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Upgrading from JPA hibernate 4-2-* to 4-3-5 exception
Try changing it to an implicit join instead: SELECT A FROM MAIL_INTERNAL_COPY A JOIN A.mail m WHERE m.id = 172 Also make sure there is no MailInternalCopyBean DB entry having a MailBean set as null (because you marked this association with nullable=false).

Categories : Hibernate

how to create and call stored procedures in hibernate?
I think this article could help: http://www.mkyong.com/hibernate/how-to-call-store-procedure-in-hibernate/

Categories : Hibernate

Why ? - Second level cache should be set to false for batch updates is this true
The second level cache keeps a reference to all objects which are used in the current transaction. Batch updates are mostly used to update many objects (> 10'000). That many objects need a lot of memory but for little gain: You probably don't need any of them again, soon (or rather, if you update a million objects, you don't really know which one of them you'll need next). So putting all these ob

Categories : Hibernate

Grails Unidirectional Many to One and Criteria
With Where queries and Detached criteria out of the question one option would be using sqlRestriction like so: Batch.withCriteria { sqlRestriction """ exists ( select * from record r join record_details rd on rd.record_id = r.id where r.batch_id = {alias}.id and r.type like ? and rd.xx like ?

Categories : Hibernate

How to use same session object across multiple dao methods in struts2+hibernate web-app?
Is my implementation right? This is off-topic here. BTW it seems fine. Is there any downside of this implementation? This implementation is called Open Session In View (OSIV) Pattern, often referred as Anti-Pattern. There are pros and cons using it (also read this). Is there a better way of implementing the same? Better is subjective, hence saying which is better than which oth

Categories : Hibernate

org.hibernate.type.SerializationException: could not deserialize java.io.EOFException at java.io.ObjectInputStream$PeekInputStream.readFully
I Divide&Conquered by simply cutting each relationship and retried. It turned out to be a wrong relationship type definition for Locale. I removed the wrongly declared @JoinColumn defintions and changed it to a m-to-1 relationship. @ManyToOne private Locale locale; Nothing more to do than that. I this helps another guy.

Categories : Hibernate

Hibernate Lazy Loading with complex object Graph
Use a Hibernate Detach Utility What you need is a 'Hibernate Detach Utility', like this one here: https://github.com/ocpsoft/socialpm/blob/master/gwt/src/main/java/com/ocpsoft/socialpm/gwt/server/util/HibernateDetachUtility.java This nulls out all uninitialized collections. Use the Session in View Pattern Or you could use the so-called 'Session in View' pattern. This keeps the Hibernate sessi

Categories : Hibernate

Hibernate - save some Entity in one transaction
probably u are not setting parentEntity in child setter,i.e.you need to set class A in class B, so when it save all hierarchy in single call ,it doesn't get parent entity in mapped By column, Class A{ @OneToMany(mappedBy = "parent" , Cascade = cascadeType.All) List<B> children; //children setter n getter } Class B{ @MAnyToOne private A parent; SetPArent(A a){ //like this y

Categories : Hibernate

not-null property references a null or transient value: in.dao.Teacher.address
When you are saving the Teacher entity it probably references address entity which hasn't been saved yet. You can fix it by first saving the address and the setting the saved Address instance to teacher before saving it, for example: Address mergedAddress = session.merge(address); teacher.setAddress(mergedAddress); session.merge(teacher); Or you can set Cascade to MERGE on your Address propert

Categories : Hibernate

How to make H2 return results faster for a big resultset?
Some explanation on the results you got: The WriterThread has a CPU time of 0, because it is waiting (sleeping) most of the time. The FileDisk.read could be reading from the database file, or reading from an large result set (in H2, large result sets are written to disk in most cases). So it's not really clear yet whether the problem is really that a temporary result set is created. To analyze pe

Categories : Hibernate

how to use fetch in Hibernate Query Language
The syntax is select a from A a left join fetch a.b left join fetch a.c where a.id = :id Relevant part of the documentation: A "fetch" join allows associations or collections of values to be initialized along with their parent objects using a single select. This is particularly useful in the case of a collection. It effectively overrides the outer join and lazy declarations of the mapping f

Categories : Hibernate

@SecondaryTable Mapping from primary table (compsite primary key) to secondary table (single primary key)
Normally in this situation I would have a OneToMany relationship in the Activity and Person pojo's. And in the PersonRole pojo you would have a ManyToOne relationship for each of Activity and Person, which lets you get at all the data you need without duplicating of data (personname). Add a OneToMany in the Person pojo. Set<PersonRole> personRoles = new HashSet<PersonRoles>(); @OneT

Categories : Hibernate

Why JPA named query timeout but when ran DBMS runs fine?
The error saying transaction timeout since as it looks a very long, nested and bad query which takes more time than the designated transaction life time. Note that JPQL is basically translated into SQL and so there is extra time used in this translation. You can increase the transaction life time from your application server console to 1 minute and try again

