Maximum Likelihood, Matlab 
Regarding the presence of several maxima: this issue will occur when
dealing with a function that is not convex. It can be partially solved
by multistart optimization, which essentially means that you run the
simulation multiple times in order to find as many maxima as possible
and then selecting the 'highest' maximum from among them. Note that
this does not guarantee global optimality, as the gl

MATLAB avoid matrix wrapping in command window 
You could do fprintf([repmat('%f ', 1, size(c, 2)) '
'], c');, which gave this output:
0.000000 0.818064 1.054641 0.342287 0.668041 0.717356
0.597756 0.804045 0.650459 0.815819
0.818064 0.000000 0.778921 0.485276 0.322136 1.157594
0.833495 0.363079 0.185730 0.060130
1.054641 0.778921 0.000000 0.917058 0.529164 0.815812

MATLAB: Error in fig2texPS 
This might not be the answer you are looking for, but there is the
marvelous matlab2tikz that does the job of conversion of figures quite
nicely, which you could use as an alternative to fig2texPS.

substitute the derivative of a function in a symbolic expression 
MATLAB interprets that you are doing a nested index call. It thinks
that you are doing D(x), then whatever result of this you are indexing
into the array with t. What you should do instead is nest a diff(x,t)
call inside of the second parameter of subs, then do your
substitution. Therefore:
subs(ans, diff(x,t), 3);

How to use MATLAB functions in Visual C++? 
You can access MATLAB from Visual Studio and Eclipse through the
MATLAB engine interface. As long as you MATLAB installed you just
need to set the right paths in your project settings and link in 3
library files.
Here is a link to the description and setup.
http://www.mathworks.com/help/matlab/matlab_external/introducingmatlabengine.html
http://www.mathworks.com/matlabcentral/answers/100603

Size of cell elements 
Store the counts of the DataCell into an array, then "nomalize" it:
data_counts = cellfun(@(x) size(x,1), DataCell);
prior = data_counts / sum(data_counts(:));
The data_counts(:) is just a funny way of summing all the elements of
data_counts, no matter what shape they're in.

Updating Waitbar throws error while using matlabpool 
I think the thing you did 'wrong' was to use a waitbar inside a parfor
loop haha. But seriously I'm afraid that's because iterations are not
executed in order inside a parfor loop so using a regular waitbar is
prohibited because of the way information is shared between the Matlab
client and the workers executing the loop. Even if you did not write
matlabpool('open',4) MATLAB would have opened it s

Why am I getting an error when trying to use vertcat? 
You can only concatenate vertical arrays (of type string) if they are
the equal size i.e. the rows and columns must be identical. A similar
question was answer here 
http://math.stackexchange.com/questions/449791/whydoikeepgettingavertcaterrorinmatlab.
May be this will help you understand what you are up against?
A tip for you would be to pad the difference using whitespace " "?
This w

Creating new matrix out of one column by order of two other columns 
You can use this method
[~,J1,K1] = unique(A(:,1));
[~,J2,K2] = unique(A(:,2));
sz = [numel(J1) numel(J2)];
B = nan(sz);
B(sub2ind(sz, K1, K2)) = A(:,3);
first use unique to gather the unique items and their indices in the
original column. The size of B is determined by number of unique
elements in first and second column of A.
Now use linear indexing (obtained using sub2ind) to put the values

Normalized Image Histogram 
I assume you use the mean of the three components instead of the
function rgb2gray because it has some advantages in your case.
(rgb2gray does something similar: it uses a weighted sum).
Subtracting the minimum and dividing by the maximum doesn't convert
your image to binary. It will only scale all values to the range
(0,1), which is the case in your example. This only means that all
values are

Change figures into ppt slides 
Break your code into sections, each section of your published code
will get its own slide. This really should be mentioned in the
documentation but I don't see it.
Compare the publishing outputs from the following:
% One Slide
x = 1:10;
y = 1:10;
h.f1 = figure();
plot(x,y);
h.f2 = figure();
plot(x,y);
vs
%%
% 3 Slides
x = 1:10;
y = 1:10;
%%
h.f1 = figure();
plot(x,y);
%%
h.f2 = figure();

Creating variable names using cells from an array in Matlab 
You might want to consider using T = readTable('mydatafile.txt'). This
allows you to load a file with seperate columns and access those
colums using their column name, for example like this:
T.MyFirstColumn. See the manual on readtable for some examples.

