w3hello.com logo
Home PHP C# C++ Android Java Javascript Python IOS SQL HTML videos Categories

Array doubles in size if a struct defines both its uint16_t words and uint8_t bytes

Instead of an array of 2 bytes, use a structure of 2 bytes:

// Two bytes in a 16-bit word
typedef struct{
    uint8_t     lsb;    // As uint8_t, LSB
    uint8_t     msb;    // As uint8_t. MSB
} two_bytes_t;

typedef union {
   uint16_t u16;   // As uint16_t
   two_bytes_t  u8x2; // As 2 each of uint8_t
} my_array_t;

my_array_t my_array[1]; // 1 word array, for

my_array[0].u8x2.msb = 1;
my_array[0].u8x2.lsb = 2;

The XC16 compiler correctly allocates only 2 bytes for each element, and the debugger correctly shows the individual bytes.

Categories : C

Related to : Array doubles in size if a struct defines both its uint16_t words and uint8_t bytes
Fastest way to concatenate two JS uint8 arrays to a uint16 array?
Assuming both Arrays have the same length, use a for loop with the bitwise left shift operator <<; var arr8A = [2, 3, 4], // example arr8B = [5, 6, 7]; // code start var arr16 = new Uint16Array(arr8A.length), i; for (i = 0; i < arr8A.length; ++i) arr16[i] = (arr8A[i] << 8) + arr8B[i]; arr16; The reverse is similar but you use the bitwise zero-fill right shift operat

Categories : Javascript
Combine multiple uint8 and uint16 into 1 byte array
You can use a ByteBuffer as follows: ByteBuffer buf = ByteBuffer.allocate(8); // Depending on the device you may need to include the following line // buf.order(ByteOrder.LITTLE_ENDIAN); buf.put((byte)16); // (# days in month) buf.putShort(450); // (distance walked) buf.putShort(334); // (distance ran) buf.putShort(800); // (steps taken) buf.put((byte)4); // (number of users) byte[] byteArray

Categories : Java
Trying to pack a uint16 into 2 bytes of a byte array C#
C# has things for doing this already.... BitConverter.GetBytes(opcode); Documented here :- http://msdn.microsoft.com/en-us/library/fk3sts66.aspx

Categories : C#
Behavior of cout << hex with uint8 and uint16
uint8_t is an alias for unsigned char. You're essentially printing a character with the value 0xab, which might be an invalid character depending on your encoding. This would be solvable by casting it to another integer type, converting its value to a string in advance or writing some sort of a wrapper class that implements std::ostream& operator<<(std::ostream&, const ClassName&

Categories : C++
size of uint8, uint16 and uint32?
It's quite unclear how you are computing the size ("the size in debug mode"?"). Use printf(): printf("the size of c is %u ", (unsigned int) sizeof c); Normally you'd print a size_t value (which is the type sizeof returns) with %zu, but if you're using a pre-C99 compiler like Visual Studio that won't work. You need to find the typedef statements in your code that define the custom names like u

Categories : C
© Copyright 2018 w3hello.com Publishing Limited. All rights reserved.