Categories : Hibernate

SQL Query in Entitymanger.createNativeQuery
You can use native SQL like that, and to map the results you can simply create a class (if you already don't have one) with fields that match the returned columns (the ones you specify in SELECT clause), and pass it in createNativeQuery call Query q = em.createNativeQuery("select * from dbo.TGEO_PARM_VALUE where PARM_DEF_UID= (select PARM_DEF_UID from dbo.TGEO_PARM_DEF where PARM_KEY_NM='VRSN_CHG

Categories : Hibernate

hibernate how to deal with divided to many tables
Based on your information you cannot use a ManyToMany since you want to keep additional information on the relation between a bus and a station. In this case you need to create a mapping entity like BusLineToStation with following properties: Busline (ManyToOne) Station (ManyToOne) stationOrder (Integer) id (optional) From BusLine and BusStation you can then just have a OneToMany to BustLineTo

Categories : Hibernate

For single database can i use multiple hibernate configuration file?
1) For a single project or a DB, multiple hibernate config files can be used. This and this makes it clear. 2) Multiple Session Factories can be created for a single Data source or a single DB. First define the DB details in the applicationContext-database.xml as: <bean id="dbName_dataSource" class="required_dataSource_Type" destroy-method="required_type"> <property name="driver

Categories : Hibernate

how to mapping Long to column datetime
Since on the database you use datetime you will need to use java.util.Date in your Java / Hibernate code. However, I believe this should not be too much of a problem since you can get the underlying timestamp anytime by calling getTime() DbHibernateObj obj = service.getMyObject(id); long timestamp = obj.getFirstExpressTime().getTime();

Categories : Hibernate

Spring Data - JPA Repository LIKE @Query for different type of entity fields
From exception trace it seems, issue is due to 'like' operation on your date field. You can use 'to_char(usr.createdOn,'ANY_DATE_TIME_FORMAT')' to convert the date to string in any date format and then use like for matching.

Categories : Hibernate

Grails Map causes exception Integer cannot be cast to String
At some point, the values in your map need to get mapped to a column in your database. That database column has to have a specific data type. My guess is that since Map<String, Object> is pretty ambiguous as far as what it contains, that GORM just made that column a varchar and so it's expecting everything to be a string. If you need to store ints as well as strings, you have two good opti

Categories : Hibernate

Criteria Query in Hibernate
Assuming Hibernate, here is an example: List cats = sess.createCriteria(Cat.class) .add( Restrictions.like("name", "Fritz%") ) .add( Restrictions.between("weight", minWeight, maxWeight) ) .list(); More details at following Criteria Queries Equivalent query for your case would be: List result = sess.createCriteria(Reportcategory.class) .add( Restrictions.eq("categoryId", new Integer(1)) ) .lis

Categories : Hibernate

Make foreign key as primary key in xml one to one mapping
Ok, could you please try this and tell me if it works? <class name="Person"> <id name="personId" column="personId"> <generator class="native"/> </id> <one-to-one name="address" cascade="all"/> </class> <class name="Address"> <id name="addressId" column="addressId"> <generator class

Categories : Hibernate

JPA + Hibernate, avoid drop table
As explained in this answer, the value create will create the schema, destroying previous data. Try with update instead if you want to preserve data.

Categories : Hibernate

Why hikaricp gives me Method not found: setUrl at startup?
The pgjdbc-ng PGDataSource does not have a setter for a url property. The URL is "composed" internally by pgjdbc-ng. You need to setup the DataSource using the individual properties: hibernate.hikari.dataSource.host=localhost hibernate.hikari.dataSource.port=5432 hibernate.hikari.dataSource.database=db

Categories : Hibernate

Which solution for Hibernate 2nd Level Cache
The second level cache is a relation-data cache and not a full-blown object caching solution. So it's just the basic entity properties and the foreign keys that get saved. As for entity associations, the *-To-One might be saved in different cache regions while the *-To-Many relationships require enabling the query cache too. I think the 2nd level cache is much more useful when your entities actu

Categories : Hibernate

How to select join column in hql
Where is your versionid in the code? I mean the declaration. There is locationId declared in "version" table. but no versionid. Check your query where you are saying `select v.id, l.locationId from Version v` In fact your error says "Could not resolve the property versionid ". Because you have no property versionid declared in the first place.