Matlab handling values after getting them in edit text 
MATLAB will generate a callback function for your "run" button in the
mfile of your GUI:
function yourpushbutton_Callback(hObject, eventdata, handles)
where handles is a structure containing all handles of the GUI. You
can get the parameters from the edit text fields and call your
function in this callback function. To get the text, use
text = get(handles.edittext1,'String');

How to write a inline function which will accept two arguments in MATLAB 
While its probably not what you want, I think this is one situation
where I would use a for loop, as nchoosek only accepts an integer for
its k value:
nCk = @(n,k)(nchoosek(n,k));
n = 3;
for k = 1:2
disp(nCk(n,k));
end
Though if you do it this way, then the inline statement is likely
redundant, so it could be reduced to:
n = 3;
for k = 1:2
disp(nchoosek(n,k));
end

How to acquire external analog input in matlab using audio line in? 
It's possible to use the method you mentioned, but be careful with
signal strength. I used to connect a laptop's speaker output to a mic
input, and record waveform of mic. The waveform was perfect as long as
speaker output fell into the right range (only 1/10 of its max
amplitude generated by laptop roughly). So I would suggest you start
from very low amplitude, for example 50 mV, and see what you

How to change image pixels values? 
It appears you only want to change the image values based on the y
coordinate, so create a new matrix y like this:
y = (1:height)' * ones(1,width);
where height and width are the size of your image:
[height, width] = size(v);
then create your image v:
v = a.*(y.^2) + b.*y + c;
This will work if a, b, and c are single values or matrices with the
same size as y.
Hopefully that is what you

MATLAB calculating distances in a loop 
Change your coord assignment to the following:
coord = [p1; p2];
The way you have it, it is storing all of the x, y pairs on the same
row, as a 1x4 matrix. The above method stores it as a 2x2 matrix and
pdist gives an answer.

Piecewise constant surface in MATLAB 
You can just use logical indexing:
x = 2:.01:2; y = 15:15;
[X,Y] = meshgrid(x,y); %// Make domain
h2=zeros(size(X));
h2(5<Y & Y<10 & 0<X & X<1)=1;
h2(0<Y & Y<5 & 0<X & X<1)=1;
h2(5<Y & Y<0 & 0<X & X<1)=1;
This statement: 5<Y & Y<10 & 0<X & X<1 returns
a matrix of 1's and 0's where a 1 means that

segregating elements and its index from matrix 
You can do this fairly easily using max:
A = [NaN 0.9 0.8 0.7; NaN NaN 0.7 0; NaN NaN NaN NaN];
[max_val,max_ind] = max(A,[],2);
max_ind(isnan(max_val)) = size(A,2);
The second output of max is the index of the maximum value. By default
it will ignore NaN values, unless every value is NaN, in which case it
returns 1. The 3rd line of this snippet simply finds values where the
maximum value is Na

Matlab index with specific values using loop 
Not sure exactly what you are trying to achieve, but I think that you
can fix your loop as follows:
entries = 3;
X =zeros(20,1);
for ni = 1:entries
n = input('Determine value for case :');
X(n) = input('Determine position:');
end

Matlab: Incorrect estimates returned by fminsearch 
Your problem does not seem to be convex. This means fminsearch will
find a local minimum rather than a global minimum, and thus your
result will be dependent on your initial estimation. You can check
this by altering your theta0 value to for example
theta0 = 0.99*ones(3,1);
Which yields completely different results.
One way of working around this problem is using a Monte Carlo method,
which b

MATLAB: solving symbolic matrix 
This question has no need for any symbolic mathematics. Your A1 and
A3 matrices are defined numerically. All you have to do to find the
entries in A2 is to invoke the inverse operator () between A1 and A3.
Specifically, if you are given:
A1 * A2 = A3 ,
to find A2, you would do:
A2 = A1^{1} * A3
You would find the inverse of A1 and multiply this with A3. You can
easily do this in MATLA

How can I (efficiently) compute a moving average of a vector? 
The conv function is right up your alley:
>> x = 1:8;
>> y = conv(x, ones(1,5), 'valid')
y =
15 20 25 30
Benchmark
Three answers, three different methods... Here is a quick benchmark
(different input sizes, fixed window width of 5) using timeit; feel
free to poke holes in it (in the comments) if you think it needs to be
refined.
conv emerges as the fastest approach;

Stopping criteria matlab iteration 
Well, somehow you need to compute the 'error' you are doing in each
iteration. In your case it would be something like this:
iter = 0;
tolerance = 1e6;
error=1;
x=F(x);
while(error>tolerance)
x2=x;
x=F(x);
error = xx2;
iter= iter + 1;
end
Note how at the beginning the error is set to 1 so we make sure it
goes inside the loop. We also compute the first instance

How can i write bits to a file in matlab 
No, file operations are inherently byteoriented. You may not write
partial bytes out. You need to concatenate all the bits into a string
of bytes, and write that string out. The code might look something
like this:
allbits = cat(2, V{:,3}); % concatenate all bits into one giant
binary string
npadding = 8  mod(length(allbits), 8); % number of bits needed to
produce an even multiple of 8
if(

MATLAB How to move a menu to center of screen 
A possibility would be to copy the content of the menu.m file into a
new function, rename it and add this line:
movegui(menuFig,'center');
on line 229. Although I must say that it might be illegal or be
against the terms of service...if that's the case I'm not even sure I
should propose this. Anyhow by typing edit menu in the command window
one can see that the function simply creates a figure

