn oEbtn instead of oEbutn Another suggestion is to use closest("form") to get the form that contains the clicked button. $(".obutn").click(function() { $(this).closest("form").attr("action", "/shop/products.php"); }); $(".oEbutn").click(function() { $(this).closest("form").attr("action", "/shop/extras.php"); }); $("form").on("submit", function () { alert($(this).attr("action")); }); JSFIDDLE

Categories : Javascript

Double action on HTML form submit button
Perhaps submit by AJAX first to the local site, then -- on success -- submit the form & navigate them whole page to the other domain? With jQuery: <form id='form' method='post' action='http://remote.website.com/send-data-here'> <input ...> <input ...> ... <button type='button' onclick='doubleSubmit();'>Submit</button> </form> <script type='text/javascript'> var LOCAL_URL = "/myForm-receiver.php"; function doubleSubmit() { var data = $('#form').serialize(); $.post( LOCAL_URL, data, new function(response){ // Successfully posted by AJAX to Local Website; // -- now POST the form to the destination site, // -- & navigate to that result page. $('#form).

Categories : HTML

Submit form data to an action as a typed viewmodel
In you Jquery Doaction() function . Prepare the viewmodel as follows. var model={ Texting:$('#IdForInputText').val(), Car:$('#IDforSelectList').val(), IsChecked:$('#IDForCheckBox').is(':checked'), } or var model={ Texting:$('input[name="Texting"]').val(); Car:$('select[name="Car"] option:selected').val(), IsChecked:$('input[name="IsChecked"]').is(':checked'); } then use JSON.stringify(model) Hope it helps .Leave comment if not understood

Categories : Asp Net Mvc

Submit an AJAX FORM from within an AJAX Success
In s.php the statement: <input type="hidden" name="mid" value="<?php echo $result['id']); ?>" /> Should be: <input type="hidden" name="mid" value="<?php echo $result['id']; ?>" /> //remove extra bracket In your javascript code in s.php there are some typos: data: $(this).closest("form").serialize(); // here should be comma not semicolon After return false you should close the script properly } should be });. And since you are trying to submit the dynamic content $(".sform").submit(function () will not work. You should use on for dynamic contents. So the correct script would be: <script type="text/javascript"> $(document).on('submit', '.sform', function () { $.ajax({ type: 'POST', url: 'sx.php', data: $(this).closest("for

Categories : PHP

PHP Form with 2 Submit Buttons, Conditional Works, but no Header Redirect
Check out here. http://php.net/manual/en/function.header.php Use the header with the location as like this header('Location: http://www.example.com/'); header('Location:http://www.mynextbit.com/authenticate/register.php'); It should work. Thanks

Categories : PHP

With/Without Javascript form submission using ajax or normal form action
You will have to have 2 versions of your site and redirect accordingly using : <noscript> <meta http-equiv="refresh" content="0;url=noscript.html"> </noscript> OR Wrap your form in your <noscript> tags, and if javascript is enabled disable that form-

Categories : PHP

Ajax prevent form action and post form data
A quick thing i noticed. form = $(this) //it is holding submit button, not the form emailcode = form.serialize(), formUrl = form.attr('action'), //there is no attribute `action` to select because form is holding submit button formMethod = form.attr('method'); //similarly, there is no attribute method change your form selector to: form = $('#emailForm')

Categories : PHP

Form to submit file to controller upload action in rails
You need to use params. That where all the vars are stored. Like so: params[:file] But for using file upload (thats slightly different) have a look at the docs http://guides.rubyonrails.org/form_helpers.html#uploading-files

Categories : Ruby On Rails

Submit form on my asp.net mvc view and the url does not show the controller and action.....How can those be shown?
The URL is myWebsite/myApplication/ after the form is submitted because you likely have the default route: routes.MapRoute( name: "Default", url: "{controller}/{action}/{id}", defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional } ); When a URL is generated in MVC the routes are used to construct the URL based on the values provided. If the values provided match the default values in the route than they will not appear in the URL because they are unnecessary. If you want the values to show in the route than remove them from the defaults. However, doing so will mean that a request to myWebsite/myApplication/ will no longer find your Home controller and Index action.

Categories : Asp Net

Call a Struts 2 action using ajax, which write a string directly to the response does not return the string
Instead of using ServeletActionContext.getResponse().getOutputStream().print("sample string"); return null; use this code PrintWriter out = response.getWriter(); out.write("sample string"); return null; This should work.

Categories : Java

PHP how to form submit using ajax
if you have more than one form on the page, you need to change: $('form').serialize(), to: $(this).serialize(), Otherwise it will include fields from all the forms in the parameters to this script. I'd also recommend that the PHP echo something to indicate whether it was successful or not, which the AJAX success function can then display. You should also sanitize the inputs to the script, and convert from the mysql_xxx functions to mysqli_xxx or PDO, preferably using parametrized queries.

Categories : PHP

Submit form via Ajax
You have missed + symbols in the #65 line Should be var dataString = 'firstname=' + firstname + '&lastname=' + lastname + '&email=' + email + '&parent_pin=' + pin + '&login=' + login + '&passwd=' + passwd + '&user_type=' + user_type; Please read http://en.wikipedia.org/wiki/JavaScript_syntax Remove $(function () { in .button click handler. Now it just registers a handle on button click but not executes it

Categories : Javascript

How can I change a form submit action from displaying an alert popup to redirecting to a new page?
You can try to replace the last line alert('We have received your request. Thank you!'); with window.location = "http://example.com/"

Categories : Javascript

AJAX form submit Codeigniter
are you returning true to who ? the message you echo will go back to the client side wich is the $_POST['name'], but the return true in your php code will bi there at the server side. Speaking of which in my opinion since you are using codeigniter , you should use $this->input->post('name'); instead of the pure php post server variable.

Categories : Jquery

jquery form submit using ajax
Use that: $("#loginForm").submit(function (event) { var url = < url > ; $.ajax({ type: "POST", url: url, context:this, //setting context on form data: $("#loginForm").serialize(), // serializes the form's elements. success: function (data) { if (data == '0') $("#loginErr").show(); else if (data == '1') this.submit();//use js submit event, not jq. We need to manually submit it now that we know its successful } }); event.preventDefault(); //Stop the form submitting straight away });

Categories : Jquery



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