Categories : Hibernate

JPA Hibernate Persist any Enum (a Map key) in human readable format?
To store a Map where key is an enum, and get something human readable in db you could try: @Entity public class QuestionnaireDefinition{ ... @OneToMany(mappedBy = "questionnaireDefinition", fetch = FetchType.LAZY, cascade = CascadeType.ALL) @MapKeyEnumerated(EnumType.STRING) @MapKeyColumn(name = "language", insertable = false, updatable = false) private final Map<Language,

Categories : Hibernate

SELECT NOT EXIST in hibernate
I have managed to run it. Here is the code: BigInteger result = (BigInteger) localSession.createSQLQuery("SELECT NOT EXISTS("+ "SELECT delivery_request_id FROM delivery_request WHERE book_id= "+book.getBookId()+" AND status LIKE 'PENDING')"+ "AND"+ "(SELECT NOT EXISTS(SELECT return_request_id FROM return_request rr WHERE rr.book_id="+boo

Categories : Hibernate

JPA or Hibernate or Spring annotation to specify a query for a relationship?
You should be able to do this in Hibernate by using custom loader @Entity @NamedNativeQuery(name="customHomeworkLoader", query="select a.* from Homework a join Tutorial b on (a.tutorial_id = b.id) where b.student_id = ?", resultClass = Homework.class) public class Student { @OneToMany Collection<Tutorial> tutorials; @Loader(namedQuery = "customHomeworkLoader") @OneToMany Collection&l

Categories : Hibernate

Hibernate remove outOfMemory
Here the snippet which causes error : @Transactional(propagation = Propagation.REQUIRED, readOnly = false) public void remove(List<Configuration> listConfiguration){ for (Configuration configuration : listConfiguration) { configuration = findById(configuration); configurationDao.remove(configuration); } }

Categories : Hibernate

Difficult with a query and join
It was a querydsl problem because it generate a extra join cross to my query. So we resolved the issue by this changing JPAQuery query = new JPAQuery(entityManager).from(lot) .leftJoin( lot.regions ).fetch() .leftJoin( lot.cities).fetch() .where(lot.city_execution.region.id_region.eq(region_value_enter_by_user)) .distinct(); to JPAQuery

Categories : Hibernate

EntityManager is null when trying to find entity in DB
Your UsersFacade is not managed by the container - it is not a managed bean so there will be no dependency injections performed. You have either make it a managed bean or (suggested solution) inject EntityManager to your LoginBean insted of UserFacade and pass it to your facade via constructor.

Categories : Hibernate

Redirecting to a page displaying a specific object
I'm not completely following you; +1 for a very nice first question, though probably excessively verbose. You can add all the details you want, but you should always contract the real question (the expected result, the obtained result, the problem) in a "one-liner", or short sentence(s), separated by all the other bunch of details potentially useful for a more deep debugging of the problem. From

Categories : Hibernate

How do I tell JPA CriteriaBuilder to order by the only column of data returned?
Something like Expression selectedExpr = builder.substring(user.get(User_.userName); criteria.select(selectedExpr, userNamePrefix.length()).as(Integer.class)); Order orderExpr = builder.asc(selectedExpr); criteria.orderBy(orderExpr);

Categories : Hibernate

uploading image into database using prime faces andhibernate
You should convert byte array to java.sql.Blob. The example code show below. import java.sql.Blob; import javax.sql.rowset.serial.SerialBlob; ... byte[] imageData = .....; try { Blob blob = new SerialBlob(imageData); schoolStudent.setImage(blob); } catch (SQLException ex) { ... }

Categories : Hibernate

Hibernate restriction on a set
I'm not sure whether it is root of your problem. However you should add alias to your criteria such as: Criteria criteria = session.createCriteria(Book.class) .createAlias("authors", "authors")... Also categories should be aliased

Categories : Hibernate

hibernate 4 session connection remains open
So this sounds very much like a Connection leak in your application. Use c3p0 config params unreturnedConnectionTimeout and debugUnreturnedConnectionStackTraces to debug it. See here. (In your hibernate.cfg they'd be hibernate.c3p0.unreturnedConnectionTimeout and hibernate.c3p0.debugUnreturnedConnectionStackTraces.)

Categories : Hibernate

Hibernate Cache error
I have added the below mentioned jars to my hibernate project. Please let me know if I am missing out something in here. antlr cglib commons-annotations commons-collection commons-logging dom4j some hibernate jars log4j myaql-java-connector slf4j-api xalan xerces

Categories : Hibernate

Hibernate + HikariCP + EHCache session creation fails
You need to remove these lines: <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property> <property name="hibernate.connection.url">jdbc:mysql://localhost:3307/******?zeroDateTimeBehavior=convertToNull</property> <property name="hibernate.connection.username">****</property> <property name="hibernate.connection.password">****<

Categories : Hibernate

Issue with Inheritance JPA/Hibernate JOINED
With JOINED inheritance it's not easy to change the sub-class type while preserving the base-class entry, so instead of inheritance you can simply use composition. The Person can have a @OneToOne(mappedBy) association to Etudiant, where Etudiant has a @OneToOne association back to Person (FK back to Person's PK). The Etudiant can still use inheritance, so it can be Student, PhdStudent, Teacher,

Categories : Hibernate




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