Failing to create an algorithm for a probabilistic simulation 
The sequence you are trying to generate is called a Markov chain and
you can generate one with the help of a transition matrix. The
transition matrix is an NxN matrix (where N is the number of possible
states, four in your case) where the ith row and jth column tells
you the probability of going from state i to state j. Naturally, the
rows of the transition matrix must sum to one. For example, a

Understanding output of cylinder function 
The cylinder surface is not a function, so each (X,Y) pair is
corresponding to different Z values (in your case  0 and 1). If you
look at the value you are getting, you will notice that for X and Y
you are getting the same data in both rows, for Z you will get
different rows.

showing how numerical solution coming close to the real selution 
I do not understand many things in your code, e.g. why BisectionM has
two identical outputs under different variable names (sol, Roots),
moreover only one output is used throughout the main function. Besides
here is my guess what you might want:
The figure shows how the numerical solution converges with respect to
iteration number. For this you have to store the iteration results in
a vector (s

How to store the 2D image pixels into 1d array? 
In your code, the quickest way (though not necessarily the most
efficient, but most compatible with your code...) would be to allocate
a 2D array and populate this array at each iteration. Referencing my
previous post to you, the total number of times this loop iterates is
(e3) x (f3) times. Therefore, allocate a 2D array like how you said
in your post. Only this time, replace count with (e3

installing libsvm on Mac (OSX 10.9.2) 
I think the following answer from the matlab support might be helpful
(http://www.mathworks.com/matlabcentral/answers/103904caniusexcode5asmycorccompilerinmatlab81r2013aormatlab82r2013b):
The Mac OS X 10.7 SDK, available in Xcode 4.1 through 4.6, is used
by
MEX and related capabilities. This SDK is no longer available in
Xcode
5, resulting in errors similar to the foll

Simulation Velocity of a harmonic oscillator system 
Your code can return a negative value as randn is a normally
distributed random number with standard deviation 1. In theory this
could return any number and there is ~15% chance it will be less than
1.
You are also correct than you should update x at each step. I would
take x as an input into getPos and xdot as an output. Then add another
step to update the position.

read input file Matlab 
Is this what you are looking for...?
I think you have to use %s %s as a format to text scan and not a float
because a vector cannot be converted to a float for example.
I changed this A = textscan(fid,'%s %s','Delimiter',' '); to include
%s %s.
Also, I think you want to concatenate along the first dimension rather
than the second.
I think you actually want to create a key/value pair of the inpu

m_line boundary for stereographic map 
I think the function is just made to find points on a map, and connect
them with a straight line (As you currently see happening).
A way to get what you want might be to work around this with a polygon
that consists of many points, for example:
bndry_lon=[linspace(0,125,100) 125 0 0 ];
bndry_lat=[linspace(86,86,100) 90 90 86 ];
If you believe the function is capable of producing the curved

Change data in intra frame of MPEG file in matlab 
I am assuming that by Intraframe you mean Iframes. There is no way
to determine whether a frame is an I, P or Bframe after it has been
decoded. One has to look at the raw encoded bitstream to do this. A
tool such as ffprobe can help you with this.
You can do this roundabout thing if you really want to:
Download ffmpeg tools. It has a function or utility called ffprobe. On
the system termina

How to find the index of dependent column in sparse matrix 
I don't know why you want discuss this in the sparse context, but
apart from simply checking each dependency you could do it
simultaneously. I suggest something like
%% create some data...
A = double(rand(3,3) > 0.5)
%% create linearDependencyMatrix with % important
% linearDependencyMatrix(i,j) == 1 % part
% iff

My simple simulink model runs too fast 
1) I had the same issues with some interactive simulations where the
CPU would make them run too fast for the user to interact. Using a
Simulink Real Time Execution Block brought the solution, despite it
gives heavy CPU load due to the solution it uses. With this, if you
define a 10sec simulation, that's what it will last. If you don't want
to pass through this burden, just lengthen your simulatio

Rotating labels and superscript in Matlab 
I recommend you to use format_tick instead of xticklabel_rotate, the
former allows you to format your labels as TeX objects and also has
positioning options.
Make the following changes in your code to get the desired output:
Change from:
% Rotate labels
xticklabel_rotate([],45,[],'Fontsize',fsizeMed,'interpreter','none')
to:
% Rotate labels
format_ticks(gca, XTL_prim, [], [], [], 45)
Add a

Could anyone help me to solve this code please? 
You have a problem with interp1 usage.
p = interp1(t,p,T)  this returns a vector
'p = interp1(t,p,method,'pp')  this returns a structure with
piecewise function.
Docs are here.
Also, you can use ppval to get values from piecewise function.
And the last note  there is a warning in Matlab r2014a:
Warning: INTERP1(...,'PP') will be removed in a future release. Use
GRIDDEDINTERPOLANT instead.
